Transcript Slide 1

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4
Fixed Rate
Mortgage Loans
©2008 The McGraw-Hill Companies,
All Rights Reserved
McGraw-Hill/Irwin
Components of the Mortgage
Interest Rate
• Real Rate of Interest
 Time Preference for Consumption
• Compensation to delay a purchase
 Production Opportunities in the Economy
• Competition for funds when there are other
investment opportunities
• Inflation Expectation
 Retain purchasing power
4-2
Copyright ©2008 by The McGraw-Hill Companies, Inc. All Rights Reserved
Components of the Mortgage
Interest Rate
• Default Risk
• Interest Rate Risk
 Anticipated Inflation and Unanticipated
Inflation
•
•
•
•
Prepayment Risk
Liquidity Risk
Legislative Risk
Option-adjusted spread
4-3
Copyright ©2008 by The McGraw-Hill Companies, Inc. All Rights Reserved
Components of the Mortgage
Interest Rate
it  r1  p1  f1
r = Real Rate
f1 = Inflation Rate
p1 = Risk Premiums/spread
4-4
Copyright ©2008 by The McGraw-Hill Companies, Inc. All Rights Reserved
Three Relationships for Fixedincome Securities
• Applicable to all fixed-income securities
 Interest payment at time t = loan balance at
time t-1 X period interest rate
 Total payment = interest payment + principal
(amortization) payment
 Principal payment at time t = Principal at time
t-1 minus payment toward principal at time t
• Different debt security has different
requirement for principal payment
4-5
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Computing a Loan Balance
• Three methods
 “Rolling” principal balance period by period
• Convenient if principal payment is constant
 Compute the present value of the remaining
payments
• More convenient if the payments are constant
 Compute the future value of the amortized
loan amount, given initial loan value
• Convenient if total payment is constant
4-6
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Mortgage Payment Patterns
• Interest-only Mortgage (IO)
 Monthly payment constant
 Total principal stays constant as well
• Constant Amortization Mortgage (CAM)
 Loan Amortization Remains the Same
 Monthly Payment Changes
• Constant Payment Mortgage (CPM)
 Loan Amortization Changes
 Monthly Payment Remains the Same
4-7
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Development of Mortgage
Payment Patterns I
1.Short-term interest-only mortgage
with large down payment requirement
• Interests paid based on constant
principal amount
• No intermediate amortization
4-8
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Development of Mortgage
Payment Patterns I
Example 1: you are interested in a
$75K house. The bank is willing to
lend you at 12% 5-year interest only
loan if you can put 50% down. What
is the monthly payment and mortgage
balance at the end of 5th year?
4-9
Copyright ©2008 by The McGraw-Hill Companies, Inc. All Rights Reserved
Development of Mortgage
Payment Patterns II
2. Constant amortization mortgage (CAM)
 Constant amortization amount
Amort = total loan amount / number of months
 Interest computed on the loan balance at the
end of previous month
Int(t) = OLB (t -1) * (mortgage rate / 12)
 Total pmt = constant amortization amount
+ monthly interest pmt
 OLB(t) = OLB(t-1) – amort(t)
Note: total payment will decrease over time
4-10
Copyright ©2008 by The McGraw-Hill Companies, Inc. All Rights Reserved
Development of Mortgage
Payment Patterns II
Example 2: if you only need to put down 20%
for the $75K property to qualify for a 30year CAM, at 12% annual interest rate,
Q: what is mortgage balance by the end of 5th
year?
Q: What is your 61st payment?
Q: How much of your 61st payment goes to
principal?
4-11
Copyright ©2008 by The McGraw-Hill Companies, Inc. All Rights Reserved
Development of Mortgage
Payment Patterns III
3. Constant payment mortgage (CPM)
 Constant total monthly payment
• Can be calculated using annuity PV formula
 Interest computed based on loan balance
at the end of previous month
int(t) = OLB (t -1) * (mortgage rate / 12)
 Amount of amortization can be backed out
by taking difference b/w total payment and
its interest component
amort(t) = pmt(t) – int(t)
4-12
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Development of Mortgage
Payment Patterns III
3. Constant payment mortgage (CPM)
 Remaining balance can be calculated by
deducting previous balance by payment
toward principal in the current period
(backward looking)
• Can also be calculated by discounting
remaining payments at the mortgage interest
rate
• Or follow a PV/PMT/FV calculation
4-13
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Development of Mortgage
Payment Patterns III
Example 3.
1. What is the monthly payment for a 30-year $60K
CPM at 12%?
2. What is the loan balance by the end of 5th year?
3. How much does your 61st payment will go towards
principal payment?
4. Over the life of the mortgage, what is the total
amount of interest paid?
5. If inflation is 6%, what is the real value of the 60th
payment today?
6. How much interest will you be paying in the 6th
year?
4-14
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Other Loan Patterns
• Partially Amortizing
 Balloon Mortgage
• Negative Amortization
 Graduated Payment Mortgage (GPM)
• Reverse Annuity Mortgages
4-15
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Development of Mortgage
Payment Patterns IV
4. Graduated payment mortgage (GPM)
 Mortgage payments are lower in the
initial years of the loan
 GPM payments are gradually increased
at predetermined rates for initial years,
and then stay constant until maturity
4-16
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GPM Example
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Loan amount
Maturity
Interest rate (yield)
Graduation time
Graduation rate
$60,000
30 years
12%
5 years
7.5%
• Q: What is the initial payment?
• Q: What is the balance after 5 years?
4-17
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Reverse Annuity Mortgage
• Residential property value $500,000
• Loan amount to be disbursed in
monthly installments
$250,000
• Term 10 years
120 months
• Interest Rate
10%
• Q: How much payment will the
homeowner receive?
4-18
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Reverse Annuity
Mortgage Example Continued
• Calculator solution:
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FV=-250,000
i=10%/ 12
PMT= ?
n=120
Solve for payment $1220.44
4-19
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Effective Interest Cost
• Fees and points are part of loan
financing charges
 Should be taken into account in
comparing loan cost or true interest
costs
• Regulation - Truth in Lending Act
 What is the borrowing cost, called
Annual Percentage Rate (APR, in %) if
the loan is paid off at maturity?
4-20
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Effective Interest Cost Example 1:
APR
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•
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•
•
Contractual loan amount
$ 60,000
Less organization fee (3%)
$ 1,800
Net cash disbursed by lender $ 58,200
Interest rate= 12%
Term 30 years
4-21
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Effective Interest Cost Examples 1:
APR Continued
• Calculator solution
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n=360
PMT= -617.17
PV= 58,200
FV= 0
i=1.034324 (12.41% annualized)
4-22
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Effective Interest Cost Example 2:
Early Termination
• Contractual loan amount
$ 60,000
• Less organization fee(3%)
$ 1,800
• Net cash disbursed by lender $ 58,200
• Interest rate= 12%
• Term 30 years
• Loan paid off in 5 years
Q: What is the true effective cost to the
borrower/effective yield to the lender?
4-23
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Effective Interest Cost Example 2:
Early Termination
• 1. Find out loan balance after 5 years
• 2. Find out initial net cash outlay
• 3. Find out the interest rate that sets the
present value of loan balance in 5 years
(minus possible penalty/fess) and the
mortgage payments in first 5 years to the
initial net cash outlay (OLB0-Fees and points)
4-24
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