Transcript Lyle and Louise Entomology Kit Climatological Data

Entomology Kit
Climate Data Analysis Tutorial
Vandalia Science Education
Updated 2/22/11
Degree-Hour Determination
Knowns
• Bodies discovered at 1:00PM on June 20
• Insects collected at 3:00PM on June 20
• Weather type (sunny, partly cloudy, overcast)
• Weather events (rain, thunderstorms, snow)
• Daily average temperature
• Male and Female had the same species and lifecycles present
(Migrating 3rd Instar Species A, 2nd Instar Species B)
Unknowns
• Elapsed degree-hours for each day
• Degree-hours for each life stage of both species
• Cumulative degree-hours for each life stage of both species
• Cumulative elapsed degree hours for each day
• Which day the adult insect from both species laid its eggs
• Earliest and latest time the insects began developing
Elapsed degree-hours for each day
Lab Procedure 2, Step 2: Determine the number of degree hours for each day using the
weather service data. To do this, multiply the average temperature times 24 hours for
each day. This can be performed in a spreadsheet.
• The collection time was 3:00PM on June 20,
this tells us to multiply the first average
temperature by 15 hours instead of 24
• Every other daily average temperature in the
month will be multiplied by 24
Elapsed degree-hours for each day
DAY MAX MIN AVG DEPAR DEPAR- HEATIN COOLIN TOTA SNOWSNOW,
AVG AVG
SKY
WEATHER
PEAK degree
-TURE TURE
G
G
L
FALL,
ICE
SPEE SPEED COVER OCCURENC WIND hours
FROM FROM
WATE ICE
PELLETS
D (KPH) SUNRISE
ES
(KPH)
NORMA NORMAL
R PELLET OR ICE (MPH
-SUNSET
L
EQUI
S
ON
)
V
GROUND
S 18.7 386.66666
18. 10. 16.
1
3
6
1
-1.9 -1.0
2.2
0.0 0.00
0
0
6.3 10.08
6
0
7
SE
19. 12. 15.
26.2
2
4
8
0
-3.0 -1.7
3.3
0.0 0.09
0
0
13.8 22.08
6
0
SW
17.
12.
33.3
3
2 9.4 8
-5.2 -2.9
5.6
0.0 0.19
0
0
17.2 27.52
8
5
W 38.6
20. 10. 13.
4
0
6
3
-4.7 -2.6
5.0
0.0 0.28
0
0
12.3 19.68
9
1
W 28.3
21. 12. 19.
5
1
8
4
1.4
0.8
0.0
1.1 0.00
0
0
11.1 17.76
7
1,2
SW
25. 16. 20.
24.3
6
6
7
6
2.6
1.4
0.0
2.2 0.00
0
0
8.1 12.96
6
0
S 16.7
23. 15. 19.
7
9
2
4
1.4
0.8
0.0
1.1 0.07
0
0
6.3 10.08
8
0
S 27.9
20. 12. 16.
8
6
8
1
-1.9 -1.0
0.0
0.0 0.11
0
0
13.2 21.12
8
0
SE
22. 13. 18.
10.3
9
1
9
9
0.9
0.5
0.0
0.6 0.00
0
0
4.2 6.72
3
0
S 22.7
25. 12. 16.
14.20
10 0
6
1
-1.9 -1.0
0.0
0.0 0.00
0
0
8.88
8
6
0
S 32.4
22.
15.
11 1 8.9 3
-2.7 -1.5
0.0
0.0 0.67
0
0
19.6 31.36
6
3,5
SW
14.
10.
43.8
12 5 9.4 5
-7.5 -4.2
0.0
0.0 1.13
T
0
23.5 37.6
8
1,3,5
S 29.8
16.
12.
13 7 7.2 1
-5.9 -3.3
0.0
0.0 0.23
0
0
14.2 22.72
7
1,2
S 24.5
19.
15.
14 3 9.3 0
-3.0 -1.7
0.0
0.0 0.02
0
0
10.5 16.8
8
1
SW 23
16.
12.
15 5 8.9 8
-5.2 -2.9
0.0
0.0
T
0
0
11.9 19.04
4
0
W 19.2
18. 10. 13.
16 9
7
3
-4.7 -2.6
0.0
0.0 0.00
0
0
6.4 10.24
3
0
S 27.2
16.
12.
17 8 9.5 9
-5.1 -2.8
0.0
0.0 0.00
0
0
9.5 15.2
3
0
W 26.3
19. 10. 16.
18 4
7
4
-1.6 -0.9
0.0
0.0 0.00
0
0
11.1 17.76
2
0
SW
19. 10. 15.
