OPTION PRICING MODEL

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Transcript OPTION PRICING MODEL

ESTIMATING u AND d

Binomial Distribution Derivation of the Estimating Formula for u an d

Estimating u and d

The estimating equations for determining u and d are obtained by mathematically solving for the u and d values which make the statistical characteristics of a binomial distribution of the stock’s logarithmic returns equal to the characteristic's estimated value.

The resulting equations that satisfy this objective are:

Equations

u

e tV e A

/

n

 

e A

/

n d

e

tV e A

/

n

 

e A

/

n

Terms

t

time to

exp

iration

exp

ressed as a proportion of a year

.

e A

,

V e A

annualized mean and

var log

arithmic return

.

Logarithmic Return

• The logarithmic return is the natural log of the ratio of the end-of-the-period stock price to the current price: ln 

S n S

0 

Example

: ln   $110 $100   ln   $95 $100   .

0953 .

0513

Annualized Mean and Variance

• The annualized mean and variance are obtained by multiplying the estimated mean and variance of a given length (e.g, month) by the number of periods of that length in a year (e.g., 12).

• For an example, see JG, pp. 167-168.

Example: JG, pp. 168-169.

• Using historical quarterly stock price data, suppose you estimate the stock’s quarterly mean and variance to be 0 and .004209.

• The annualized mean and variance would be 0 and .016836.

• If the number of subperiods for an expiration of one quarter (t=.25) is n = 6, then u = 1.02684 and d = .9739.

Estimated Parameters:

Estimates of u and d: 

e A V e A

 4 

e q

 4

V e A

 

u

e

[.

(.

 0 )]/ 6  0 6  016836

d

e

 [.

25 016836 )]/ 6  0 6  .

9739

Call Price

The BOPM computer program (provided to each student) was used to value a $100 call option expiring in one quarter on a non dividend paying stock with the above annualized mean (0) and variance (.016863), current stock price of $100, and annualized RF rate of 9.27%.

n 6 u

BOPM Values

d rf Co* 1.02684

.9739

1.0037

$3.25

30 100 1.01192

.9882

1.00074

$3.34

1.00651

.9935

1.00022

$3.35

  0 ,

V e A

 .

016836 ,

R f A

 .

0927 ,

t

 .

25

R p R

)  1

u and d for Large n

In the u and d equations, as n becomes large, or equivalently, as the length of the period becomes smaller, the impact of the mean on u and d becomes smaller. For large n, u and d can be estimated as:

u

e tV e A

/

n d

e

tV e A

/

n

 1 /

u

Binomial Process

• The binomial process that we have described for stock prices yields after n periods a distribution of n+1possible stock prices. • This distribution is not normally distributed because the left-side of the distribution has a limit at zero (I.e. we cannot have negative stock prices) • • The distribution of stock prices can be converted into a distribution of logarithmic returns, gn:

g n

 ln F

S

H

n

0 I K

Binomial Process

• The distribution of logarithmic returns can take on negative values and will be normally distributed if the probability of the stock increasing in one period (q) is .5.

• The next figure shows a distribution of stock prices and their corresponding logarithmic returns for the case in which u = 1.1, d = .95, and So = 100.

Binomial process u

d

 .

95 ,

q

 .

5

S g u u

 1 1%   .

09 53

S u

g u

 11 2 1906 25 )

S u

g u

 11% 11

S u

g u

 ln(.

095 )   .

(. )

S u

g u

S u

g u

 ln(.

95 2 )   .

1026 (.

25 )

S uuu

g uuu

 11 3 2859 125 )

S uud

g uud

 11 2 ln(( . )(.

95 1393 375 )

S udd

g udd

 ln((.

95 2   .

(.

)

E g

1 1  022  0054

E g

1 1  044  0108

S ddd

g ddd

 ln(.

95 2 )   .

(.

)

E g

1 1  066  0162

Binomial Process

• Note: When n = 1, there are two possible prices and logarithmic returns: ln ln F F

uS

0 H

S

0

dS

0 H

S

0 I K  I K    .

095  ln(.

95 )   .

0513

Binomial Process

• When n = 2, there are three possible prices and logarithmic returns: ln ln

n

F H F G 2

u S S S

2

d S S

0 0

udS

0 0 0 0 I K  I K  I K  ln( ln( ln(

d u ud

2 2 ) ) )    11 2 ln(.

95 2 )  .

1906 ))  .

044   .

1026

Binomial Process

• Note: When n = 1, there are two possible prices and logarithmic returns; n = 2, there are three prices and rates; n = 3, there are four possibilities.

• The probability of attaining any of these rates is equal to the probability of the stock increasing j times in n period: pnj. In a binomial process, this probability is

p nj

 (

n

n

!

j q j

( 1 

q

)

Binomial Distribution

• Using the binomial probabilities, the expected value and variance of the logarithmic return after one period are .022 and .0054:

E g

1 )  1 )  )   .

] 2  0513 )  .

022    .

] 2  .

0054

Binomial Distribution

• The expected value and variance of the logarithmic return after two periods are .044 and .0108:

E g

1 )  1 )  )   .

] 2  )   1026 )  .

] 2   .

044   .

] 2  .

0108

Binomial Distribution

• Note: The parameter values (expected value and variance) after n periods are equal to the parameter values for one period time the number of periods: ( (

n

)

n

)  

nE g

1 ) 1 )

Binomial Distribution

• Note: The expected value and variance of the logarithmic return are also equal to

n n

)  ) 

u n q

( 1 

q

( 1

q

2

Deriving the formulas for u and d The estimating equations for determining u and d are obtained by mathematically solving for the u and d values which make the expected value and variance of a binomial distribution of the stock’s logarithmic returns equal to the characteristic's estimated value.

Deriving the formulas for u and d

Let

: 

e V e

 

estimated mean of the loagarithmic return

.

Estimated

var

iance of the

log

arithmic return

.

Objective Solve for u and d where

:

u

( 1

q

 

e n q

( 1 

q

2 

V e Or given q

n

5

n

5 2

u

 5 2  

e

V e

Derivation of u and d formulas

Solution:

u

e d

e

  

e

/

n

 

e

/

n where

: 

e and V e

mean and

var

iance for a period equal in length to n

.

For the mathematical derivation see JG

:  .

Annualized Mean and Variance

Equations

u

e tV e A

/

n

 

e A

/

n d

e

tV e A

/

n

 

e A

/

n