Transcript Slide 1
1. Introduction and Fundamental Concepts [1] 1. System-Surroundings-Interaction 2. Physical Phenomena, Physical Quantities, and Physical Relations 3. Physical Quantity q [q ] 1. Dimensions 2. Numerical value Q 3. Unit of Measure Q l 2 m, l 4. [l ] L ( Length) 2 m 2. numerical value wrt unit of measure Q 3. unit of measure Q [ l] L ( Length) 1. Dimension Dimensions – A simple key to some physical understanding of fluid mechanics Systems of Dimensions and Units Physical Quantity Units of Measure Dimension is a power-law monomial and and Principle of Absolute Significance of Relative Magnitude (PASRM) 5. Physical Relation 6. Dimensionless Variables and ‘Measuring/Scaling’ abj , Principle of Dimensional Homogeneity 1 Fundamental Concept: System-Surroundings-Interaction Universe / Isolated System Surroundings Interaction Mechanical interaction (force) Thermal interaction (energy and energy transfer) (Physical) System Electrical, Chemical, etc. The very first task in any one problem: Identify the system Identify the surroundings Identify the interactions between the system and its surroundings, e.g., abj Mechanics - Force (identify all the forces on the system by its surroundings) Thermodynamics - Energy and Energy Transfer (identify all forms of energy and energy transfer between the system and its surroundings) 2 Example: Thermodynamics - Heating Water Water 1 liter in a container in atmosphere. Add heat of the amount Q. [Assume no heat loss elsewhere.] QUESTION: How much is the temperature rise? Q abj Q mcT ? T Q ? mc 3 Energy transfer as heat Q into the two systems are not the same. Two different systems have two different (energy) interactions with their own surroundings. System 1: Q mcT ? T Q ? mc Water + Container Q T System 1 ? mc • How much is the energy transfer as heat into the System 1? Q? Obviously, at least the mass of the two systems are not the same. System 2: Water only Q T System 2 ? mc Q abj Q? • How much is the energy transfer as heat into the System 2? 4 Example: (Fluid) Mechanics - Flow in Pipe System 1: Water stream in the pipe only, exclude the solid pipe and flange. System 2: Water stream in the pipe, and the solid pipe and flange (cut through the bolts). abj 5 External forces on the two systems are not the same. Two different systems have two different (mechanical) interactions with their own surroundings. System 1: • Pressure and shear stress distributions on the surfaces only. • No force at the solid bolt. Obviously, at least the mass of the two systems are not the same. F System 2: • There are forces at the solid bolts acting on the system. abj 6 Key Point: Define your system first before you apply an equation. Since the application of basic principles / equation is always to a specific system, define your system first before you apply an equation. abj 7 Classification of Systems Interaction between system and surroundings Exchange of Mass Exchange of Energy (between system and surroundings) (between system and surroundings) Isolated system No No Closed system No Yes Yes Yes (Identified mass, Control mass, Material volume) Open system (Identified volume, Control volume) abj 8 Example: Various types of systems Isolated system: Insulated hot water bottle (approximately isolated over a short period of time, no energy absorption due to radiation, etc.) abj Closed system Open system (part of the mass is evaporated out of the system) 9 Physical Phenomena, Physical Quantities, and Physical Relations physical phenomena physical quantities physical relations [relations among physical quantities] Boeing 747-400 Cruising speed Mach Number = 0.85 (Compressible Flows). (From http://www.boeing.com/companyoffices/gallery/images/commercial/747400-06.html) abj 10 Physical Quantity Describing A Physical Quantity Physical quantity is a concept. A quantifiable/measurable attribute we assign to a particular characteristic of nature that we observe. l 1. abj We must find a way to ‘quantify’ it. 2 m 2. numerical value wrt unit Q 3. unit of measure Q Describing a physical quantity. , [ l] L ( Length) 1. Dimension We need 3 things: 1. Dimension [q ] 2. Numerical value with