Practicing the Ideal Gas Law - x10Hosting

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Transcript Practicing the Ideal Gas Law - x10Hosting

PV = nRT
R = 0.0821 Latm/molK = 8.315 dm3kPa/molK
Ideal Gas Law & Gas Stoichiometry
1) Work out each problem on scratch paper.
2) Click ANSWER to check your answer.
3) Click NEXT to go on to the next problem.
EXIT
CLICK TO START
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QUESTION #1
How many grams of CO2 are
produced from 75 L of CO at 35°C
and 96.2 kPa?
2CO + O2  2CO2
ANSWER
EXIT
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ANSWER #1
Find the new molar volume:
n = 1 mol
V=?
P = 96.2 kPa
T = 35°C = 308 K
R = 8.315 dm3kPa/molK
V = 26.6 dm3/mol
BACK TO PROBLEM
EXIT
PV = nRT
CONTINUE...
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ANSWER #1 (con’t)
3
2CO
4
75 L
+ O2

2CO2
?g
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75 L
CO
1 mol
CO
2 mol
CO2
44.01
g CO2
26.6 L 2 mol
CO
CO
1 mol
CO2
BACK TO PROBLEM
EXIT
= 120 g
CO2
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EXIT
QUESTION #2
How many moles of oxygen will
occupy a volume of 2.5 L at 1.2
atm and 25°C?
ANSWER
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ANSWER #2
n=?
V = 2.5 L
P = 1.2 atm
T = 25°C = 298 K
R = 0.0821 Latm/molK
PV = nRT
n = 0.12 mol
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BACK TO PROBLEM
EXIT
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EXIT
QUESTION #3
What volume will 56.0 grams of
nitrogen (N2) occupy at 96.0 kPa
and 21°C?
ANSWER
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ANSWER #3
V=?
n = 56.0 g = 2.00 mol
P = 96.0 kPa
T = 21°C = 294 K
R = 8.315 dm3kPa/molK
PV = nRT
V = 50.9 dm3
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BACK TO PROBLEM
EXIT
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QUESTION #4
What volume of NH3 at STP is
produced if 25.0 g of N2 is reacted
with excess H2?
N2 + 3H2  2NH3
ANSWER
EXIT
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ANSWER #4
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N2
4
25.0 g
+ 3H2

NH3
?L
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25.0 g
N2
1 mol
N2
2 mol
NH3
22.4 L
NH3
28.02 g 1 mol
N2
N2
1 mol
NH3
BACK TO PROBLEM
EXIT
= 40.0 L
NH3
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QUESTION #5
What volume of hydrogen is
produced from 25.0 g of water at
27°C and 1.16 atm?
2H2O  2H2 + O2
ANSWER
EXIT
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ANSWER #5
Find the new molar volume:
n = 1 mol
V=?
P = 1.16 atm
T = 27°C = 300. K
R = 0.0821 Latm/molK
BACK TO PROBLEM
EXIT
PV = nRT
V = 21.2 L/mol
CONTINUE...
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ANSWER #5 (con’t)
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2H2O
4

25.0 g
2H2 + O2
?L
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25.0 g
H2O
1 mol
H2O
2 mol
H2
21.2 L
H2
18.02 g 2 mol
H2O
H2O
1 mol
H2
BACK TO PROBLEM
EXIT
= 29.4
NEXT
L
H2
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QUESTION #6
How many atmospheres of pressure
will be exerted by 25 g of CO2 at
25°C and 0.500 L?
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EXIT
ANSWER
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ANSWER #6
P=?
n = 25 g = 0.57 mol
T = 25°C = 298 K
V = 0.500 L
R = 0.0821 Latm/molK
PV = nRT
P = 28 atm
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EXIT
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QUESTION #7
How many grams of CaCO3 are
required to produce 45.0 dm3 of CO2
at 25°C and 2.3 atm?
CaCO3 + 2HCl  CO2 + H2O + CaCl2
ANSWER
EXIT
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ANSWER #7
Find the new molar volume:
n = 1 mol
V=?
P = 2.3 atm
T = 25°C = 298 K
R = 0.0821 Latm/molK
BACK TO PROBLEM
EXIT
PV = nRT
V = 11 L/mol
CONTINUE...
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ANSWER #7
CaCO3 + 2HCl  CO2 + H2O + CaCl2
?g
45.0 dm3
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45.0dm3
CO2
1 mol 1 mol 100.09 g
CO2 CaCO3 CaCO3
11 dm3 1 mol 1 mol
CO2
CO2 CaCO3
BACK TO PROBLEM
EXIT
= 410 g
CaCO3
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QUESTION #8
Find the number of grams of CO2 that
exert a pressure of 785 torr at 32.5 L
and 32°C.
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ANSWER
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ANSWER #8
n=?
P = 785 torr = 1.03 atm
V = 32.5 L
T = 32°C = 305 K
R = 0.0821 Latm/molK
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BACK TO PROBLEM
EXIT
PV = nRT
n = 1.34 mol

59.0 g CO2
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