Transcript Document
Design Example: Inductor
Design Specs
L=100 mH
IDC = 5 A
DI = 0.75 A p-p
Bmax = 0.25 T = 0.25 x 10-6 wb/mm2
Jmax = 6.0A/mm2
fs = 100kHz
kw = 0.5
4
ˆ
10
5.375 5.005
LII rms
4
4
Ap
3590mm
0.359cm
kw Bmax J max 0.5 0.25x10-6 6.0
Catalog Link
Acore
F2
4
H2
4
11.3
4
2
5.52 97.44 mm 2
Ae 93.9 mm2
C F
2
AW 2 D
5.5
18.0
11.3
36.85
mm
2
Ap 3900
Aw
41.5 mm2
Ae
93.9
Ap Acore AW 97.4436.85 3950 mm4
LIˆ
5.375 x 104
N
22 Turns
6
Bmax Acore 0.25x 10 97.44
Acond
I rms 5.0
0.83 mm2
J max 6.0
N m0 Acore
lg
L
2
This would be 18 gauge wire, which is
pretty stiff. The author suggests 5 strands
of 25 gauge (0.162 mm2)
22 4 x 1010 97.44
2
10
4
0.59 mm
Design Example: Transformer
Design Specs
v1 = v2 = v3 = 30 v
IRMS = 2.5 A
Bmax = 0.25 T = 0.25 x 10-6 wb/mm2
Jmax = 5.0A/mm2
fs = 100kHz
kw = 0.5
kc = 0.5
Ap
kc Vy I rms , y
y
kw f s Bmax J max
1800 mm4 0.18 cm4
Acore
F2
4
H2
63.9 mm 2
4
CF
2
AW 2 D
29.2
mm
2
kc
0.5
10 Turns
N1 N2 N3 V
30
-6
5
63.9 0.25 x 10 10
Acore Bmax f s
Acond
I rms 2.5
0.5 mm2
J max 5.0
This would be 20 gauge wire. The author
suggests 3 strands of 25 gauge (0.162 mm2)
Design Example: Transformer
Design Specs
Primary : 28 v, Secondary A: 5 v @ 6 A, Secondary B: 12 v @ 2.75 A
Primary current: Ip = 6(5/28)+2.75(12/28) = 2.25A
Bmax = 0.25 T = 0.25 x 10-6 wb/mm2
Jmax = 6.0A/mm2
fs = 50kHz
kw = 0.6
kc = 0.5
Ap
kc Vy I rms , y
y
kw f s Bmax J max
E Core:
0.5 28 2.25 5 6 12 2.75
0.6 5 x 104 0.25 x 106 6
1400 mm 4 0.14 cm 4
Acore Ae 45.5 mm
2
AW
Ap
Ae
1500
33 mm2
45.5
kc
0.5
280.88 25 Turns
N p Vp
28
-6
4
45.5 0.25 x 10 5 x10
Acore Bmax f s
N A 4.4 5 Turns
N B 10.5 11 Turns
Wire Cross Section:
Acond
Check Fill Factor with actual turns
and Wire sizes:
I
rms
J max
2.25
Apri
0.375 mm 2 21 Gauge
6.0
17 Gauge
AA 1.0 mm 2
AB 0.458 mm 2
20 Gauge
kw
25.410 51.04 11 0.518
0.64
33