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Design Example: Inductor Design Specs L=100 mH IDC = 5 A DI = 0.75 A p-p Bmax = 0.25 T = 0.25 x 10-6 wb/mm2 Jmax = 6.0A/mm2 fs = 100kHz kw = 0.5 4 ˆ 10 5.375 5.005 LII rms 4 4 Ap 3590mm 0.359cm kw Bmax J max 0.5 0.25x10-6 6.0 Catalog Link Acore F2 4 H2 4 11.3 4 2 5.52 97.44 mm 2 Ae 93.9 mm2 C F 2 AW 2 D 5.5 18.0 11.3 36.85 mm 2 Ap 3900 Aw 41.5 mm2 Ae 93.9 Ap Acore AW 97.4436.85 3950 mm4 LIˆ 5.375 x 104 N 22 Turns 6 Bmax Acore 0.25x 10 97.44 Acond I rms 5.0 0.83 mm2 J max 6.0 N m0 Acore lg L 2 This would be 18 gauge wire, which is pretty stiff. The author suggests 5 strands of 25 gauge (0.162 mm2) 22 4 x 1010 97.44 2 10 4 0.59 mm Design Example: Transformer Design Specs v1 = v2 = v3 = 30 v IRMS = 2.5 A Bmax = 0.25 T = 0.25 x 10-6 wb/mm2 Jmax = 5.0A/mm2 fs = 100kHz kw = 0.5 kc = 0.5 Ap kc Vy I rms , y y kw f s Bmax J max 1800 mm4 0.18 cm4 Acore F2 4 H2 63.9 mm 2 4 CF 2 AW 2 D 29.2 mm 2 kc 0.5 10 Turns N1 N2 N3 V 30 -6 5 63.9 0.25 x 10 10 Acore Bmax f s Acond I rms 2.5 0.5 mm2 J max 5.0 This would be 20 gauge wire. The author suggests 3 strands of 25 gauge (0.162 mm2) Design Example: Transformer Design Specs Primary : 28 v, Secondary A: 5 v @ 6 A, Secondary B: 12 v @ 2.75 A Primary current: Ip = 6(5/28)+2.75(12/28) = 2.25A Bmax = 0.25 T = 0.25 x 10-6 wb/mm2 Jmax = 6.0A/mm2 fs = 50kHz kw = 0.6 kc = 0.5 Ap kc Vy I rms , y y kw f s Bmax J max E Core: 0.5 28 2.25 5 6 12 2.75 0.6 5 x 104 0.25 x 106 6 1400 mm 4 0.14 cm 4 Acore Ae 45.5 mm 2 AW Ap Ae 1500 33 mm2 45.5 kc 0.5 280.88 25 Turns N p Vp 28 -6 4 45.5 0.25 x 10 5 x10 Acore Bmax f s N A 4.4 5 Turns N B 10.5 11 Turns Wire Cross Section: Acond Check Fill Factor with actual turns and Wire sizes: I rms J max 2.25 Apri 0.375 mm 2 21 Gauge 6.0 17 Gauge AA 1.0 mm 2 AB 0.458 mm 2 20 Gauge kw 25.410 51.04 11 0.518 0.64 33