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Applied Le Chatelieir's Principle Lesson 4 Lab 19A Le Chatelier’s Principle Copy the five Equilibrium Equations into your lab handout Part I Thymol Blue (blue) + H+ ⇌ Thymol Blue (yellow) Part II Fe3+(aq) + SCN-(aq) ⇌ yellow Fe3+(aq) FeSCN2+(aq) brown + 3OH- → Fe(OH)3(s) Part III Co(H2O)62+ + 2Cl- ⇌ Co(H2O)4Cl22- + pink blue 2H2O(l) Part IV Energy + 2CrO42- + 2H+ yellow Ba2+ + CrO42- ⇌ Cr2O72- + orange → H2O(l) BaCrO4(s) Part V Cu(H2O)42+ + 2NH3 ⇌ light blue Cu(OH)2(s) + powder blue Cu(OH)2(s) + 4NH3 ⇌ powder blue Cu(NH3)42+ + 2OHviolet 2NH4+ + 2H2O Application of Le Chatelier’s Principle 2CrO42- + 2H+ yellow Know the following: Energy + ⇄ Cr2O72- + orange H2O(l) Any acid is H+ Any base is OH- Acids react with bases H+ + OH- → H2O(l) Stress Add H+ Add CrO42Add Cr2O72- Shift [CrO42-] [Cr2O72-] colour Application of Le Chatelier’s Principle 2CrO42- + 2H+ yellow Know the following: Energy + ⇄ Cr2O72- + orange H2O(l) Any acid is H+ Any base is OH- Acids react with bases H+ + OH- → H2O(l) Stress Add H+ Add CrO42Add Cr2O72- Shift [CrO42-] [Cr2O72-] colour Application of Le Chatelier’s Principle 2CrO42- + 2H+ yellow Know the following: Energy + ⇄ Cr2O72- + orange H2O(l) Any acid is H+ Any base is OH- Acids react with bases H+ + OH- → H2O(l) Stress Add H+ Add CrO42Add Cr2O72- Shift [CrO42-] [Cr2O72-] colour Application of Le Chatelier’s Principle 2CrO42- + 2H+ yellow Know the following: Energy + ⇄ Cr2O72- + orange H2O(l) Any acid is H+ Any base is OH- Acids react with bases H+ + OH- → H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour Add H+ right decrease increase orange Add CrO42Add Cr2O72- Application of Le Chatelier’s Principle 2CrO42- + 2H+ yellow Know the following: Energy + ⇄ Cr2O72- + orange H2O(l) Any acid is H+ Any base is OH- Acids react with bases H+ + OH- → H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour Add H+ right decrease increase orange Add CrO42- right increase increase ? Add Cr2O72- Application of Le Chatelier’s Principle-1 2CrO42- + 2H+ yellow Know the following: Energy + ⇄ Cr2O72- + orange H2O(l) Any acid is H+ Any base is OH- Acids react with bases H+ + OH- → H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour Add H+ right decrease increase orange Add CrO42- right increase increase ? increases increases ? Add Cr2O72- left Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ yellow ⇄ Cr2O72- + orange H2O(l) Acids react with bases H+ + OH- → H2O(l) Stress Shift [CrO42-] [Cr2O72-] colour Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ yellow ⇄ Cr2O72- + orange H2O(l) Acids react with bases H+ + OH- → H2O(l) Stress Add NaOH Shift [CrO42-] [Cr2O72-] colour Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ yellow ⇄ Cr2O72- + orange H2O(l) Acids react with bases H+ + OH- → H2O(l) NaOH → Stress Shift Add NaOH Na+ + [CrO42-] OH- [Cr2O72-] colour Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ yellow ⇄ Cr2O72- + orange H2O(l) Acids react with bases H+ + OH- → H2O(l) NaOH → Stress Shift Add NaOH Na+ + spectator ion [CrO42-] OHstress ion- lowers H+ [Cr2O72-] colour Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ yellow ⇄ Cr2O72- + orange H2O(l) Acids react with bases H+ + OH- → H2O(l) NaOH → Stress Shift [CrO42-] [Cr2O72-] colour Add NaOH left increases decreases yellow Na+ + spectator ion OHstress ion- lowers H+ Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ yellow ⇄ Cr2O72- + orange H2O(l) BaCrO4 has low solubility BaCr2O7 has high solubility Stress Shift [CrO42-] [Cr2O72-] colour Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ yellow ⇄ Cr2O72- + orange H2O(l) BaCrO4 has low solubility BaCr2O7 has high solubility Stress Ba(NO3)2 Shift [CrO42-] [Cr2O72-] colour Application of Le Chatelier’s Principle-1 Energy + 2CrO42- + 2H+ yellow ⇄ Cr2O72- + orange H2O(l) BaCrO4 has low solubility- Ba2+ reacts with CrO42BaCr2O7 has high solubility- no reaction Ba(NO3)2 → Stress Shift Ba(NO3)2 Ba2+ + [CrO42-] 2NO3[Cr2O72-] colour Application of