Thermodynamics and kinetics

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Transcript Thermodynamics and kinetics

Thermodynamics and kinetics

• • • • •

Thermodynamic laws Half-cell reactions Kinetics Acid-Base Equilibrium calculations

Speciation calculation from complexation constants

Provide review of concepts for applications to radiochemistry

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Thermodynamic terms

• • • •

Heat Capacity (C p )

Heat required to raise one gram of substance 1 °C Enthalpy (∆H) Energy of a system (heat content)

Internal energy, volume, pressure

Accounts for energy transferred to environment by expansion or heating ∆H = ∆H products - ∆H reactants Exothermic reactions, negative ∆H

Negative ∆H tend to be spontaneous

∆H products ∆H reactants

2 H + + CO 3 2 <--> CO 2 + H 2 O

-393.5 + (-285.8)-(-677.1+2(0)) = -2.2 kj/mol

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Thermodynamic terms

Endothermic

Reaction requires energy (at 25 °C) 2 HgO + 181.70 kj <--> 2 Hg + O 2 Enthalpy (∆H)

Energy of a system (heat content)

Internal energy, volume, pressure

Accounts for energy transferred to environment by expansion or heating

• •

∆H = ∆H products - ∆H reactants Exothermic reactions, negative ∆H

Negative ∆H tend to be spontaneous

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Entropy (∆S) and Gibbs Free Energy (∆G)

• • •

Randomness of a system

increase in ∆S tends to be spontaneous Enthalpy and Entropy can be used for evaluating the free energy of a system Gibbs Free Energy

∆G = ∆H -T∆S

∆G=-RTlnK

K is equilibrium constant

Activity at unity

Compound ∆G° (kJ/mol) at 298.15 K H 2 O OH (aq) H + (aq)

-237.129

-157.244

0 H 2 O



H + +OH What is the constant for the reaction?

Products-reactants At 298.15 K ∆G(rxn) = 0 + -157.244 - (-273.129) = 79.9 kJ/mol lnK= (79.9E3/(-8.314*298.15))=-32.2; K=1E-14, K w = [H + ][OH ]

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Thermodynamic Laws

• • •

1st law of thermodynamics

Energy is conserved in a system

Can be changed or transferred

Heat and work are energy transfer

∆E = q (heat absorbed) + w (work) 2nd law of thermodynamics

Reactions tend towards equilibrium

 

Increase in entropy of a system Spontaneous reaction for -∆G

∆G = 0, system at equilibrium 3rd law of thermodynamics

 

Entropies of pure crystalline solids are zero at 0 K Defines absolute zero

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• • • • • •

Half-cell potentials

Cell reaction for

Zn and Fe 3+/2+ at 1.0 M

Write as reduction potentials

Fe 3+ + e <--> Fe 2+

°=0.77 V

Zn 2+ + 2e <-->Zn

°=-0.76 V Reduction potential for Fe 3+ is larger

Fe 3+ is reduced, Zn is oxidized in reaction Overall balanced equation

2Fe 3+ +Zn <--> 2Fe 2+ + Zn 2+

°=0.77+0.76=1.53 V Use standard reduction potential Application of Gibbs Free Energy If work is done by a system

∆G = -

°nF (n= e ) Find ∆G for Zn/Cu cell at 1.0 M

Cu 2+ + Zn <--> Cu + Zn 2+

°=1.10 V

2 moles of electrons (n=2)

∆G =-2(96487C/mole e )(1.10V)

∆G = -212 kJ/mol

    2. 30RT nF log [C] c [D] d [A] a [B] b 2-6

• •

Kinetics and Equilibrium

Kinetics and equilibrium important concepts in examining and describing chemistry

Identify factors which determine rates of reactions

   

Temperature, pressure, reactants, mixing Describe how to control reactions Explain why reactions fail to go to completion Identify conditions which prevail at equilibrium General factors effecting kinetics

Nature of reactants

   

Effective concentrations Temperature Presence of catalysts Number of steps

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• •

Rate Law

Concentration of reactant or product per unit time Effect of initial concentration on rate can be examined

rate = k[A] x [B] y

 

rate order = x + y knowledge of order can help control reaction

rate must be experimentally determined Rate=k[A] n ; A=conc. at time t, A o =initial conc., X=product conc.

