Biochem-5012.1A - Center for Structural Biology

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Transcript Biochem-5012.1A - Center for Structural Biology

Proteins : The primary worker molecule in the body

Transport- hemoglobin in blood

Storage- ferritin in liver

Immune response- antibodies

Receptors- sense stimuli, e.g. in neurons

Channels- control cell contents

Structure- collagen in skin

Enzymes- catalyze biochemical reactions

Cell functions- multi-protein machines

Proteins are amino acid polymers

20 different amino acids: many combinations

Proteins are made in the RIBOSOME

Amino Acid Chemistry

20 different types

amino

NH 2 R 1 C

a

H COOH NH 2 R 2 C

a

H COOH NH 2 R C

a

H COOH NH 2 R 1 C

a

H

acid

CO NH R 2 C

a

H COOH Amino acid Polypeptide Protein

Water, pH and pKa’s

The following sections are taken from a website created by Dr. Michael W. King at Indiana University School of Medicine http://www.indstate.edu/thcme/mwking/home.html

K

eq

, K

w

and pH

As H 2 O is the medium of biological systems one must consider the role of this molecule in the dissociation of ions from biological molecules. Water is essentially a neutral molecule but will ionize to a small degree. This can be described by a simple equilibrium equation: H 2 O <-------> H + + OH Eqn. 1 The equilibrium constant can be calculated as for any reaction: K eq = [H + ][OH ]/[H 2 O] Eqn. 2 Since the concentration of H 2 O is very high (55.5M) relative to that of the [H + ] and [OH ], consideration of it is generally removed from the equation by multiplying both sides by 55.5 yielding a new term, K w : K w = [H + ][OH ] Eqn. 3

K

eq

, K

w

and pH (cont.)

This term is referred to as the ion product. In pure water, to which no acids or bases have been added: K w = 1 x 10 -14 M 2 Eqn. 4 As K w is constant, if one considers the case of pure water to which no acids or bases have been added: [H + ] = [OH ] = 1 x 10 -7 M Eqn. 5 This term can be reduced to reflect the hydrogen ion concentration of any solution. This is termed the pH, where: pH = -log[H + ] Eqn. 6

pKa

Acids and bases can be classified as proton donors (A-H

and proton acceptors (B + H +

BH + A + H + ) ). In biology, various weak acids and bases are encountered, e.g. the acidic and basic amino acids, nucleotides, phospholipids etc. Weak acids and bases in solution do not fully dissociate and, therefore, there is an equilibrium between the acid (HA) and its conjugate base (A ).

HA <-----> A + H + Eqn. 7 This equilibrium can be calculated and is expressed in terms of the association constant K a .

K a = [H + ][A ]/[HA] Eqn. 8 The equilibrium is also sometimes expressed as the dissociation constant K d = 1/K a .

pKa

As in the case of the equilibrium of H + and OH in water, the equilibrium constant K a can be expressed as a pK a : pK a = -logK a Eqn. 9 Therefore, in obtaining the -log of both sides of the equation describing the association of a weak acid, we arrive at the following equation: -logK a = -log[H + ][A ]/[HA] Eqn. 10 Since as indicated above -logK a = pK a and taking into account the laws of logarithms: pK a = -log[H + ] -log[A ]/[HA] Eqn. 11 pK a = pH -log[A ]/[HA] Eqn. 12

The Henderson-Hasselbalch Equation

By rearranging the above equation we arrive at the Henderson-Hasselbalch equation : pH = pK a + log[A ]/[HA] Eqn. 13 The pH of a solution of any acid can be calculated knowing the concentration of the acid, [HA], and its conjugate base [A ]. At the point of the dissociation where the concentration of the conjugate base [A ] = to that of the acid [HA]: pH = pK a + log[1] Eqn. 14 The log of 1 = 0. Thus, at the mid-point of a titration of a weak acid: pK a = pH Eqn. 15

The term pK a is that pH at which an equivalent distribution of acid and conjugate base (or base and conjugate acid) exists in solution.

1.0

Added base .8

.6

.4

.2

pKa .0

2 3 6 7 8 4 pH 5

Buffering

It should be noted that around the pK a the pH of a solution does not change appreciably even when large amounts of acid or base are added. This phenomenon is known as buffering . In most biochemical studies it is important to perform experiments, that will consume H + or OH equivalents, in a solution of a buffering agent that has a pK a experiment. near the pH optimum for the

Thinking beyond the lecture

Clinical significance of blood buffering

Role of kidneys in acid-base balance See Dr. King’s website:

http://www.indstate.edu/thcme/mwking/ionic equilibrium.html

Amino Acid Chemistry

amino

NH 2 R C

a

COOH

acid

H The free amino and carboxylic acid groups have pKa’s NH 3 + NH 2 COOH COO pKa ~ 9.4

pKa ~ 2.2

+ NH 3 R C

a

COO H At physiological pH, amino acids are zwitterions

Amino Acid Chemistry

Amino Acids with Aliphatic R-Groups

Glycine Gly - G 2.4

9.8

2.4

9.9

pKa’s

Alanine Ala - A Valine Val - V 2.2

9.7

Leucine Leu - L 2.3

9.7

Isoleucine Ile - I 2.3

9.8

Amino Acids with Polar R-Groups

Non-Aromatic Amino Acids with Hydroxyl R-Groups

2.2

9.2

~13 Serine Ser - S Threonine Thr - T 2.1

9.1

~13

Amino Acids with Sulfur-Containing R-Groups

Cysteine Cys - C 1.9

10.8

8.3

Methionine Met-M 2.1

9.3

Acidic Amino Acids and Amide Conjugates

Aspartic Acid Asp - D Asparagine Asn - N Glutamic Acid Glu - E Glutamine Gln - Q 2.0

9.9

3.9

2.1

8.8

2.1

9.5

4.1

2.2

9.1

Arginine Arg - R Lysine Lys - K Histidine His - H

Basic Amino Acids

1.8

9.0

12.5

2.2

9.2

10.8

1.8

9.2

6.0

Aromatic Amino Acids and Proline

Phenylalanine Phe - F 2.2

9.2

Tyrosine Tyr - Y 2.2

9.1

10.1

Tryptophan Trp-W 2.4

9.4

Proline Pro - P 2.0

10.6