Transcript Born-Haber Cycles

Born-Haber Cycles
Born-Haber Cycle for formation of sodium chloride:
Na+ (g) + Cl (g) + e-
H4 = -349 kJ
H3 = +496 kJ
Na+ (g) + Cl- (g)
Na(g) + Cl (g)
H2 = +122 kJ
Na(g) + 1/2 Cl2 (g)
H5 = -787 kJ
H1 = +107 kJ
Na(s) + 1/2 Cl2 (g)
START
Hf = -411 kJ
NaCl (s)
END
Born-Haber Cycle for formation of MgF2
Mg+2 (g) + 2 F (g) + 2e-
H4 = +1421 kJ
H5 = 2 x -328 kJ
Mg+ (g) + 2F (g) + e-
Mg+2 (g) + 2F- (g)
H3 = +738 kJ
Mg (g) + 2 F (g)
H2 = +159 kJ
Mg(g) + F2 (g)
H6 = -2962 kJ
H1 = +146 kJ
Mg(s) + F2 (g)
START
Hf = -1124 kJ
MgF2 (s)
END
Born-Haber Cycle for formation of LiF
Li+ (g) + F (g) + e-
H4 = -328 kJ
H3 = +520 kJ
Li+ (g) + F- (g)
Li(g) + F (g)
H2 = +159 kJ
Li(g) + 1/2 F2 (g)
H5 = -1047 kJ
H1 = +159 kJ
Li(s) + 1/2 F2 (g)
START
Hf = ???
LiF (s)
END
Born-Haber Cycle for formation of LiCl
Li+ (g) + Cl (g) + e-
H4 =
H3 =
Li+ (g) + Cl- (g)
Li(g) + Cl (g)
H2 =
Li(g) + 1/2 Cl2 (g)
H5 = ???
H1 =
Li(s) + 1/2 Cl2 (g)
START
Hf = -409 kJ
LiCl (s)
END
Born-Haber Cycle for formation of sodium fluoride:
Na+ (g) + F (g) + e-
H4 =
H3 =
kJ
kJ
Na+ (g) + F- (g)
Na(g) + F (g)
H2 =
kJ
Na(g) + 1/2 F2 (g)
H5 =
H1 =
kJ
Na(s) + 1/2 F2 (g)
START
Hf =
kJ
NaF (s)
END
kJ