Order rate equation 0 [A 0 ]-[A]=kt, [X]=kt k mole/L sec 1 1/sec 2 3 1 [A] ln[A 0 ]-ln[A]=kt, ln[A 0 ]-ln([A o ]-[X])=kt 1 [A]

1 [A o ]

kt 1 [A o ]

[X]

1 [A o ]

kt 2

1 [A o ] 2

kt 2 1 ([A o ]

[X]) 2

1 [A o ] 2

kt 2 L/mole sec L 2 /mole 2

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sec

Acid-Base Equilibria

• • •

Brønsted Theory of Acids and Bases

Acid

Substance which donates a proton

Base

Accepts proton from another substance

• •

NH 3 + HCl <--> NH 4 + H 2 O + HCl <--> H 3 O + NH 3 + H 2 O <--> NH 4 + + Cl + Cl + OH Remainder of acid is base Complete reaction is proton exchange between sets Extent of exchange based on strength Water can act as solvent and reactant

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Dissociation Constants

Equilibrium expression for the behavior of acid HA + H 2 O <--> A + H 3 O + Water concentration is constant

K  [A  ][H 3 O  ] [HA][H 2 O] •

pK a =-logK a

K a  K[H 2 O] 

Can also be measured for base

[A  ][H 3 O  ] [HA]

Constants are characteristic of the particular acid or base Acid Acetic Carbonic Phosphoric Oxalic Formula HC 2 H 3 O 2 H 2 CO 3 HCO 3 H 3 PO 4 H 2 PO 4 HPO 4 2 H 2 C 2 O 4 HC 2 O 4 K a 1.8E-5 3.5E-7 5E-11 7.5E-3 6.2E-8 4.8E-13 5.9E-2 6.4E-5

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• •

Buffer Solutions

• •

Buffers can be made over a large pH range Can be useful in controlling reactions and separations

Buffer range

Effective range of buffer

Determined by pK a HA + H 2 O <--> A -

K a  [A  ][H 3 O  ] [HA]

of acid or pK b + H 3 O -

[H 3 O  ]  K a [HA] [A  ]

of base Write as pH

pH  pK a  log [HA] [A  ]

The best buffer is when [HA]=[A ]

largest buffer range for the conditions

pH = pK a - log1 For a buffer the range is determined by [HA]/[A ]

  

[HA]/[A ] from 0.1 to 10 Buffer pH range = pK a ± 1 Higher buffer concentration increase durability

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Hydrolysis Constants

• • • • •

Reaction of water with metal ion

Common reaction

Environmentally important

Strength dependent upon metal ion oxidation state 2 H 2 O <--> H 3 O +

water: + OH Water concentration remains constant, so for

K w = [H 3 O + ][OH ]= 1E-14 at 25°C Metal ions can form hydroxide complexes with water M z+ + H 2 O <--> MOH z-1+ + H + Constants are listed for many metal ion with different hydroxide amounts

Database at: http://www.escholarship.org/uc/item/9427347g

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• • •

Equilibrium

Le Châtelier’s Principle At equilibrium, no further change as long as external conditions are constant Change in external conditions can change equilibrium

A stressed system at equilibrium will shift to reduce stress

concentration, pressure, temperature N 2

+ 3 H 2 <--> 2 NH 3 + 22 kcal What is the shift due to

Increased temperature?

Increased N 2 ?

Reduction of reactor vessel volume?

