Transcript Slide 1

Chapter 14
Aqueous Equilibria: Acids and Bases
Polyprotic Acids
 Acids that contains more than one dissociable proton
 Dissociate in a stepwise manner
 Each dissociation step has its own Ka
 Stepwise dissociation constants decreases in the order
Ka1 > Ka2 > Ka3
 More difficult to remove a positively charge proton from
negative ion
Polyprotic Acids
 Diprotic acid solutions contain a mixture of acids:
H2A, HA, H2O
 Strongest acid – HA
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Principle reaction – dissociation of H2A
All of H3O+ come from the first ionization
Polyprotic Acids
Equilibria in Solutions of Weak Bases
B(aq) + H2O(l)
Base
Acid
BH1+(aq) + OH1-(aq)
Acid
Base
[BH1+][OH1-]
Base-Dissociation Constant:
NH3(aq) + H2O(l)
[NH41+][OH1-]
Kb =
[NH3]
Kb =
NH41+(aq) + OH1-(aq)
[B]
Equilibria in Solutions of Weak
Bases
Equilibria in Solutions of Weak
Bases
Calculate the [-OH] and pH of a 0.40 M NH3 solution. At 25
°C, Kb = 1.8 x 10-5.
Example
 Morphine (C17H19NO3), a narcotic used in painkillers,
is a weak organic base. If the pH of a 7.0 x 10-4 M
solution of morphine is 9.5, what is the value of Kb?
Relation Between Ka and Kb
NH41+(aq) + H2O(l)
H3O1+(aq) + NH3(aq)
Ka
NH3(aq) + H2O(l)
NH41+(aq) + OH1-(aq)
Kb
H3O1+(aq) + OH1-(aq)
Kw
2H2O(l)
Ka x Kb =
[H3O1+][NH3]
[NH41+]
x
[NH41+][OH1-]
[NH3]
= (5.6 x 10-10)(1.8 x 10-5) = 1.0 x 10-14
= [H3O1+][OH1-] = Kw
Relation Between Ka and Kb
Ka x Kb = Kw
conjugate acid-base pair
Ka =
Kw
Kb
Kb =
pKa + pKb = pKw = 14.00
Kw
Ka
Example
 Find the pH of a 0.100 M NaCHO2 solution. The salt
completely dissociate into Na+(aq) and CHO2-(aq) and
Na+ ion has no acid or base properties. Ka (HCHO2)=
1.8 x 10-4
Acid-Base Properties of Salts
 pH of a salt solution is determined by the acid-base
properties of the consistuent cations and anions
 In an acid-base reaction, the influence of the stronger
partner is predominant
 Strong acid + Strong Base  Neutral solution
 Strong acid + Weak Base  Basis solution
 Weak acid + Strong Base  Acidic solution
Acid-Base Properties of Salts
 Acidic cation + neutral anion  Acidic salt
 Neutral cation + neutral anion  neutral salt
 Neutral cation + basic anion  basic salt
Acid-Base Properties of Salts
 Acidic cation + basic anion  (50 :50 mixture) must
compare Ka and Kb
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•
Ka > Kb: The solution will contain an excess of H3O1+
ions (pH < 7).
Ka < Kb: The solution will contain an excess of OH1ions (pH > 7).
Ka ≈ Kb: The solution will contain approximately equal
concentrations of H3O1+ and OH1- ions (pH ≈ 7).
Acid-Base Properties of Salts
Salts That Yield Acidic Solutions
Hydrated cations of small, highly charged metal ions, such as Al3+.
Acid-Base Properties of Salts
Copyright © 2008 Pearson Prentice Hall, Inc.
Chapter
14/17
Examples
 Calculate Ka for the cation, and Kb for the anion in an
aqueous NH4CN solution. Is the solution acidic, basic
or neutral? Write the hydrolysis reaction of the salt
(Kb for NH3 = 1.8 x 10-5, Ka for HCN = 4.9 x 10-10)
 Predict whether 0.35 M NH4Br solution is neutral,
basic or acid. Write the hydrolysis equation and
calculate the pH
Lewis Acids and Bases
Lewis Acid: An electron-pair acceptor.
• Include cations and neutral molecule having
vacant valence orbitals that can accept a share
in a pair of electrons from a Lewis Base
Lewis Base: An electron-pair donor.
• All Lewis bases are Bronsted-Lowry bases
Lewis Acids and Bases
Lewis Acids and Bases
Lewis Acids and Bases
Examples
 For each of the following reactions, identify the Lewis
acid and the Lewis base
 CO2(g)
+ -OH(aq)  HCO3-(aq)
 AlCl3(aq) + Cl-(aq)  AlCl4-(aq)