respect to the unit of measure Q 3. Unit of measure Q 11 2. Q and Q must go together. • Change the unit of measure Q, the numerical value Q must be changed accordingly. l abj 2 m , 2. numerical value wrt unit Q 3. unit of measure Q [ l] L, Length 1. Dimension 1.34 1011 au (astronomic al unit) 1.08 103 nauticalmile 1.24 103 mile 2.19 6.56 yard ft 7.87 101 in 2 102 cm 2 103 mm 2 1010 angstrom In fact, we can change these numerical values to any numerical value that we want so long as we choose the corresponding unit of measure Q. 12 Key Point: Q and Q must go together. Always write the corresponding unit Q for the corresponding numerical value Q of a physical quantity. [Except when that quantity is dimensionless.] m=5 5 what? 5 kg 5 lbm 5 ton? m = 5 ton abj 13 Fundamental Concept: Quantification and Measure(ment) (Any sort of) Quantification is always based on measure, unit of measure, measurement. There is a degree of arbitrariness in choosing a unit of measure. l abj 2 m , 2. numerical value wrt unit Q 3. unit of measure Q [ l] L, Length 1. Dimension 1.34 1011 au (astronomic al unit) 1.08 103 nauticalmile 1.24 103 mile 2.19 6.56 yard ft 7.87 101 in 2 102 cm 2 103 mm 2 1010 angstrom In fact, we can change these numerical values to any numerical value that we want so long as we choose the corresponding unit of measure Q. 14 Key Point: Dimensions - A simple key to gain some understanding of fluid mechanics (or rather physics in general) The followings cannot be emphasized enough. To gain some physical understanding of fluid (mechanics), pay attention to the dimensions of the physical quantity/relation of interest. Choose any dimension that you can relate physically, not necessarily – and often not - MLtT. • Enthalpy abj h has the dimension of • L2t-2 “What is this?” • Energy/Mass O.k. This, I can relate. 15 More Example: Dimensions - A simple key to gain some understanding of fluid mechanics (or rather physics in general) Specific heat Note • L2t-2T-1 • Energy Mass Temp Energy Mass Temp C has the dimension of “What is this?” O.k. This, I can relate. reads “Energy per unit mass per unit (change in) temp” • I can guess that C should somehow be related to the amount of energy per unit mass per unit (change in) temperature. abj 16 Systems of Dimensions and Units 1. Primary Quantities and Primary Dimensions Choose a set of primary quantities (and consider their dimensions to be independent). 2. Three systems of common use are FMLtT Choose a unit of measure for each primary quantity. MLtT: In SI: M – kg, L – m, t – sec, T–K Derived Quantities/Dimensions Through physical relations, we have derived quantities and their dimensions By definition By law abj FLtT, Units of Measure for Each Primary Quantity 3. MLtT, e.g., dr V dt F ma [Velocity] = L/t, [r ] [V ] [t ] [ F ] [m][a ] MLt 2 [Acceleration] = L/t2 [Force] = ML/t2, etc. 17 Key Point: There is some arbitrariness in choosing primary quantities and dimensions. Conceptually, for example, we can choose ELtT Energy-Length-Time-Temp as a set of primary quantities and primary dimensions in place of MLtT abj 18 Example of Systems of Units: SI From Physics Laboratory, The National Institute of Standards and Technology (NIST)’s web page: http://physics.nist.gov/cuu/Units/SIdiagram2.html abj Note that there can be some characters missing from this diagram due to font and file related issues during the making of the presentation slide. Go to the NIST’s web page given above for the original. 19 Fundamental Concepts: Physical Quantity: Chosen System of Units and The Principle of Absolute Significance of Relative Magnitude (PASRM) To have some physical sense, (we prefer to use and/or) we require (of systems of units to be used) that the ratio of magnitudes of any two concrete physical quantities should not depend on the system of units used. A2 A1 A2 in m 2 A in m 2 1 A2 in ft 2 A in ft 2 1 r The ratio A2/A1 should be the same regardless of whether the numerical values of A1 and A2 are expressed in m2 or ft2. What about abj T2 in K T2 in o C ??? o T1 in K T1 in C 20 Dimension (function) is a power-law monomial The dimensions of a derived quantity q must be in