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• •

Equilibrium Constants

For a reaction

aA + bB <--> cC + dD At equilibrium the ratio of the product to reactants is a constant

The constant can change with conditions

By convention, constants are expressed as products over reactants

K  [C] c [D] d [A] a [B] b •

Conditions under which the constant is measured should be listed

Temperature, ionic strength

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Activities

• • • •

Strictly speaking, activities, not concentrations should be used

K   C [C] c  D [D] d  A [A] a  B [B] b

At low concentration, activities are assumed to be 1 The constant can be evaluated at a number of ionic strengths and the overall activities fit to equations Debye-Hückel (Physik Z., 24, 185 (1923))

 log  A  1  0.5085Z

a 2 0.3281R

A  

Z µ = molal ionic strength R A A = charge of species A = hydrated ionic radius in Å (from 3 to 11) First estimation of activity

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Activities

Debye-Hückel term can be written as:

• D  0.5107

1  1.5

 

Specific ion interaction theory

Uses and extends Debye-Hückel

long range Debye-Hückel

• 

ij

Short range ion interaction term = specific ion interaction term

log  i

Pitzer

log ß(  )  logß(0)   Z i 2 D   ij     Z 2 D   ij 

Binary (3) and Ternary (2) interaction parameters

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6.6

6.5

6.4

6.3

Experimental Data Cm-Humate shows change in stability constant with ionic strength Ion Specific Interaction Theory used

6.2

6.1

6.0

0.0

K +

0.5

1.0

1.5

sqrt Im

2.0

2.5

3.0

Ca 2+ Al 3+ Fe(CN) 6 4-

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Constants

Constants can be listed by different names

Equilibrium constants (K)

Reactions involving bond breaking

  *

2 HY <--> H 2 + 2Y Stability constants (ß), Formation constants (K)

Metal-ligand complexation

* *

Pu 4+ + CO 3 2 <--> PuCO 3 2+ Ligand is written in deprotonated form Conditional Constants

An experimental condition is written into equation

*

Pu 4+ + H 2 CO 3 <--> PuCO 3 2+ +2H +

Constant can vary with concentration, pH

Must look at equation!

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Realistic Case

Consider uranium in an aquifer

Species to consider include

 

free metal ion: UO 2 2+

hydroxides: (UO 2 ) x (OH) y

carbonates: UO 2 CO 3

humates: UO 2 HA(II), UO 2 OHHA(I) Need to get stability constants for all species

 

UO 2 2+ + CO 3 2 <--> UO 2 CO 3 Know or find conditions

Total uranium, total carbonate, pH, total humic concentration

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Stability constants for selected uranium species at 0.1 M ionic strength Species logß UO 2 OH + UO 2 (OH) 2 UO 2 (OH) 3 UO 2 (OH) 4 2 (UO 2 ) 2 OH 3+ (UO 2 ) 2 (OH) 2+ UO 2 CO 3 UO 2 (CO 3 ) 2 2 UO 2 (CO 3 ) 3 4 UO 2 HA(II) UO 2 (OH)HA(I) 8.5

17.3

22.6

23.1

11.0

22.0

8.87

16.07

21.60

6.16

14.7±0.5

Other species may need to be considered. If total uranium concentration is low enough, binary or tertiary species can be excluded.

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• • •

Equations

Write concentrations in terms of species

  

[UO 2 ] tot = UO [CO 3 2 ] free =f(pH) [OH ] = f(pH) 2free +U-carb+U-hydroxide+U-humate

[HA] tot = UO 2 HA + UO 2 OHHA+ HA free Write the species in terms of metal, ligands, and constants

 

[(UO 2 ) x A a B b ] = 10 -(xpUO2+apA+bpB-log(UO2)xAaBb) pX = -log[X] free

[(UO 2 ) 2 (OH) 2 2+ ]=10 -(2pUO2+2pOH-22.0) Set up equations and solve for known terms

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U speciation with different CO

2

partial pressure

0% CO 2 1% CO 2

1.0

1.0

UO 2 HA(II) UO 2 (OH) UO 2 2+ 3 UO 2 HA(II) UO 2 OHHA(I)

