Chapter 7 Chemical Quantities

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Transcript Chapter 7 Chemical Quantities

1 Section 3.3

The Mole: A Measurement of Matter  OBJECTIVES: –

Describe how Avogadro’s number is related to a mole of any substance.

2 Section 3.3

The Mole: A Measurement of Matter  OBJECTIVES: –

Calculate the mass of a mole of any substance.

3 What is a Mole?

You can measure mass ,

or volume ,

or you can count pieces .

We measure mass in grams.

We measure volume in liters.

We count pieces in MOLES.

4 Moles (abbreviated: mol) 

Defined as the number of carbon atoms in exactly 12 grams of carbon-12.

1 mole is 6.02 x 10 23 particles.

Treat it like a very large dozen

6.02 x 10 23 number.

is called Avogadro’s

5 Representative particles 

The smallest pieces of a substance.

For a molecular compound: it is the molecule.

For an ionic compound: it is the formula unit.

For an element: it is the atom.

Types of questions 

How many molecules of CO 2 there in 4.56 moles of CO 2 ?

are

How many moles of water is 5.87 x 10 22 molecules?

6 

How many atoms of carbon are there in 1.23 moles of C 6 H 12 O 6 ?

How many moles is 7.78 x 10 24 formula units of MgCl 2 ?

7 Measuring Moles 

Remember relative atomic mass?

The amu was one twelfth the mass of a carbon-12 atom.

Since the mole is the number of atoms in 12 grams of carbon-12,

the decimal number on the periodic table is also the mass of 1 mole of those atoms in grams.

Gram Atomic Mass (gam) 

Equals the mass of 1 mole of an element in grams

12 grams of C has the same number of pieces as 1 gram of H and 56 grams of iron.

We can write this as 12 g C = 1 mole C

8 

We can count things by weighing them.

9 Examples 

How much would 2.34 moles of carbon weigh?

How many moles of magnesium is 24 g of Mg?

How many atoms of lithium is 1.00 g of Li?

How much would 3.45 x 10 22 of U weigh?

atoms

What about compounds?

in 1 mole of H 2 O molecules there are two moles of H atoms and 1 mole of O atoms

To find the mass of one mole of a compound

determine the moles of the elements they have

Find out how much they would weigh

add them up

10

What about compounds?

11 

What is the mass of one mole of CH 4 ?

1 mole of C = 12 g 4 mole of H x 1 g = 4 g 1 mole CH 4 = 12 + 4 = 16 g

The Gram Molecular Mass (gmm) of CH 4 is 16 g

this is the mass of one mole of a molecular compound.

12 Gram Formula Mass (gfm) 

The mass of one mole of an ionic compound.

Calculated the same way as gmm.

What is the GFM of Fe 2 O 3 ?

2 moles of Fe x 56 g = 112 g 3 moles of O x 16 g = 48 g The GFM = 112 g + 48 g = 160 g

13 Section 3.3

Mole-Mass and Mole-Volume Relationships  OBJECTIVES: –

Use the molar mass to convert between mass and moles of a substance.

14 Section 3.3

Mole-Mass and Mole-Volume Relationships  OBJECTIVES: –

Use the mole to convert among measurements of mass, volume, and number of particles.

15 Molar Mass 

Molar mass is the generic term for the mass of one mole of any substance (in grams)

The same as: 1) gram molecular mass, 2) gram formula mass, and 3) gram atomic mass- just a much broader term.

Examples 16 

Calculate the molar mass of the following and tell what type it is:

Na 2 S

N 2 O 4

C

Ca(NO 3 ) 2

C 6 H 12 O 6

(NH 4 ) 3 PO 4

17 Molar Mass 

The number of grams of 1 mole of atoms, ions, or molecules.

We can make conversion factors from these.

To change grams of a compound to moles of a compound.

18 For example 

How many moles is 5.69 g of NaOH?

19 For example 

How many moles is 5.69 g of NaOH?

g  

20 For example 

How many moles is 5.69 g of NaOH?

g   mole

g

  

need to change grams to moles

21 For example 

How many moles is 5.69 g of NaOH?

g   mole

g

  

need to change grams to moles

for NaOH

For example 22 

How many moles is 5.69 g of NaOH?

g   mole

g

  

need to change grams to moles

for NaOH

1mole Na = 23 g 1 mol O = 16 g

1 mole of H = 1 g

For example 

How many moles is 5.69 g of NaOH?

g   mole

g

  

need to change grams to moles

for NaOH

1mole Na = 23 g 1 mol O = 16 g

1 mole of H = 1 g

23 

1 mole NaOH = 40 g

For example 

How many moles is 5.69 g of NaOH?

g   1 mole 40.00

g

  

need to change grams to moles

for NaOH

1mole Na = 23 g 1 mol O = 16 g

1 mole of H = 1 g

24 

1 mole NaOH = 40 g

For example 

How many moles is 5.69 g of NaOH?

g   1 mole 40.00

g

  = 0.142 mol NaOH 

need to change grams to moles

for NaOH

1mole Na = 23 g 1 mol O = 16 g

1 mole of H = 1 g

25 

1 mole NaOH = 40 g

26 Examples 

How many moles is 4.56 g of CO 2 ?

How many grams is 9.87 moles of H 2 O?

How many molecules is 6.8 g of CH 4 ?

49 molecules of C 6 H 12 O 6 how much?

weighs

Gases 27 

Many of the chemicals we deal with are gases.

They are difficult to weigh.

Need to know how many moles of gas we have.

Two things effect the volume of a gas

Temperature and pressure

We need to compare them at the same temperature and pressure.

28 Standard Temperature and Pressure 

0ºC and 1 atm pressure

abbreviated STP

At STP 1 mole of gas occupies 22.4 L

Called the molar volume

1 mole = 22.4 L of any gas at STP

29 Examples 

What is the volume of 4.59 mole of CO 2 gas at STP?

How many moles is 5.67 L of O 2 at STP?

What is the volume of 8.8 g of CH 4 gas at STP?

Density of a gas 

D = m / V

for a gas the units will be g / L

We can determine the density of any gas at STP if we know its formula.

To find the density we need the mass and the volume.

If you assume you have 1 mole, then the mass is the molar mass (from PT)

30 

At STP the volume is 22.4 L.

31 Examples 

Find the density of CO 2 at STP.

Find the density of CH 4 at STP.

The other way 

Given the density, we can find the molar mass of the gas.

Again, pretend you have 1 mole at STP, so V = 22.4 L.

m = D x V

m is the mass of 1 mole, since you have 22.4 L of the stuff.

What is the molar mass of a gas with a density of 1.964 g/L?

32 

2.86 g/L?

Summary 33 

These four items are all equal: a) 1 mole b) molar mass (in grams) c) 6.02 x 10 23 particles representative d) 22.4 L at STP Thus, we can make conversion factors from them.