17.8
19 1
9
9
-2.1 -1.2
0.0
2.8 0.00
0
0
4.6 7.36
1
0
W 23.1
22. 12. 18.
20 0
8
4
0.4
0.2
0.0
5.0 0.00
0
0
7.4 11.84
1
0
Degree-hours for each life stage: Species A
Lab Procedure 2, Step 3: Determine the number of degree hours required for each life
stage of both species. To do this, multiply the number of hours by the degrees Celsius
given in the table.
Temp
°C
Egg
1st
Instar
2nd Instar
Feeding 3rd
Instar
Migrating
3rd Instar
Pupa
21
21
31
26
50
118
240
21*21 =
441
Degree-hours for each life stage: Species B
Lab Procedure 2, Step 3: Determine the number of degree hours required for each life
stage of both species. To do this, multiply the number of hours by the degrees Celsius
given in the table.
Temp
°C
Egg
1st
Instar
2nd Instar
Feeding 3rd
Instar
Migrating
3rd Instar
Pupa
21
25
37
31
60
124
286
25*21 =
525
Cumulative degree-hours for each life stage:
Species A
Lab Procedure 2, Step 4: By adding all the degree hours for each of the six life stages
together, you calculate the cumulative degree hours required for an adult fly to develop
at 21°C.
Temp
°C
Egg
1st Instar
2nd Instar
Feeding 3rd
Instar
Migrating
3rd Instar
Pupa
21
21
31
26
50
118
240
Deg Hrs
441
651
546
1050
2478
5040
Cum.
Deg Hrs
441
651+441
= 1092
Adult degree-hours = ∑ degree hours at each stage
= cumulative degree hours
=
Cumulative degree-hours for each life stage:
Species B
Lab Procedure 2, Step 4: By adding all the degree hours for each of the six life stages
together, you calculate the cumulative degree hours required for an adult fly to develop
at 21°C.
Temp
°C
Egg
1st Instar
2nd Instar
Feeding 3rd
Instar
Migrating
3rd Instar
Pupa
21
25
37
31
60
124
286
Deg Hrs
525
777
651
1260
2604
6006
Cum.
Deg Hrs
525
777+525
= 1302
Adult degree-hours = ∑ degree hours at each stage
= cumulative degree hours
= ?????
2
Cumulative degree-hours for each day
Lab Procedure 2, Step 5: Calculate elapsed degree hours for each of the days in the
climatological data provided. To do this, multiply the number of hours by the average
temperature that day.
DAY MAX
1
MIN
AVG DEPAR- DEPAR- HEATING COOLING TOTAL SNOW- SNOW, ICE AVG
AVG
SKY
WEATHER
PEAK degree
TURE
TURE
WATER FALL, PELLETS SPEED SPEED
COVER OCCURENCES WIND hours
FROM
FROM
EQUIV
ICE OR ICE ON (MPH) (KPH) SUNRISE(KPH)
NORMAL NORMAL
PELLETS GROUND
SUNSET
18.3 10.6 16.1
-1.9
-1.0
2.2
0.0
0.00
0
0
6.3
10.08
6
0
cumulative
degree
hours
S 18.7 386.66666
7
SE 26.2
2
19.4 12.8 15.0
-3.0
-1.7
3.3
0.0
0.09
0
0
13.8 22.08
6
0
3
4
17.2 9.4 12.8
20.0 10.6 13.3
-5.2
-4.7
-2.9
-2.6
5.6
5.0
0.0
0.0
0.19
0.28
0
0
0
0
17.2 27.52
12.3 19.68
8
9
5
1
5
21.1 12.8 19.4
1.4
0.8
0.0
1.1
0.00
0
0
11.1 17.76
7
1,2
6
25.6 16.7 20.6
2.6
1.4
0.0
2.2
0.00
0
0
8.1
12.96
6
0
7
23.9 15.2 19.4
1.4
0.8
0.0
1.1
0.07
0
0
6.3
10.08
8
0
8
20.6 12.8 16.1
-1.9
-1.0
0.0
0.0
0.11
0
0
13.2 21.12
8
0
9
22.1 13.9 18.9
0.9
0.5
0.0
0.6
0.00
0
0
3
0
10 25.0 12.6 16.1
-1.9
-1.0
0.0
0.0
0.00
0
0
8.88 14.208
6
0
11 22.1 8.9 15.3
-2.7
-1.5
0.0
0.0
0.67
0
0
19.6 31.36
6
3,5
SW 33.3
W 38.6
W 28.3
SW 24.3
S 16.7
S 27.9
SE 10.3
4.2
6.72
S 22.7
360
306.66666
7
320
466.66666
7
493.33333
3
466.66666
7
386.66666
7
453.33333
3
386.66666
7
S 32.4
367.2
SW 43.8
12 14.5 9.4 10.5
-7.5
-4.2
0.0
0.0
1.13
T
0
23.5
37.6
8
1,3,5
252
S 29.8
13 16.7 7.2 12.1
-5.9
-3.3
0.0
0.0
0.23
0
0
