Transcript Document

Electromagnetic Induction Faraday’s Law Lenz’s Law

CHAPTER 25

Electromagnetic Induction

Induced Current in a Circuit

Motional electromotive force (emf)

e 

vlB

Magnetic Flux

Lenz’s Law

Checking Understanding

A magnetic field goes through a loop of wire, as below. If the magnitude of the magnetic field is increasing, what can we say about the current in the loop?

A.

B. The loop has a counterclockwise current.

C.

The loop has a clockwise current.

The loop has no current.

Answer

A magnetic field goes through a loop of wire, as below. If the magnitude of the magnetic field is increasing, what can we say about the current in the loop? A.

B. The loop has a counterclockwise current.

C.

The loop has a clockwise current.

The loop has no current.

Checking Understanding

A magnetic field goes through a loop of wire, as below. If the magnitude of the magnetic field is decreasing, what can we say about the current in the loop? A.

B. The loop has a counterclockwise current.

C.

The loop has a clockwise current.

The loop has no current.

Answer

A magnetic field goes through a loop of wire, as below. If the magnitude of the magnetic field is decreasing, what can we say about the current in the loop?

A.

B. The loop has a counterclockwise current.

C.

The loop has a clockwise current.

The loop has no current.

Checking Understanding

A magnetic field goes through a loop of wire, as below. If the magnitude of the magnetic field is constant, what can we say about the current in the loop? A.

B. The loop has a counterclockwise current.

C.

The loop has a clockwise current.

The loop has no current.

Answer

A magnetic field goes through a loop of wire, as below. If the magnitude of the magnetic field is constant, what can we say about the current in the loop? A.

B. The loop has a counterclockwise current.

C.

The loop has a clockwise current.

The loop has no current.

Checking Understanding

A battery, a loop of wire, and a switch make a circuit below. A second loop of wire sits directly below the first. Just before the switch is closed, what can we say about the current in the lower loop? A.

B. The loop has a counterclockwise current.

C.

The loop has a clockwise current.

The loop has no current.

Answer

A battery, a loop of wire, and a switch make a circuit below. A second loop of wire sits directly below the first. Just before the switch is closed, what can we say about the current in the lower loop? A.

B. The loop has a counterclockwise current.

C.

The loop has a clockwise current.

The loop has no current.

Checking Understanding

A battery, a loop of wire, and a switch make a circuit below. A second loop of wire sits directly below the first. Immediately after the switch is closed, what can we say about the current in the lower loop? A.

B. The loop has a counterclockwise current.

C.

The loop has a clockwise current.

The loop has no current.

Answer

A battery, a loop of wire, and a switch make a circuit below. A second loop of wire sits directly below the first. Immediately after the switch is closed, what can we say about the current in the lower loop? A.

B. The loop has a counterclockwise current.

C.

The loop has a clockwise current.

The loop has no current.

Induced Fields

A changing magnetic field induces an electric field.

A changing electric field induces a magnetic field too.

Checking Understanding

A plane electromagnetic wave has electric and magnetic fields at all points in the plane as noted below. With the fields oriented as shown, the wave is moving A.

B. out of the plane of the paper.

C.

E.

into the plane of the paper.

to the left.

D. to the right.

toward the top of the paper.

Answer

A plane electromagnetic wave has electric and magnetic fields at all points in the plane as noted below. With the fields oriented as shown, the wave is moving A.

B. out of the plane of the paper.

C.

E.

into the plane of the paper.

to the left.

D. to the right.

toward the top of the paper.

Summary

Additional Questions

A bar magnet sits inside a coil of wire that is connected to a meter. The bar magnet is at rest in the coil. What can we say about the current in the meter?

A.

The current goes from right to left.

B. The current goes from left to right.

C.

There is no current in the meter.

Answer

A bar magnet sits inside a coil of wire that is connected to a meter. The bar magnet is at rest in the coil. What can we say about the current in the meter?

A.

The current goes from right to left.

B. The current goes from left to right.

C.

There is no current in the meter.

Additional Questions

A bar magnet sits inside a coil of wire that is connected to a meter. The bar magnet is pulled out of the coil. What can we say about the current in the meter?

A.

The current goes from right to left.

B. The current goes from left to right.

C.

There is no current in the meter.

Answer

A bar magnet sits inside a coil of wire that is connected to a meter. The bar magnet is pulled out of the coil. What can we say about the current in the meter?

A.

The current goes from right to left.

B. The current goes from left to right.

C.

There is no current in the meter.

Additional Questions

A bar magnet sits inside a coil of wire that is connected to a meter. The bar magnet is completely out of the coil and at rest. What can we say about the current in the meter?

A.

The current goes from right to left.

B. The current goes from left to right.

C.

There is no current in the meter.

Answer

A bar magnet sits inside a coil of wire that is connected to a meter. The bar magnet is completely out of the coil and at rest. What can we say about the current in the meter?

A.

The current goes from right to left.

B. The current goes from left to right.

C.

There is no current in the meter.

Additional Questions

A bar magnet sits inside a coil of wire that is connected to a meter. The bar magnet is reinserted into the coil. What can we say about the current in the meter?

A. The current goes from right to left.

B. The current goes from left to right.

C. There is no current in the meter.

Answer

A bar magnet sits inside a coil of wire that is connected to a meter. The bar magnet is reinserted into the coil. What can we say about the current in the meter?

A. The current goes from right to left.

B. The current goes from left to right.

C. There is no current in the meter.

Transformers

Checking Understanding

If the primary coil of wire on a transformer is kept the same and the number of turns of wire on the secondary is increased, how will this affect the voltage observed at the secondary?

A.

B. The voltage will stay the same.

C.

The voltage will increase.

The voltage will decrease.

Answer

If the primary coil of wire on a transformer is kept the same and the number of turns of wire on the secondary is increased, how will this affect the voltage observed at the secondary?

A.

B. The voltage will stay the same.

C.

The voltage will increase.

The voltage will decrease.

Two-Phase Power to Your Home

Root-Mean-Square Current and Voltage

If we define

I

rms 

I

R 2 and

V

rms 

V

R 2 then we can write and

P

R   

I

R 2   2

R

 (

I

rms ) 2

R

The expressions for AC power are identical to those used for DC currents if rms currents and voltages are used.

Example Problem

The following devices are plugged into outlets on the same 120 V circuit in a house. This circuit is protected with a 15-A circuit breaker.

Device

Computer Heater Lamp Stereo

Power

250 W 900 W 100 W 120 W Is there too much current in the circuit—that is, does the circuit breaker blow?

Example Problem

The following devices are plugged into outlets on the same 120 V circuit in a house. This circuit is protected with a 15-A circuit breaker.

Device

Computer Heater Lamp

Power

250 W 900 W 100 W Stereo 120 W Is there too much current in the circuit—that is, does the circuit breaker blow?

Note that the V, I, and P values are all root-mean square (rms), so DC formulas apply.

I = P/V; I computer = 250/120 = 2.08 amps: I heater = 900/120 = 7.50 amps: I lamp = 100/120 = 0.83 amp: I stereo = 120/120 = 1.00 amp: Total current used is 11.41 amps. Circuit does not blow.

Physiological Effects and Electrical Safety

Electrical Safety

I

 

V R

eq  

V R

boots  480 V 