AP Calculus Chapter 1, Section 4

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Transcript AP Calculus Chapter 1, Section 4

AP Calculus
Chapter 1, Section 4
Continuity and One-Sided Limits
2013 - 2014
What is a continuous graph?
Continuity at a Point and on an Open Interval
𝑓(𝑐) is not defined
lim 𝑓(π‘₯)
π‘₯→𝑐
does not exist
lim 𝑓(π‘₯) β‰  𝑓(𝑐)
π‘₯→𝑐
Definition of Continuity
β€’ Continuity at a point: a function f is continuous at c if the
following three conditions are met.
1. 𝑓(𝑐) is defined.
2. lim 𝑓(π‘₯) exists.
π‘₯→𝑐
3. lim 𝑓(π‘₯) = 𝑓 𝑐 .
π‘₯→𝑐
β€’ Continuity on an Open Interval: A function is continuous
on an open interval (a, b) if it is continuous as each point in
the interval. A function that is continuous on the entire
real line (βˆ’βˆž, ∞) is everywhere continuous.
Types of Discontinuity
Removable Discontinuity
Nonremovable discontinuity
Discuss the continuity of each function
1
𝑓 π‘₯ =
π‘₯
π‘₯2 βˆ’ 1
𝑔 π‘₯ =
π‘₯βˆ’1
π‘₯ + 1,
β„Ž π‘₯ = 2
π‘₯ + 1,
𝑦 = sin π‘₯
π‘₯≀0
π‘₯>0
One-sided limits & continuity on a
closed interval
β€’ One-sided limits come in handy when
evaluating limits on closed intervals.
– Limit from the right:
lim+ 𝑓 π‘₯ = 𝐿
π‘₯→𝑐
– Limit from the left:
limβˆ’ 𝑓 π‘₯ = 𝐿
π‘₯→𝑐
Find the limit of 𝑓 π‘₯ = 4 βˆ’ π‘₯ 2 as x
approaches -2 from the right.
Definition of Continuity on a Closed
Interval
β€’ A function f is continuous on the closed interval
[a, b] if it is continuous on the open interval (a, b)
and
lim+ 𝑓 π‘₯ = 𝑓(π‘Ž)
π‘₯β†’π‘Ž
and
limβˆ’ 𝑓 π‘₯ = 𝑓(𝑏)
π‘₯→𝑏
β€’ The function f is continuous from the right at a
and continuous from the left at b.
Discuss the continuity of 𝑓 π‘₯ = 1 βˆ’ π‘₯ 2
Properties of Continuity
β€’ If b is a real number and f and g are
continuous at x=c, then the following
functions are also continuous at c.
1. Scalar Multiple: bf
2. Sum and Difference: f ± g
3. Product: fg
4. Quotient:
𝑓
,
𝑔
if g(c) β‰  0
The following types of functions are
continuous at every point in their domains.
1. Polynomial functions:
𝑝 π‘₯ = π‘Žπ‘› π‘₯ 2 + π‘Žπ‘›βˆ’1 π‘₯ π‘›βˆ’1 + β‹― + π‘Ž1 π‘₯ + π‘Ž0
2. Rational Functions: π‘Ÿ π‘₯ =
𝑝(π‘₯)
,
π‘ž(π‘₯)
𝑛
3. Radical Functions: 𝑓 π‘₯ = π‘₯
4. Trigonometric Functions:
sin π‘₯, cos π‘₯, tan π‘₯ , sec π‘₯ , csc π‘₯
π‘ž(π‘₯) β‰  0
By using these properties, you can see that each
of the following functions are continuous at
every element of its domain.
β€’ 𝑓 π‘₯ = π‘₯ + sin π‘₯
β€’ 𝑓 π‘₯ = 3 tan π‘₯
β€’ 𝑓 π‘₯ =
π‘₯ 2 +1
cos π‘₯
Continuity of a Composite Function
β€’ If g is continuous at c and f is continuous at
g(c), then the composite function given by
(𝑓○ 𝑔) π‘₯ = 𝑓(𝑔 π‘₯ ) is continuous at c.
Describe the interval(s) on which each
function is continuous.
𝑓 π‘₯ = tan π‘₯
1
g x = sin π‘₯ ,
0,
π‘₯β‰ 0
π‘₯=0
Intermediate Value Theorem
β€’ If a function is continuous on a closed interval
[a, b], and if k is between f(a) and f(b), then
there must exist a value c in [a, b] such that
𝑓 𝑐 = π‘˜.
Height
Age
Applying IVT
β€’ Use the Intermediate Value Theorem to show that the
polynomial function
𝑓 π‘₯ = π‘₯ 3 + 2π‘₯ βˆ’ 1
has a zero in the interval [0, 1].
Homework
β€’ Pg. 78 – 81: 1 – 61 every other odd, 71, 75, 95