14.2 22.72
7
1,2
14 19.3 9.3 15.0
-3.0
-1.7
0.0
0.0
0.02
0
0
10.5
8
1
290.4
S 24.5
16.8
SW
15
16
17
18
16.5
18.9
16.8
19.4
8.9
10.7
9.5
10.7
12.8
13.3
12.9
16.4
-5.2
-4.7
-5.1
-1.6
-2.9
-2.6
-2.8
-0.9
0.0
0.0
0.0
0.0
0.0
0.0
0.0
0.0
T
0.00
0.00
0.00
0
0
0
0
0
0
0
0
19 19.1 10.9 15.9
20 22.0 12.8 18.4
-2.1
0.4
-1.2
0.2
0.0
0.0
2.8
5.0
0.00
0.00
0
0
0
0
11.9 19.04
6.4 10.24
9.5
15.2
11.1 17.76
4.6
7.4
7.36
11.84
4
3
3
2
0
0
0
0
1
1
0
0
W
S
W
SW
W
360
23 306.66666
7
19.2
320
27.2
309.6
26.3
393.6
17.8
381.6
23.1
276
7283.73333
Which day the adult insect laid eggs on
the body: Species A
Lab Procedure 2, Step 6a: Examine the species A life stages collected as evidence and
identify the oldest species A life stage collection for the adult male.
DAY degree
hours
1
cumulative
degree
hours
386.66666
7
2
Feeding 3rd
Instar
Migrating 3rd
Instar
50
118
1050
2478
1050+1638 =
2688
2478+1638 =
5166
7283.73333
360
306.66666
3
7
4
320
466.66666
5
7
493.33333
6
3
466.66666
7
7
386.66666
8
7
453.33333
9
3
386.66666
10
7
6897.06667
11
367.2
3257.06667
12
252
2889.86667
13
290.4
2637.86667
14
2347.46667
15
16
17
18
360
306.66666
7
320
309.6
393.6
19
20
381.6
276
657.6
276
6537.06667
6230.4
5910.4
5443.73333
4950.4
4483.73333
4097.06667
3643.73333
1987.46667
1680.8
1360.8
1051.2
On Day 11, the cumulative degree-hours were _____
Species A takes ______degree-hours to complete
development in the Feeding 3rd Instar and begin
development in the Migration stage of the 3rd Instar.
The temperature data alone suggests that the eggs
were laid on the 12th, but there was a storm then, so
we know that the eggs were laid before then since
flies are not active during thunderstorms.
Which day the adult insect laid eggs on
the body: Species B
Lab Procedure 2, Step 6a: Examine the species A life stages collected as evidence and
identify the oldest species B life stage collection for the adult male.
DAY degree
hours
1
cumulative
degree
hours
386.66666
7
2
7283.73333
360
306.66666
3
7
4
320
466.66666
5
7
493.33333
6
3
466.66666
7
7
386.66666
8
7
453.33333
9
3
386.66666
10
7
6897.06667
11
367.2
3257.06667
12
252
2889.86667
13
290.4
2637.86667
14
2347.46667
15
16
17
18
360
306.66666
7
320
309.6
393.6
19
20
381.6
276
657.6
276
6537.06667
6230.4
5910.4
1st Instar
2nd Instar
37
31
777
651
777+525 =
1302
651+1302 =
1953
5443.73333
4950.4
4483.73333
4097.06667
3643.73333
1987.46667
1680.8
1360.8
1051.2
On Day 17, the cumulative degree-hours were _____.
Species B takes ______ degree-hours to complete
development in the 1st Instar and begin development
in the 2nd Instar.
How Long have the bodies been
expired (dead)?
DAY degree
hours
10
453.3333
33
386.6666
67
11
367.2
12
252
13
290.4
14
15
16
17
18
360
306.6666
67
320
309.6
393.6
19
20
381.6
276
9
cumulative
degree
hours
Post Mortem Interval = ∑ hours(day)
= h(20) + h(19) + h(18) … h(10)
= 207 hours
= 8 days, 15 hours
THUNDERSTORM
The post mortem interval was calculated to be
______but we know that the storm occurred on the
evening of the 11th, so we conjecture that at the flies
were active at least an hour on the 11th, thus bringing
our PMI to a minimum of __________. The actual
PMI, which is unknown, may vary up to 12 hours more
than this calculation due to weather. Students’
calculations may vary by up to a day later.