Transcript Slide 1
INTERNATIONAL ECONOMICS: THEORY, APPLICATION, AND POLICY; Charles van Marrewijk, 2012; 1
Constant returns to scale
K Suppose 5 labor and 15 capital can produce 10 X This is the isoquant associated with point
A
Under constant returns to scale a proportional increase in inputs leads to a proportional increase in output Suppose we increase K and L by 40% K from 15 to 21 and L from 5 to 7 21 15
A B
Then output also increases by 40% from X = 10 to X = 14 Thus, the isoquant at point
B
is X = 14 X = 14 X = 10 0 5 7 L
INTERNATIONAL ECONOMICS: THEORY, APPLICATION, AND POLICY; Charles van Marrewijk, 2012; 2
Constant returns to scale
K
A’
Increasing the inputs at
A
with 40% is equivalent to increasing the length of a line from the origin through
A
with 40% But if A’ is another point on the X=10 isoquant we can use the same procedure to conclude that
B’
must be also
B’
on the X=14 isoquant This procedure can be repeated for
B
any arbitrary point on the X=10 isoquant; here are a few
A
The X = 14 isoquant is a radial blow-up X = 14 X = 10 0 L
INTERNATIONAL ECONOMICS: THEORY, APPLICATION, AND POLICY; Charles van Marrewijk, 2012; 3
Constant returns to scale
K Under constant returns to scale the isoquants are radial blow-ups of each other, which implies that drawing 1 isoquant gives information on all others 21
A
For example, that if cost is minized at point
A
for X = 10, then it is also minimized at the 40% radial blow-up of
A
(
B
) for X = 14
B
Thus, the slope of the isoquant at point
A
is the same as at point
B
15 X = 14 X = 10 0 5 7 L
INTERNATIONAL ECONOMICS: THEORY, APPLICATION, AND POLICY; Charles van Marrewijk, 2012; 4
Constant returns to scale
K Since the isoquants are radial blow-ups of one another and the slope at point
A
is the same as the slope at point
B
cost minimization is simpler.
21
A
If we know the cost minimizing input mix for
one
isoquant and any ratio of w/r, we also know it for any other production level.
B
You only have to multiply the input mix times the output ratio (we frequently use the isoquant X = 1) 15 X = 14 X = 10 0 5 7 L