PETROLEUM ENGINEERING 405
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Transcript PETROLEUM ENGINEERING 405
PETE 411
Well Drilling
Lesson 3
The Rig - Drilling Equipment
1
Contents
Rig Pumps
Solids Control Equipment
Air Drilling
The Rotary System
The Swivel
The Well Control System
The Well Monitoring System
Offshore Drilling
2
Assignments:
READ:
ADE Ch. 1, to p.30
HW #1:
ADE 1.1, 1.2, 1.3
Due Monday, Sept. 9, 2002
at the beginning of class
NOTE: Answers in book are not
always correct...
3
Schematic of
Rig
Circulating
System for
liquid
drilling fluid
4
5
Example 1.3
Compute the pump factor in units of
barrels per stroke for a double-acting
duplex pump having:
6.5-inch liners
(dL)
2.5 inch rods
(dr)
18-inch strokes
(LS)
and a volumetric efficiency of 90%. (EV)
6
Solution:
The pump factor for a duplex pump can
be determined using Equation 1.10
2
2
Fp L SE V 2dL dr
2
2
2
18 0.9 26.5 2.5
2
3
1991 in / stroke
7
Recall:
There are 231 in.3 in an U. S. gallon and
42 U.S. gallons in a U.S. barrel. Thus
converting to the desired field units
yields:
1991 in.3/stroke * gal/231 in.3 * bbl/42 gal.
= 0.2052 bbl/stroke.
Thus: Pump Factor = 0.2052 bbl/stroke
8
Pump Factor = 3 * /4 dL2 LS EV/(231 * 42)
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Example:
Pump Factor for Triplex Pump
2
3 dL L S E V
4
3
in
bbl
2
3 6 120.90
in.
stroke 231 42
4
0.09442 bbl/stroke
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Example: Pump Rate
= Pump Factor * Strokes/min
bbl
stks
80
= 0.09442
stk
min
= 7.554 bbl/min
= 317.3 gal/min
Pump Rate = 317 gal/min
11
Hydrocyclone
• desander
• desilter
* Pressure drop
* Diameter
* No moving parts
* Low cost
12
Decanting Centrifuge
Use?
13
l
l
Use?
14
Fig. 1.33
Schematic
of Rotary
System
15
Fig. 1.34
Cutaway
View of
Swivel
ROTATING
* Seals
* Bearings
16
PIN
BOX
TJ
Shoulder
Fig. 1.38
Cutaway View and
Dimensions for
Example Tool Joint
17
Fig. 1.39
Stabilizer
* Keeps pipe in center of hole
* Aids in drilling straight hole
* Prolongs bit life
18
Fig. 1.41
Kick Detection During
Drilling Operations
3
GAIN IN PIT
VOLUME EQUAL
TO KICK VOLUME
KICK 2
1
19
CHOKE
Fig. 1.46
Remote
Control
Panel for
operating
Blowout
Preventers
What to do if KICK occurs?
20
DP
TJ
DC
OH
Press
Fig. 1.44 Annular Blowout Preventer
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Ram Blowout Preventer
22
SHEAR / BLIND
RAM ASSEMBLY
Ram Blowout Preventer - cont’d
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Fig. 1.48 Rotating Blowout Preventer
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Fig. 1.51
HighPressure
Circulating
System for
Well
Control
Operations
Kick
Keep BHP const.
25
Fig. 1.56
Subsurface
Well
Monitoring
System
MWD
26
OFFSHORE DRILLING
Fig. 1.57 Spread Mooring Systems
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Fig. 1.58
Schematic of
Equipment
for Marine
Drilling
28
Fig. 1.59 Operation of a
Heave Compensator
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Fig. 1.60
Subsea
BOP
Stack
30
Fig. 1.63 Subsea Equipment
Installation Procedure
31
Typical Casing Strings
Water Level
Seafloor
Conductor pile
Depth
Below ML
36” 30” 200’
Conductor Casing 26” 20” 1000’
Surface Casing
17 1/2” 13 3/8” 4000’
Hole Csg. Depth32
Some Typical Casing Strings
Depth
Below ML
Conductor pile
36” 30” 200’
Conductor Casing 26” 20” 1000’
Surface Casing
17 1/2” 13 3/8” 4000’
Hole Csg. Depth
33
Capacity = Area * Length
34
What is the capacity of 10,000 ft of 5”
OD, 19.50 lb/ft drillpipe?
Capacity = Area * Length
Area = /4 d2 = /4 * 4.2762 = 14.36 in2
Length = 10,000 ft = 120,000 in
Capacity = 14.36 *120,000 in3 /(231*42 in3 /bbl)
Capacity = 177.6 bbls
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What is the displacement of 10,000 ft
of 5” OD, 19.50 lb/ft drillpipe?
Capacity = Area * Length
Area = /4 (od2 - id2 ) = /4 * (52 - 4.2762)
= 5.275 in2
Length = 10,000 ft = 120,000 in
Displ. = 5.276 * 120,000 in3 /(231 * 42 in3 /bbl)
Displacement = ?
Bbls
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