Le Chatelier’s Principle-1 Energy + ⇄ Cr2O72- + orange + 2NO3spectator [CrO42-] [Cr2O72-] 2CrO42- + 2H+ yellow H2O(l) BaCrO4 has low solubility BaCr2O7 has high solubility Ba(NO3)2 → Stress Shift Ba(NO3)2 Ba2+ stress colour Application of Le Chatelier’s Principle-1 2CrO42- + 2H+ ⇄ Cr2O72- + yellow orange ↓ Ba2+ reacts with this ion BaCrO4 has low solubility BaCr2O7 has high solubility Energy + Ba(NO3)2 → Stress Shift Ba(NO3)2 Ba2+ stress + 2NO3spectator [CrO42-] [Cr2O72-] H2O(l) colour Application of Le Chatelier’s Principle-1 2CrO42- + 2H+ ⇄ Cr2O72- + yellow orange ↓ Ba2+ reacts with this ion BaCrO4 has low solubility BaCr2O7 has high solubility Energy + Ba(NO3)2 → Stress Ba(NO3)2 Ba2+ stress H2O(l) + 2NO3spectator Shift [CrO42-] [Cr2O72-] colour left decreases decreases yellow Application of Le Chatelier’s Principle-1 Energy Stress HCl + 2CrO42- + 2H+ yellow Shift ⇄ [CrO42-] Cr2O72- + orange [Cr2O72-] H2O(l) colour Application of Le Chatelier’s Principle-1 2CrO42- + 2H+ yellow ⇄ Cr2O72- + orange HCl → + Cl- Stress Shift Energy HCl + H+ [CrO42-] [Cr2O72-] H2O(l) colour Application of Le Chatelier’s Principle-1 2CrO42- + 2H+ yellow ⇄ Cr2O72- + orange HCl → + Clspectator Stress Shift [CrO42-] [Cr2O72-] Energy HCl + H+ stress H2O(l) colour Application of Le Chatelier’s Principle-1 2CrO42- + 2H+ yellow ⇄ Cr2O72- + orange HCl → + Clspectator Stress Shift [CrO42-] [Cr2O72-] colour HCl right decreases increases orange Energy + H+ stress H2O(l) Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Clpink Stress HCl stress ion ⇄ spectator ion Co(H2O)4Cl22- + blue shift 2H2O(l) colour Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Clpink HCl → Stress stress ion HCl H+ ⇄ Co(H2O)4Cl22- + blue + Cl- spectator ion shift 2H2O(l) colour Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Clpink HCl → Stress stress ion HCl H+ spectator ⇄ Co(H2O)4Cl22- + blue + Clstress spectator ion shift 2H2O(l) colour Application of Le Chatelier’s Principle- 2 Co(H2O)62+ + 2Clpink HCl → Stress stress ion HCl Cl- ⇄ H+ spectator Co(H2O)4Cl2 + 2H2O(l) blue + spectator ion H+ Clstress shift right colour blue Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Clpink Stress stress ion Increase temperature ⇄ spectator ion Co(H2O)4Cl22- + blue shift 2H2O(l) colour Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Clpink Stress stress ion Increase temperature ⇄ spectator ion Co(H2O)4Cl22- + blue shift 2H2O(l) colour Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Clpink ⇄ Co(H2O)4Cl22- + blue Stress stress ion spectator ion shift ↑ temp none none right 2H2O(l) colour blue Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Clpink Stress AgNO3 stress ion ⇄ spectator ion Co(H2O)4Cl22- + blue shift 2H2O(l) colour Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Clpink AgNO3 → Stress stress ion AgNO3 Ag+ + ⇄ Co(H2O)4Cl22- + blue 2H2O(l) NO3- spectator ion shift colour Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Clpink AgNO3 → Stress stress ion AgNO3 ⇄ Co(H2O)4Cl22- + blue 2H2O(l) Ag+ + NO3↑ stress- low solubility (data book-4) with Clspectator ion shift colour Application of Le Chatelier’s Principle- 2 Energy + Co(H2O)62+ + 2Clpink ⇄ Co(H2O)4Cl22- + blue 2H2O(l) AgNO3 → Stress stress ion spectator ion shift colour AgNO3 Ag+ NO3- left pink Ag+ + NO3↑ stress- low solubility (data book-4) with Cl- Here is a the first question from your lab. I will give you a good answer so that you understand the level of detail that is required in the response 1. Explain the colour changes observed when Fe(NO3)3, KSCN, and NaOH were added to the thiocyanatoiron equilibrium system. Start by writing the equilibrium equation. Fe3+(aq) + SCN-(aq) yellow ⇄ Fe(SCN)2+(aq) brown Adding Fe(NO3)3 increases the [Fe3+] and causes the reaction to shift right and turn brown. Adding KSCN increases the [SCN-] and causes the reaction to shift right and turn brown. Adding NaOH increases the [OH-] which reacts with Fe3+, lowering the [Fe3+] causing the equilibrium to shift left and turn yellow.