Transcript Prepared by - cpprashanths Chemistry

DISTINCTIONS BETWEEN SOME PAIRS OF ORGANIC COMPOUNDS
(CHEMICAL TEST)
Prepared by
C P Prashanth
KV Ganeshkhind Pune
C2H5Br + KOH (aq) → C2H5OH + KCl
KCl + AgNO3 → AgBr + KNO3
Yellow ppt
CH3—CH(Cl)—CH3 + aqKOH → CH3—CH(OH)—CH3 + NaOI → CHI3
Isopropyl chloride
i
CH3CH2CH2C1 + aq KOH → CH3CH2CH2OH + NaOI →Does not give
iodoform test.
CH3CH2OH +I2/NaOH →CH3-CHO
3C6H5OH + FeCl3
C6H5N2Cl +
→
(C6H50)3 Fe + 3HC1
→
C6H5-N=N-
3C6H5OH + FeCl3
→
(C6H50)3 Fe + 3HC1
C6H5N2Cl +
→
(iii)
+ Br2
→
C6H5-N=N-
•
1-Propanol (primary alcohol)does not produce turbidity at room temperature with
Lucas reagent.
•
CH3CH2CH2OH +
•
2-Methyl-2-propanol(tertiary alcohol) reacts with Lucas reagent (anhyd ZnCl2 +
HCl) giving turbidity immediately.
•
•
(CH3)3C-OH + anhyd ZnCl2 + HCl → (CH3)3C-Cl
Turbidity immediately
anhyd ZnCl2 + HCl →
No turbidity at room
CH3—CH(CH3)—OH + 4I2 + 6NaOH → CHI3 + CH3COONa + 5NaI + 5H20
CH3CH(OH)CH2CH3 + I2 + NaOH → CHI3
CH3CH2CH2CH2OH + I2 + NaOH → No yellow ppt.
3C6H5OH + FeCl3
→
(C6H50)3 Fe + 3HC1
Violet
Primary amine can be tested by carbylamine test
Primary amine can be tested by carbylamine test
C6H5-NH2 +
+ NaOH →
C6H5-
→
C6H5SO2N(CH2-CH3)2
•
Thanks
•
C P Prashanth