Transcript Document
Mohammad Golshani (Joint work with Sy David Friedman) Institute for Research in Fundamental Sciences (IPM) Tehran β Iran 60 th Birthday of Sy David Friedman
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
(1) Supercompact Radin forcing
(Foreman β Woodin): Starting from a supercompact cardinal π and infinitely many inaccessibles above it, we can construct a generic extension π β β π in which: ο± Cardinals are preserved, ο± π remains inaccessible, ο± βπ < π , 2 π > π + and in fact 2 π is weakly inaccessible.
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
(2) Radin forcing with interleaved collapses
(Cummings): Starting from a (π + 3) a generic extension π β β strong cardinal β π in which: π we can construct ο± π remains inaccessible, ο± βπ < π , 2 π 2 π = π + = π ++ ππ π ππ π π π’ππππ π ππ ππππππππ ππ π ππ π πππππ‘ ππππππππ Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
(3) Extender based Radin forcing
(Merimovich): Let π > 1 . Starting from a (π + π + 1) there exists a generic extension π β β π β strong cardinal π , in which: ο± π remains inaccessible, ο± βπ < π , 2 π = π +π Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
ο
Question:
Is it possible to kill GCH everywhere by a cofinality preserving forcing over a model of GCH? If so, can we have a fixed finite gap in the resulting model; meaning that
2
π
= π
+π for some finite
π > 1
for all
π
?
ο
Question:
Can we have a pair
(π
1
, π
2
)
of models of ZFC with the same cardinals and cofinalities such that (or even
π π
1 2
β¨ πΊπΆπ» β¨ βπ, 2
π and
π
2
β¨ βπ, 2 = π
+π )?
π
> π
+ Introduction Question A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
π Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem
Introduction Questions A Natural Idea Merimovich Construction Properties the Forcing Notion β Must Have Solution of the Problem Open Problem