AE 301 Aerodynamics I
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Transcript AE 301 Aerodynamics I
Vortex Lattice Method
•
The lifting line method was very useful to understand
the basic concepts of span loading and the elliptical
distribution.
•
However, lifting line theory is limited to high aspect
ratio, unswept wings – and even then is approximate.
•
To do analysis for more generalized geometries we need
to go to a numerical approach like that of the Vortex
Lattice Method.
•
To keep our numerical method simple lets assume a
planar wing – I.e. the entire wing lies on the z=0 plane.
•
We can still model twist and/or camber, but we will
apply the slope boundary condition at z=0 just like we
did in Thin Airfoil Theory.
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Vortex Lattice Method [2]
•
Our approach is to panel the wing planform and place a
horseshoe vortex at the c/4 of each panel.
•
In addition, we place a flow tangency boundary
condition point at the mid-span and 3c/4 point of each
panel.
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For 6 spanwise and 2 chordwise panels, the result is:
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Surface Paneling
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How to space the panels?
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The most obvious is to use even spacing in both
directions.
•
However, on most wings, the greatest change in span
loading occurs at the wing tips .
•
To better resolve these variations, a spacing which
clusters panels near the tips can be used.
•
Thus, if we have nj spanwise panels and ni chordwise
panels, the sides of the panels may be given by:
nj j
b
y j 1,nj 1 cos
2 nj
•
i 1
xi 1,ni 1 xle c
ni
Note: there is one more side then there are panels!
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Surface Paneling [2]
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Note that we really are not interested in the panels
themselves – just the vortex corner points and the flow
tangency points.
•
To find the vortex corner points directly use:
nj j
b
yc (i, j ) cos
n
2
j
xc (i, j ) xle, j
i .75
c j
ni
i 1, ni 1
j 1, nj 1
•
This gives one extra set of corner points behind the
wing, but is useful for the next step.
•
Now, average the corner points to find the tangency
point in the center:
x(i, j) 14 xc (i, j) xc (i 1, j) xc (i 1, j 1) xc (i, j 1)
y(i, j ) 14 yc (i, j ) yc (i 1, j) yc (i 1, j 1) yc (i, j 1)
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Surface Paneling [3]
•
•
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For each span station, the local chord and leading edge
values can be found from the planform:
2 yc ( j,1)
2 yc ( j,1)
xle, j
tan le
ct cr
c j cr
b
b
Where the wing parameters can be determined from:
b
2c
ct cr
c
cr
AR
1
cr ct
tan le tan c / 4
2b
All this set takes a bit of work – don’t be surprised if
half your program is just setting up the geometry.
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Induced Downwash
•
We have already developed an equation for the
downwash due to a horseshoe vortex based upon the
Biot-Savart Law.
•
However, the equation, shown below, is only good for
when the bound vortex is perpindicular to the trailing
ones.
cos 1 cos 2
w
4d
1 cos 1
4l1
2
cos 2 1
4l2
2
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l2
d
l1
1
2
z
y
x
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Induced Downwash [2]
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For the more general case of a skewed vortex
arrangement, the following equation applies:
( xk , yk )
2
1
cos 1 cos 2
w
y2 yb yk
4 d
( xb , yb ) d 3
1
1 cos 0
y1
y1 yk ya
1
1
cos 3 1
0
y2
( xa , ya )
• From this relation, we can determine the downwash
induced at any flow tangency point due to any panel
horseshoe vortex.
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Induced Downwash [3]
•
To aid in evaluating the angles used in the previous
equation, it is helpful to set our x-y axis at one corner
point – and then rotate it to align with the bound
vortex.
( xk , yk )
( xb , yb )
2
2
l xb xa yb ya
y y
xb xa
l
atan
x
y
y
a
b
x
xk xk xa cos yk ya sin
( xa , ya )
yk xk xa sin yk ya cos
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Induced Downwash [4]
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In terms of the coordinates of this rotated system, the
distance to the point and the angles are then:
d xk
xk
1 atan
yk
xk
2 atan
y k l
0
2
1
3 2
•
2
( xk , yk )
2
( xb , yb )
y
d
3
1
0
x
x
( xa , ya )
Now we are ready to set up our solution method.
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Solution Method
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Our problem is that we have a total of nk unknown
vortex strengths to find, one for each panel.
nk ni nj
•
When programming, it will be easiest to loop over all
the chordwise and spanwise panels using the counter:
k j nji 1
•
The velocity induced at each flow tangency point, k,
due to all the panel vortices is:
nk
wk kk wk ,kk
kk 1
•
Where, from our earlier relation:
1 1
1
1
cos 1 cos 2 1 cos 0 cos 3 1
wk ,kk
4 d
y1
y2
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Solution Method [2]
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At the same time, for flow tangency, the downwash
velocity must equal:
dz
wk V
•
Where, for a simple untwisted, uncambered wing:
dz
•
dx
dx
sin
From this, we see that our matrix solution formulation is
going to be:
[wk ,kk ]kk / V sin
•
•
Once this equation is solved for the individual vortex
strengths, the lift and drag must then be computed.
The lift is easy - just sum the
L
V
individual lift contributions:
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nk
y
k 1
k
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k
Solution Method [3]
•
•
Or, in terms of the lift coefficient:
2 nk
k yk
CL
SV k 1
The drag coefficient is found by from the induced
downwash velocity due to the trailing vortices:
2
CD
SV2
wt k ,kk
•
nk
k yk wtk ,kk kk
k 1
kk 1
nk
1 1
1
1 cos0 cos3 1
4 y1
y2
A little computation could be saved if the above wake
downwash term was saved from when it was computed
as part of the earlier downwash term.
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Solution Refinements
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The preceding analysis method will give good results for
a wide range of problems.
•
Wing twist and camber can easily be added by including
the appropriate surface slope at each tangency point.
•
To model winglets or wings with extreme dihedral
angles, the method must be reformulated in 3-D.
•
One advantage of doing this is the ability to model
ground effect via a mirror wing below the surface.
•
To find surface pressure distributions for boundary layer
calculations, thickness must also be modeled.
•
This is usually done by having both upper and lower
surface panels.
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