Electrical Energy & Current

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Transcript Electrical Energy & Current

Electrical Energy & Current

Introduction to Electric PE, Electric Potential, and Potential Difference  Intro to Electric Potential

Electrical Potential Energy      PE associated with a charge due to its position in an electric field.

Analogous to PE

g PE g

of an object results from its position in a gravitational field (mgh) Is a component of mechanical energy ME = KE + PE

grav

+ PE

elastic

+ PE

electric

Electric PE in a

Uniform

Field Electric

 A uniform field is one that has the same direction at all points, such as between two parallel plates  Remember: electric field lines are always directed from away from positive and toward negative

Electric Potential Energy         Recall that Δ

PE = -W

When charge q is released at point a, electric force will move the charge to b, i.e.

The electric field does work on the charge q

W = Fd

Since F = qE (E = F/q)

W = qEd PE b -PE a = -qEd

Δ

PE = -qEd

PE as a charge moves in a uniform electric field

Movement of charge

Along E Opposite E

+ charge

Loses PE (where + “wants” to go) Gains PE

- charge

Gains PE Loses PE (where – “wants” to go)

  Similarity of

PE electric

and

PE g PE g

= mgh m is mass

  g is gravitational field h is distance above a reference point

PE elect

= -qEd

q is charge  E is electric field strength    d is distance from reference point The (-) sign indicates the PE

elect

for +q will increase for –q and decrease Using dimensional analysis, what is the unit of PE

elect

?

Potential Difference  Electric potential is the ratio of PE

elect

to charge q

V

PE elect q

  Represents the work needed to move a charge against electric forces from a reference point to some other point in an electric field The unit of electric potential is what?

Potential difference   The change in electric potential The difference in electrical potential between two points 

V

 

PE elect q

 Is the work that must be done against electric forces to move a charge from one point to another divided by the charge

Potential Difference  Unit is the volt (V) 

V

 

PE elect q

1 V  J C

Potential Difference in a Uniform Electric Field    Varies in a uniform field with displacement from a reference point Where d is displacement parallel to the field Use this equation to determine potential difference between two points in a field 

V

 

Ed

Potential Difference at a Point Near a Charge    One point is near the charge The other point is at infinity Use this equation to find the potential difference at a single point 

V

k C q r

Electric potential due to multiple charges     Electric potentials are scalar quantities (whew!) So….

Total potential at some point in a field is the simple sum of the potentials due to each charge Keep track of signs!

Sample Problem    As a charge moves x

a

= 4.0 cm to x

b

= 8.0 cm in a uniform field of 350 N/C, it loses 4.5 x 10-18 J of potential energy.

What is the magnitude of the charge?

What is the potential difference between the two points a and b?

    17.2 Capacitance Capacitors are devices that store electrical PE Often constructed of parallel metal plates When connected to a battery, the plates become charged When fully charged, ∆V cap = ∆V bat

 Capacitance Ability of a conductor to store energy in the form of separated charges 

C

Q V

Unit of capacitance is the farad, F

1 Farad

1 Coulomb Volt

Capacitance of a Parallel Plate Capacitor in a Vacuum    A is the area of the plates E 0 is permittivity constant for a vacuum = 8.85 x 10 -12 C2/Nm2

C

  0

A d

Dielectric Materials   Insulating material placed between the plates of a capacitor Increases the ability of a capacitor to carry a charge

Discharging a Capacitor    Capacitors are devices that store charge When discharge, they release charge Computer keyboards are an example of capacitors in action

    Capacitance of a Sphere R is radius Because the earth has a large radius, it has a very large capacitance i.e., the earth can accept or supply a very large amount of charge without changing its electrical potential

C sphere

 This is why the earth is “ground,” (reference point for measuring potential differences)

Q

V

R k C

Energy and Capacitors PE Stored in a Charged Capacitor

PE

 1 2

Q

V PE

 1 2

C

  2

PE

Q

2 2

C

Current and Resistance   Current is the rate of movement of charge Rate of movement of electrons through a cross-sectional area

I

 

Q

t

1ampere  1 coulomb second

Sample Problem  If current flowing through a light bulb is 0.835 A, how long does it take for 1.67 C of charge to pass through the filament of the bulb?

 2.00 seconds

Conventional Direction of Current      Depending upon the circumstances, either positive, negative, or both can move.

Particles that move are called

charge carriers

By convention, direction of current is defined as the direction a positive charge moves or would move if it could.

In metals, only electrons can move.

Good conductors permit charge carriers to move easily  Electrons in metals  Ions in solution (electrolytes)

Conventional Direction of Current

Drift Velocity http://www.bbc.co.uk/staticarchive/4e6786539008e5012ff9c723c4255ae6fc6c1b9f.gif

     Recall the structure of metals Valence electrons move about randomly due to their thermal energy Their net movement is zero But if an electric field is established in the wire, there is a net movement of electrons against the electric field (toward +) Drift velocity animation

Drift Velocity Consider motion of an electron through a wire      It is the electric field that exerts force and thereby sets charge carriers in motion E propagates very rapidly (near speed of light) Charge carriers move more slowly, in an erratic path, Called drift velocity

v

Slow: e.g. in a copper wire carrying a 10.0 A current,

drift

= 2.46 x 10 -4 m/s

Resistance to Current    Opposition to electric current Unit of electrical resistance is the ohm ( Ω ) More commonly known as Ohm’s law 

V

R

 

V I

1 ohm  1 volt amp

IR

Ohmic and Non-ohmic Materials     Materials which follow ohm’s law are ohmic materials Resistance is constant over a wide range of potential differences (linear) Non-ohmic materials have variable resistance (non linear Diodes are constructed of non-ohmic materials

Other Factors Affecting Resistance

17.4 Electric Power    A potential difference (∆V) is necessary to cause current (I) Batteries supply chemical energy (PE

chem

) which can be converted into electical PE Generators convert mechanical energy into electrical PE   E.g. hydroelectric power plants Coal or natural gas powr plants  Nuclear power plants

Direct and Alternating Current  DC current flows in one direction only  Electrons move toward the (+) terminal  Conventional current directed from (+) to (-)  AC current  Terminals of source of ∆V constantly switch  Causing constant reversal of current, e.g. 60 Hz  Rapid switching causes e s to

vibrate

a net motion.

rather than have

DC and AC   DC   constant uni-directional AC   not constant bi-directional

Energy Transfer      In a DC circuit Electrons leave the battery with high PE Lose PE as flow through the circuit Regain PE when returned to battery (battery supplies PE through electrochemical reactions)

Electric Power

P

V

W

t

  

PE q

PE

t

 

PE P P

  

q

V

t I

V

Since

q

t q

V

I

  The rate of conversion of electrical energy SI unit is the watt (W)

Other Formulas for Power Beginning with

P

I

V

Using Ohm' s Law...

P

P

I

2

R

  2

R

Kilowatt-hours     How utility companies measure energy consumed Is the energy delivered in one hour a constant rate of one kW 1kWh=3.6 x 10 6 J What is the cost to light a 100 W light bulb for 1 full day if the electric utility rate is $0.0600 per kWh?

100 W  24 h  2400 Wh  2.4

kWh 2.4

kWh  $0.0600

kWh  $0.144

Transmission Lines     Transit at high voltage and low current to minimize energy lost during transmission Compare the equations….

P = I

2

R P = I∆V