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Introductory Nanotechnology
~ Basic Condensed Matter Physics ~
Atsufumi Hirohata
Department of Electronics
Quick Review over the Last Lecture
Waves :
Wave modes :
(
(
transverse wave
(
longitudinal wave )
Photon : (
h
), phonon : (
optical mode
)
)
(
)
acoustic mode )
Contents of Introductory Nanotechnology
First half of the course :
Basic condensed matter physics
1. Why solids are solid ?
2. What is the most common atom on the earth ?
3. How does an electron travel in a material ?
4. How does lattices vibrate thermally ?
5. What is a semi-conductor ?
6. How does an electron tunnel through a barrier ?
7. Why does a magnet attract / retract ?
8. What happens at interfaces ?
Second half of the course :
Introduction to nanotechnology (nano-fabrication / application)
How Does Lattices Vibrate Thermally ?
•
Specific heat
Einstein model
•
•
Debye model
Imagine You Are on a Beach in Summer …
When you walk on a beach ...
Comfortable in water !
Very hot on sand !
Water : difficult to be warmed up / cooled down.
Specific Heat Capacity
In order to compare :
Thermal energy required to increase temperature of a unit-volume material
(1 mole at constant volume)
Molecule
1-atom
2-atom
3-atom
Many-atom (>3)
Material
cV,mol [J/molK]
He
12.5
Ar
12.5
H2
20.4
CO
20.8
HCl
21.0
H2 S
26.9
SO2
32.3
CH4
27.0
C2H2
33.1
cV,mol increases with increasing numbers of atoms in a molecule.
increases with increasing numbers of degree of freedom.
Thermal Fluctuation in a Molecule
At finite temperature :
Atoms in a molecule vibrates (translation and rotation).
* http://www.wikipedia.org
Amplitude of Lattice Vibration
Amplitude increases with increasing temperature :
(r)
r
Higher vibration energy state
Thermal activation
Lower vibrtion energy state
Specific Heat 1 - Classical Model for Ideal Gas
Equal volume specific heat :
U
cV
T V
According to Dulong-Petit empirical law,
cV 6 [cal/molK] 25.1 [J/molK]
T
( RT)
In order to explain this law, L. Boltzmann introduced classical thermodynamics :
Average kinetic energy for a particle in a vacuum is written as follows in 3D
EK 3
kBT
2
For 1 mole (N0 : Avogadro constant),
EK,mol
3N 0kBT 3RT
2
2
where R = N0kB : gas constant, and EK, mol equals to internal energy of ideal gas.
* http://www.wikipedia.org
Specific Heat 1 - Classical Model for a Crystal Lattice
For a crystal lattice, each atom at a lattice point have potential energy of
EU, mol
3N 0kBT 3RT
2
2
Therefore, internal energy of 1 mol solid crystal is written as
Umol EK, mol EU, mol 3RT
By substituting R = 1.99 cal/molK,
Umol
cV, mol
3R 5.96 [cal/mol K]
T V
This agrees very well with Dulong-Petit empirical law.
However, about 1900,
J. Dewar found that specific heat approaches 0
at low temperature.
* http://www.wikipedia.org
Specific Heat 2 - Einstein Model 1
In a crystal lattice as a harmonic oscillator, energy is expressed as
En
h E
nh E
2
n 0,1,2,
Einstein assumed that is constant for all the same atoms in the oscillator.
Now, the numbers of the oscillators with energy of E0, E1, E2, ... are assumed
to be N0, N1, N2, ..., respectively, and these numbers to follow the MaxwellBoltzmann distribution.
En E0
nh E
Nn
exp
exp
N0
k
T
k
T
B
B
In order to calculate average energy <E> of an oscillator, probability for En is
Nn
N
n
n
En
n
N
1
En n h E
N n 2
n
n
nh E
nh E exp
kBT
nh E
exp
kBT
n
* http://www.wikipedia.org
Specific Heat 2 - Einstein Model 2
Substituting x = -hE / kBT, the second term in the right part becomes
h E
n expnx
n
h E
n
ex 2e2x
expnx h E
1 ex e2x
d
log 1 ex e2x
dx
h E
d
1
1
log
h
E x
dx
1 ex
e 1
Therefore, average energy of an oscillator is
1
1
E h E h E
2
exph E kBT 1
Energy of a phonon
En nh E
1
n
exph E kBT
1
Also, assuming,
Planck distribution
1
h
2 E
nh E h E n
By neglecting zero point energy,
n kBT h E
n exph E
high temperatureh E kBT
kBT low temperatureh E kBT
Specific Heat 2 - Einstein Model 3
Average energy of an oscillator can be modified as
E h E 2 n h E
E h E 2 kBT kBT
high temperatureh E kBT
Energy only depends on T (= classical model).
