GLYPHOSATE RESISTANCE Background / Problem

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Transcript GLYPHOSATE RESISTANCE Background / Problem

Lecture 8: Types of Selection September 17, 2012

Reminders

 I will be gone Thursday and Friday. No office hours this week.

 Monday Review Session  Bring specific questions!

 Exam next Wednesday  Everything mentioned in lecture and lab fair game  Formulas provided: see sample exam

Last Time

 Introduction to selection  Predicting allele frequency change in response to selection

Today

 Dominance and types of selection  Why do lethal recessives stick around?

 Equilibrium under selection  Stable equilibrium: overdominance  Unstable equilibrium: underdominance

Putting it all together Relative Fitness (ω) Relative Fitness (hs) A 1 A 1 ω 11 1 A 1 A 2 ω 12 1-hs Δq =pq[q(ω 22 Reduces to: – ω 12 ) - p(ω 11 - ω 12 )] ω Δq =-pqs[ph + q(1-h)] 1-2pqhs-q 2 s A 2 A 2 ω 22 1-s

Modes of Selection on Single Loci

Directional – One homozygous genotype has the highest fitness

Purifying selection AND Darwinian/positive/adaptive selection

ω

1 0.8

0.6

0.4

0.2

0

 

Depends on your perspective!

0 ≤ h ≤ 1 A AA 1 A 1 A Aa 1 A 2 A 2 A 2

Overdominance – Heterozygous genotype has the highest fitness (balancing selection) h<0, 1-hs > 1

Underdominance – The heterozygous genotypes has the lowest fitness (diversifying selection) h>1, (1-hs) < (1 – s) < 1 for s > 0

ω

1 0.8

0.6

0.4

0.2

0 A AA 1 A 1 A Aa 1 A 2 A 2 A 2

ω

1 0.8

0.6

0.4

0.2

0 A AA 1 A 1 A Aa 1 A 2 A 2 A 2

Directional Selection Δq =-pqs[ph + q(1-h)] 1-2pqhs-q 2

s

0 ≤ h ≤ 1 Δq 0

q

0.5

q

1 h=0.5, s=0.1

Time

Lethal Recessives Relative Fitness (ω) A 1 A 1 ω 11 A 1 A 2 ω 12 Relative Fitness (hs) 1

For completely recessive case, h=0 1-hs

For lethality, s=1

ω

0.8

0.6

1 0.4

0.2

0 A 1 A A 1 1 1 A 1 1 A 1 A 1 2 1 A 2 2 A 2 A 2 2 2 A 2 2 A 2 A 2 ω 22 1-s

Lethal Recessive Δq = -pqs[ph + q(1-h)] = 1-2pqhs-q 2 s For q<1 -pq 2 1-q 2 =

0.0

h=0; s=1

-0.1

ω 11 =1; ω 12 =1-hs=1; ω 22 =1-s=0

q

-0.2

-0.3

-0.4

Δq more negative at large q

-0.5

0.0

Population moves toward maximum fitness

1.0

0.8

Rate of change decreases at low q

 0.6

0.4

0.2

0.0

0.0

-q 2 1+q

0.2

0.2

0.4

q

0.6

0.4

q

0.6

0.8

0.8

1.0

1.0

Retention of Lethal Recessives

As p approaches 1, rate of change decreases

Very difficult to eliminate A population

2

, recessive deleterious allele from

Heterozygotes

hidden

from selection (ω 11 =1; ω 12 =1-hs=1)

12 10 

2pq 2q

2

=

At low frequencies, most A

2

heterozygous state:

p p q q 0.5

0.1

0.01

q 1 9 99

are in Ratio of A2 alleles in heterozygotes versus homozygotes

8 6 4 2 0 0.0

0.2

0.4

q

0.6

0.8

1.0

Time to reduce lethal recessives

t

 1

q t

q

1 0

See Hedrick 2011, p. 123 for derivation It takes a very large number of generations to reduce lethal recessive frequency once frequency gets low

Selection against Recessives ω s A 1 A 1 ω 11 1 A 1 A 2 ω 12 1-hs A 2 A 2 ω 22 1-s

For completely recessive case, h=0

For deleterious recessives, s<1

ω

0.8

0.6

1 0.4

0.2

0 A 1 A A 1 1 1 A 1 A 1 A 1 2 1 A 2 A 2 A 2 2 2 A 2

Selection Against Recessives Δq = -pqs[ph + q(1-h)] 1-2pqhs-q 2 s

h=0; 0

Maximum rate of change at intermediate allele frequencies

q

s=0.4

Location of maximum depends on s: q=2/3 for small s

Where is maximum rate of change in q for lethal recessive?

Lethal recessive, continues off chart

What is final value of q?

What is final average fitness of population?

Modes of Selection on Single Loci

Directional – One homozygous genotype has the highest fitness

Purifying selection AND Darwinian/positive/adaptive selection

ω

1 0.8

0.6

0.4

0.2

0

 

Depends on your perspective!

