Transcript Normal Stress (1.1-1.5)
Beam Deflection
(9.1-9.5)
MAE 314 – Solid Mechanics Yun Jing Beam Deflection
1
Introduction
Up to now, we have been primarily calculating normal and shear stresses.
In Chapter 9, we will learn how to formulate the deflection curve (also known as the elastic curve ) of a beam.
Beam Deflection 2
Differential Equation of Deflection
d
ds d
ds
1 Recall from Ch. 4 that 1/ρ is the curvature of the beam.
y
θ ds dx dy
dy dx
tan
dx
cos
ds dy
sin
ds
Slope of the deflection curve Beam Deflection 3
Assumptions
Assumption 1: θ is small.
1.
ds
dx
d
ds
1
d
2.
dy
tan
d
dx dx dx
d
2
y
dx
2 1
d
2
y dx
2 Assumption 2: Beam is linearly elastic.
1
M EI
Thus, the differential equation for the deflection curve is:
d
2
y
dx
2
M EI
Beam Deflection 4
Diff. Equations for M, V, and w
Recall from Ch. 5:
dV dx
w dM
V dx
So we can write:
EI d
2
y dx
2
M EI d
3
y dx
3
V EI d
4
y dx
4
w
Deflection curve can be found by integrating Bending moment equation ( 2 constants of integration) Shear-force equation ( 3 constants of integration) Load equation ( 4 constants of integration) Chosen method depends on which is more convenient.
Beam Deflection 5
Boundary Conditions
Sometimes a single equation is sufficient for the entire length of the beam, sometimes it must be divided into sections.
Since we integrate twice there will be two each section .
constants of integration for These can be solved using boundary conditions .
Deflections and slopes at supports Known moment and shear conditions
V B M B
0 0
M A
0 Beam Deflection
M B
0 6
Boundary Conditions
Continuity conditions: Section AC: y AC (x) Displacement continuity
y AC
(
C
)
y CB
(
C
) Slope continuity
dy AC
(
C
)
AC
(
C
)
dx
Symmetry conditions:
dy CB dx
(
C
)
CB
(
C
) Section CB: y CB (x)
dy dx
0 Beam Deflection 7
Example Problem
For the beam and loading shown, (a) express the magnitude and location of the maximum deflection in terms of w 0 , L, E, and I, (b) Calculate the value of the maximum deflection, assuming that beam AB is a W18 x 50 rolled shape and that w 0 = 4.5 kips/ft, L = 18 ft, and E = 29 x 10 6 psi.
Beam Deflection 8
Statically Indeterminate Beams
x=0, y=0 x=0, θ =0
When there are more reactions than can be solved using statics, the beam is indeterminate.
Take advantage of boundary conditions to solve indeterminate problems.
x=L, y=0
Problem: Number of reactions: 3 (M A , A y , B y ) Number of equations: 2 (Σ M = 0, Σ F y = 0) One too many reactions!
Additionally, if we solve for the deflection curve, we will have two constants of integration, which adds two more unknowns!
Solution: Boundary conditions Beam Deflection 9
Statically Indeterminate Beams
x=0, y=0 x=0, θ =0 x=L, y=0 x=0, θ=0
Problem: Number of reactions: 4 (M A , A y , M B , B y ) Number of equations: 2 (Σ M = 0, Σ F y = 0) + 2 constants of integration Solution: Boundary conditions Beam Deflection 10
Example Problem
For the beam and loading shown, determine the reaction at the roller support.
Beam Deflection 11
Beam Deflection: Method of Superposition
(9.7-9.8)
MAE 314 – Solid Mechanics Yun Jing Beam Deflection: Method of Superposition
12
Method of Superposition
Deflection and slope of a beam produced by multiple loads acting simultaneously can be found by superposing the deflections produced by the same loads acting separately.
Reference Appendix D (Beam Deflections and Slopes) Method of superposition can be applied to statically determinate and statically indeterminate beams.
Beam Deflection: Method of Superposition 13
Superposition
Consider sample problem 9.9 in text.
Find reactions at A and C.
Method 1: Choose M C redundant.
and R C as Method 2: Choose M C and M A as redundant.
Beam Deflection: Method of Superposition 14
Example Problem
For the beam and loading shown, determine (a) the deflection at C, (b) the slope at A Beam Deflection: Method of Superposition 15
Example Problem
For the beam and loading shown, determine (a) the deflection at C, and (b) the slope at end A.
Beam Deflection: Method of Superposition 16
Example Problem
For the beam shown, determine the reaction at B.
Beam Deflection: Method of Superposition 17