the form of a power-law monomial [q] M a Lbt cT d e.g., [V ] L1t 1 It cannot be, e.g., [q] sin(M ), [q] e ML In other words, the argument of these functions must be dimensionless, e.g., if we know that we then know that abj V (t ) Vo sin(at b) [at b] M 0 L0t 0T 0 1 [ a] 1 / t , [b] 1 21 Dimensionless Quantity Dimensionless quantity q has the dimension of [q] M 0 L0t 0T 0 1 Example abj Efficiency : W ork/ Energy output W ork/ Energy Input Angle (radian) : s r [ ] M 0 L0 t 0T 0 1 [ ] M 0 L0t 0T 0 1 22 Independent Dimensions Independent Dimensions: Physical quantities q1,…, qr are said to have independent dimensions if none of these quantities has a dimension function that can be written in terms of a power-law monomial of the dimensions of the remaining quantities. (Barenblatt, 1996) By definition By law dr V dt F ma [r ] [V ] Lt 1 [t ] [ F ] [m][a ] MLt 2 In MLtT system, since the dimension of velocity V can be written as the power-law monomial of L and t, V = L1t-1 the physical quantities (Velocity, Length, time) do not have independent dimension. Similarly, (Length, Time, Mass, and Force) do not have independent dimension since, according to Newton’s Second law of motion, abj F = MLt-2 23 Physical Relation and Principle of Dimensional Homogeneity (PDH) Requirement/Premise: Any equation that describes a physical relation cannot be dependent upon an arbitrary choice of units (within a given class of systems of units). Principle of Dimensional Homogeneity (PDH): All physically meaningful equations, i.e., physical relation/equation, are dimensionally homogeneous. (Smits, 2000) If then Y X1 X 2 Y , X 1 , X 2 , is a physical equation, have the same dimension, i.e., Y X1 X 2 Useful for checking our derived result: [We shall deal only with physical equations.] abj Physical Relation Dimensionally homogeneous ~ Dimensionally homogeneous ~ Physical Relation (We derive something wrong somewhere.) 24 Example: The Use of The Principle of Dimensional Homogeneity in Checking Our Results We can use PDH to tell whether something is definitely wrong. QUESTION: Without the knowledge of mechanics, can you tell whether this result/equation is V 2g h wrong: ? [V ] Velocity [ 2 g h] ( Lt 2 )1/ 2 L L3 / 2t 1 Velocity The result is not correct. However, we cannot use PDH to tell whether something is definitely correct. Even though our result is dimensionally homogeneous, we cannot tell whether it is correct by PDH alone. 1 2 gt ? 4 1 [ s] [ut] [ gt 2 ] 4 s ut abj 25 Dimensionless Variables and ‘Measuring/Scaling’ Dimensionless Variables: From Y X1 X 2 X n if we divide through by one of the term, say Xn, we obtain Y X1 X 2 X n 1 1 X X X X n n n n The new variables, e.g., X Z i i Xn Scaling/Measuring: Xi is Zi fraction of Xn. then have no dimension. We call these variables dimensionless variables. abj Scaling: One can think of the above process as the measurement/scaling of the variables Y, X1,…,Xn-1, with Xn. In other words, we measure, e.g., Xi as a fraction (or per cent) of Xn, or we measure Xi relative to Xn 26 Example: Dimensionless Variables and ‘Measuring/Scaling’ Unit of measure L cm D D (= 10 cm) The pipe is 300 cm long - unit of measure = cm L 300 1 cm The pipe is 30 D long - unit of measure = D L 30 D abj 27 Key Idea: Use the units/scales of measure that are inherent in the problem itself, not the man-made one irrelevant to the problem. Unit of measure L cm D D (= 10 cm) L 300 1 cm L 30 D • In order to understand physical phenomena better, we prefer to use the units/scales of measure that exist in the problem itself, not the man-made one irrelevant to the problem. abj 28 Key Point: The numerical value of dimensionless variable does not depend on the (appropriate) system of units used. While the numerical values of power output in the units of Watt and hp are not the same, 2,000 W VS 2,000/746 = 2.68 hp the numerical value of the dimensionless variables efficiency is the same regardless of whether we use W or hp: : W ork/ Energy output W ork/ Energy Input [ ] M 0 L0t 0T 0 1 2,000 W 2,000/ 746 hp 4,000 W 4,000/ 746 hp 0.5 Other examples of dimensionless variables are abj Reynolds number Re Mach number M 29