0.8

UO 2 2+ UO 2 (CO 3 ) 3 4 UO 2 OHHA(I)

0.8

UO 2 (OH) 2

0.6

0.6

0.4

0.4

UO 2 (CO 3 ) 2 2-

0.2

0.2

0.0

2.0

4.0

pH

6.0

1.0

8.0

10.0

0.0

2.0

UO 2 2+ UO 2 HA(II) UO 2 OHHA(I) UO 2 (CO 3 ) 3 4-

0.8

4.0

pH

6.0

8.0

10.0

0.6

0.4

0.2

0.0

UO 2 (CO 3 ) 2 2-

2-22 2.0

4.0

pH

6.0

8.0

10.0

10% CO 2

Comparison of measured and calculated uranyl organic colloid

1.0

0.8

0.6

0.4

0.2

0.0

100% 10% 1% 0% 0.035%

2.0

4.0

pH

6.0

8.0

10.0

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Excel spreadsheets CHESS Program

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Energy terms

Constants can be used to evaluate energetic of reaction

From Nernst equation

∆G=-RTlnK

76 74 72 70 

∆G=∆H-T∆S

-RTlnK = ∆H-T∆S

68 66 

RlnK= - ∆H/T + ∆S

64 0.003

*

Plot RlnK vs 1/T

56

Temperature effect on Np-Humate stability

48 40

T emp (°C)

32 24 0.0031

0.0032

1/T (K)

0.0033

²H = -22.2 ± 2.8 kJ/mol ²G 298 =-21.7 kJ/mol ²S=1.2±1.4 J/molK 0.0034

16 0.0035

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Solubility Products

Equilibrium involving a solid phase

AgCl(s) <--> Ag + + Cl -

K  [Cl  ][Ag  ] [AgCl ]  

AgCl concentration is constant

Solid activity and concentration is treated as constant

By convention, reaction goes from solid to ionic phase in solution Can use K sp solution for calculating concentrations in

K sp  K[AgCl]  [Cl  ][Ag  ] 2-26

Solubility calculations

K sp of UO 2 = 10 -52 . What is the expected U 4+ concentration at pH 6. Generalize equation for any pH

Solubility reaction:

UO 2 + 2 H 2 O



U(OH) 4



U 4+ + 4 OH -

 

K sp = [U 4+ [U 4+ ]= K sp ][OH /[OH ] 4 ] 4

pOH + pH =14

  

At pH 6, pOH = 8, [OH ]=10 -8 [U 4+ ]= 10 -52 /[10 -8 ] 4 = 10 -52 /10 -32 = 10 -20 M For any pH

[U 4+ ]= 10 -52 /[10 -(14-pH)*4 ]

Log [U 4+ ]= -52+((14-pH)*4)

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Limitations of K

sp

• • • •

Solid phase formation limited by concentration

below ≈1E-5/mL no visible precipitate forms

colloids formation of supersaturated solutions

slow kinetics Competitive reactions may lower free ion concentration Large excess of ligand may form soluble species

AgCl(s) + Cl <--> AgCl 2 (aq)

K sp really best for slightly soluble salts 2-28

Overview

• • • •

Understand heats of reactions

 

Enthalpy, entropy, Gibbs free energy Reaction data from constituents

Understand half-cell reactions

Nernst Equation

Kinetics

Influence of reaction conditions

Equilibrium and constants

Use to develop a speciation spreadsheet

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Questions

• • • • • • •

What is the difference between 1 st kinetics?

and 2 nd order What can impact reaction rates?

How can a compound act as a base and acid? Provide an example.

What does the dissociation constant of an acid provide?

Provide the speciation of acetic acid at pH 3.5, 4.5, and 5.5.

What are the species from carbonic acid at pH 4.0, 6.0, and 8.0?

Set up the equations to describe the speciation of uranyl, the uranyl monocarbonate, and the uranyl dicarbonate.

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Pop Quiz

Show the relationship between Gibbs free energy, enthalpy, and entropy

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