Strength of materials - Yogyakarta State University
Download
Report
Transcript Strength of materials - Yogyakarta State University
Statically Determinate and Indeterminate System of Bars
STRENGTH OF MATERIALS
Statically Determinate
System of Bars
Investigation to trusses and to structures
which consist of bars and rigid body
Assumption : the elongations are small as
compared with the length of the bars
Applying the equilibrium conditions to the
undeformed system
Statically Determinate
System of Bars
B
All bars have the axial rigidity EA
2
1
C
A
l
F
Statically Determinate
System of Bars
B
All bars have the axial rigidity EA
2
S2
1
A
l
C
F
S1
C
F
Statically Determinate
System of Bars
Calculating S1 and S2 in the bars, as follow :
𝑆2 sin 𝛼 − 𝐹 = 0
𝑆1 + 𝑆2 cos 𝛼 = 0
𝐹
𝑆1 = −
tan 𝛼
𝑆2 =
𝐹
sin 𝛼
Calculating elongation li of the bars
𝑆1 𝑙1
𝐹𝑙
𝛿1 =
=
𝐸𝐴
𝐴𝐸 tan 𝛼
𝛿2 =
𝑆2 𝑙2
𝐹𝑙
=
𝐴𝐸
𝐴𝐸 sin 𝛼 cos 𝛼
Statically Determinate
System of Bars
Statically Determinate
System of Bars
𝐹𝑙
𝑢 = ∆𝑙𝑖 =
𝐴𝐸 tan 𝛼
∆𝑙2
𝑢
𝐹𝑙 1 + 𝑐𝑜𝑠 3 𝛼
𝑣=
+
=
sin 𝛼 tan 𝛼
𝐴𝐸 𝑠𝑖𝑛2 𝛼 cos 𝛼
STATICALLY DETERMINATE SYSTEM OF BARS
ANY QUESTIONS ?
Statically Indeterminate
System of Bars
A system of bars is statically indeterminate of
degree n if the number of unknowns exceeds
the number of the equilibrium conditions by
n.
In order to determine the forces in the bars of
such a system, n compatibility conditions are
needed in addition to the equilibrium
conditions.
Solving this system of equations yields the
unknown forces in the bars.
Statically Indeterminate
System of Bars
Statically Indeterminate
System of Bars
From figure (b) , we can get :
−𝑆1 sin 𝛼 + 𝑆3 sin 𝛼 = 0 → 𝑆1 = 𝑆3
(a)
𝐹 − 𝑆2
𝑆1 cos 𝛼 + 𝑆2 + 𝑆3 cos 𝛼 − 𝐹 = 0 → 𝑆1 = 𝑆3 =
2 cos 𝛼
The elongations of the bars are given by :
∆𝑙1 = ∆𝑙3 =
𝑆1 𝑙1
𝐸𝐴1
∆𝑙2 =
𝑆2 𝑙2
𝐸𝐴2
(b)
Statically Indeterminate
System of Bars
∆𝑙1 = ∆𝑙2 cos 𝛼
(c)
With (a) and (b), and l1= l / cos , we can get :
𝐹 − 𝑆2 𝑙
𝑆2 𝑙
𝐹
=
cos
𝛼
→
𝑆
=
2
𝐸𝐴
2𝐸𝐴1 𝑐𝑜𝑠 2 𝛼 𝐸𝐴2
1 + 2 𝐸𝐴1 𝑐𝑜𝑠 3 𝛼
2
𝐸𝐴1
2
𝐸𝐴2 cos 𝛼
𝑆1 = 𝑆3 =
𝐹
𝐸𝐴1
1 + 2 𝐸𝐴 cos3 𝛼
2
The vertical displacement :
𝐹𝑙
𝑆2 𝑙
𝐸𝐴2
𝑣 = ∆𝑙2 =
=
𝐸𝐴2 1 + 2 𝐸𝐴1 cos 3𝛼
𝐸𝐴2
STATICALLY INDETERMINATE SYSTEM OF BARS
ANY QUESTIONS?
Statically Determinate
System of Bars
The truss is subjected to a force F.
Given: E = 2· 102 GPa, F = 20kN.
Determine the cross-sectional area of
the three members so that
the stresses do not exceed the
allowable stress σallow = 150 MPa
and the displacement of support B is
smaller than 0.5 ‰ of the
length of bar 3.
Statically Indeterminate
System of Bars
To assemble the truss in Fig. (a), the free end of bar 3 (length l − δ, δ<<l) has to be
connected with pin C.
a) Determine the necessary force F acting at pin C (Fig. b).
b) Calculate the forces in the bars after the truss has been assembled
and force F has been removed.