E h E 2 h Eexp-h E kBT
low temperatureh E kBT
For 1 mol 3D harmonic oscillator,
3
1
Umol 3N 0 E N 0h E 3N 0h E
2
exph E kBT 1
Thus, equal volume specific heat is
h E 2 exph E kBT
Umol
cV, mol
3R
T V
kBT exph E kBT 12
Since E depends on materials, both cV, mol and hE depends on materials.
Accordingly, characteristic temperature E for hE is introduced as
h E kBE
Einstein temperature
Specific Heat 2 - Einstein Model 4
With using Einstein temperature, equal volume heat is rewritten as
E 2 expE T
E
cV, mol 3R
3RfE
T exp T 12
T
E
f E x 2ex ex 1
2
fE (x) : Einstein function
For high temperature (T > E),
f E x 1
cV, mol 3R
Agrees with Dulong-Petit empirical law
For low temperature (T << E),
cV, molexpE T
With decreasing temperature,
Einstein model decrease
faster than measurement.
* N. W. Ashcroft and N. D. Mermin, Solid State Physics (Thomson Learning, London, 1976).
Specific Heat 2 - Einstein Model 5
In Einstein model, discrete energy levels are assumed :
1
E3 3 h E
2
1
E2 2 h E
2
1
E1 1 h E
2
1
E0
h E
2
n3
n2
n 1
n0
For low temperature (T << E), most of the atoms stay at the zero point energy
(E0).
With increasing temperature, very few atoms are excited to E1 as compared with
the theoretical prediction.
Departure from experiment at low temperature
Specific Heat 3 - Debye Model 1
Debye introduced quantum harmonic oscillators :
Phonon can be produced by lattice vibration and can fill in one energy state.
follows Planck distribution with energy of
E h
Numbers of particles occupying an energy level Ei, which is gi-fold degenerated
at angular frequency of i are calculated to be
ni gi n
gd
gi
exp i kBT 1 exp i kBT 1
is treated as a continuous function
Here, the density of states for a phonon is written as
gd
V
2
3
4 k 2dk
For longitudinal / transverse waves,
l vl k, t vt k
Vl 2 1
Vt 2 2
gl
, gt
2
3
2 vl
2 2 vt 3
* http://www.wikipedia.org
Specific Heat 3 - Debye Model 2
By using average and add both longitudinal and transverse waves :
V 2 1
2
2
g
C
3
2 2
vt 3
vl
V 1
2
C 2
2 v 3 v 3
l
t
For a N-atom 3D lattice, 3N modes are allowed :
CD 3
C d
3N
0
3
9N 2
g
0 D
3
D
D
g ()
C 2
2
D : Debye angular frequency
Therefore, Debye temperature is defined as
D
D
kB
0
D
Specific Heat 3 - Debye Model 3
Now, numbers of states can be rewritten as
1
9N 2
n
d
exp kBT 1 D3
By neglecting the zero point energy, total internal energy is
E n
U
D
0
1
gd
exp kBT 1
9N 2
exp kBT 1 D
3
d
Therefore, equal volume specific heat is calculated to be
U
cV, mol
T V
D
0
T 3
cV, mol 9R
D
2 exp kBT 9N 2
kB
d
2
3
k
T
B exp kBT 1 D
D T
0
x 4ex
e 1
x
2
dx
D
, D
, R NkB N 0kB
x
k
T
k
B
B
Specific Heat 3 - Debye Model 4
For high temperature (D << T),
T 3 1 D 3
cV, mol 9R 3R
D 3 T
x 4ex
e 1
x
2
x 4 1 x
2
x x 2 2
x4
2 x2
x
Agrees with Dulong-Petit empirical law
For low temperature (T << D),
3
3
12 R T
T
3
cV, mol
464.5 cal/mol K T
5 D
D
4
D T
0
x 4ex
e 1
x
2
dx
0
4 4
dx
2
x
15
e 1
x 4ex
Agrees with experiment