0 ≤ h ≤ 1 A AA 1 A 1 A Aa 1 A 2 A aa 2 A 2

Overdominance – Heterozygous genotype has the highest fitness (balancing selection) h<0, 1-hs > 1

Underdominance – The heterozygous genotypes has the lowest fitness (diversifying selection) h>1, (1-hs) < (1 – s) < 1 for s > 0

ω

1 0.8

0.6

0.4

0.2

0 A AA 1 A 1 A Aa 1 A 2 A aa 2 A 2

ω

1 0.8

0.6

0.4

0.2

0 A 1 A 1 A 1 A 2 A aa 2 A 2

Equilibrium

The point at which allele frequencies become constant through time

Two types of equilibria

Stable

Unstable

The question: stable or unstable?

What happens if I move q a little bit away from equilibrium?

Stable Equilibria

Perturbations from equilibrium cause variable to move toward equilibrium railslide.com

Unstable Equilibria

Perturbations from equilibrium cause variable to move away from equilibrium

Does selection always cause average fitness to approach 1?

Under what conditions do we reach an equilibrium while polymorphisms still exist in the population?

Heterozygote Advantage (Overdominance)

ω

1 0.8

0.6

0.4

0.2

0

New notation for simplicity (hopefully):

Fitness Fitness in terms of

s

and

h q

1 = 1 2 2

p

0

q

0 w 12 w +

q

2 w 22 w =

p

0

q

0 w 12 w +

q

0 2 w 22

AA A 1 A 1 Aa A 1 A 2 aa A 2 A 2

Genotype A 1 A 1

ω

11 1 –

s

1 A

ω

1 1 A 12 2 A

ω

2 1 – A 22

s

2 2

q

1 =

p

0 2

p

0

q

0 +

q

2 0 (1 -

s

2 ) (1 -

s

1 ) + 2

p

0

q

0 +

q

2 0 (1 -

s

2 )

Equilibrium under Overdominance

Equilibrium occurs under three conditions: q=0, q=1 (trivial), and

s 1 p – s 2 q = 0

s

1

p eq

s

2

q eq

 0

s

2

q eq

s

1 ( 1 

q eq

)

s

2

q eq

s

1

q eq

s

1

q eq

s

1

s

1 

s

2

q eq

(

s

1 

s

2 ) 

s

1

Equilibrium under Overdominance

Allele frequency always approaches same value of q when perturbed away from equilibrium value

Stable equilibrium

Allele frequency change moves population toward maximum average fitness

q eq

s

1

s

1 

s

2

Heterozygote Disadvantage (Underdominance) 1 0.8

ω

0.6

0.4

0.2

0 A 1 A 1 A 1 A 2 A aa 2 A 2

Fitness Fitness in terms of

s

and

h

A 1 A 1

ω

11 1 +

s

1 Genotype A 1 A 2

ω

12 1 A 2 A 2

ω

22 1 +

s

2

q eq

s

1

s

1 

s

2

Heterozygote Disadvantage (Underdominance)

Fitness Fitness in terms of

s

and

t

A 1 A 1

ω

11 1 +

s

Genotype A 1 A 2

ω

12 1 A 2 A 2

ω

22 1 +

t

s = 0.1

t = 0.1

Equilibrium under Underdominance

Allele frequency moves away from equilibrium point and to extremes when perturbed

Unstable equilibrium

Equilibrium point is at local minimum for average fitness

Population approaches trivial equilibria: fixation of one allele

Where are equilibrium points?

ω 11

=1.1 ω

12

= 1 ω

22

= 1.1

Underdominance Revisited

Genotype Fitness Fitness in terms of

s 1

and

s 2

Fitness in terms of

s h

 1 and

h

A 1 A 1

ω

11 1 +

s

1 1 A 1 A 2

ω

12 1 1-

hs

A 2 A 2

ω

22 1 +

s

2 1-

s s

1 

hs s

2  

s

(

h hs

  1 )

s ω

s 1

hs

s s 2

A 1 A 1 A 1 A 2 A 2 A 2

Why does

nontrivial

equilibrium occur with underdominance?

Why doesn always go to fixation if

A 1 A 1

genotype?

t A

1

is most fit allele

ω

Proportion of A 1 alleles in heterozygous state:

pq

(pq+p 2 )

= q

A 1 A 1 A 1 A 2 A 2 A 2

What determines the equilibrium point with underdominance?

ω 11 =1; ω 12 =0.8; ω 22 =1 ω 11 =0.85; ω 12 =0.8; ω 22 =1

Why does equilibrium point of A

1

allele frequency increase when selection coefficient decreases?

A 1 A 1 A 1 A 2 A 2 A 2 p eq s

1

p eq

s

1

s

2 

s

2 

s

2

q eq

Example: Kuru in Fore Tribespeople

Prion disease in Fore tribesmen

Transmitted by cannibalism of relatives by women/children

Cannibalism stopped in 1950

s

Older people exposed to selection, younger are

controls

’ 

Identified locus that causes susceptibility: Prion Protein Gene, PRNP

MM and VV are susceptible, MV are resistant http://learn.genetics.utah.edu/features/prions/kuru.cfm

Kuru and Heterozygote Advantage

Selection coefficient (

s

 1  2

v

)

(only females)

0.403

0.2985

0.373

q eq

s MM s MM

s VV

 0 .

483 

Tremendous selective advantage in favor of heterozygotes

Balancing selection maintains polymorphism in human populations