Transcript CHAPTER 4

CHAPTER 4
Stoichiometry
Calculations Based on Chemical
Equations

Fe2O3 + 3 CO  2 Fe + 3 CO2
How many CO molecules are required to
react with 25 molecules of Fe2O3?
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Calculations Based on Chemical
Equations
What mass of CO is required to react with
146 g of iron (III) oxide?

Fe2O3 + 3 CO 
 2 Fe + 3 CO2
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Calculations Based on Chemical
Equations
What mass of carbon dioxide can be
produced by the reaction of 0.540 mole of
iron (III) oxide with carbon monoxide?

Fe2 O3 + 3 CO 

 2 Fe + 3 CO2
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Calculations Based on Chemical
Equations
How many iron atoms can be produced by
the reaction of 2.50 x 105 molecules of
iron (III) oxide with excess carbon
monoxide?

Fe2O3 + 3 CO  2 Fe + 3 CO2
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Calculations Based on Chemical
Equations
What mass of iron (III) oxide reacted with
carbon monoxide if the carbon dioxide
produced by the reaction had a mass of
8.65 grams?

Fe2O3 + 3 CO 
 2 Fe + 3 CO2
You do it!
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Limiting Reactant Concept
The reagent consumed first is the limiting
reactant (or limited reagent)
– -A chemical reaction proceeds forward according
to the stoichiometry of the reaction until one (or
both) reactants are consumed
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Limiting Reactant Concept
• Kitchen example of limiting
reactant concept:
1 packet of muffin mix + 2 eggs + 1 cup of milk
 makes 12 muffins
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Limiting Reactant Concept
1 packet of muffin mix + 2 eggs + 1 cup of milk
12 muffins
• Mix Packets
1
2
3
4
5
6
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Eggs
Milk
1 dozen
1 gallon
limited by the muffin mix
1 dozen
1 gallon
1 dozen
1 gallon
1 dozen
1 gallon
1 dozen
1 gallon
1 dozen
1 gallon
1 dozen
1 gallon
limited by the amount of eggs
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Limiting Reactant Concept
Suppose a box contains 87 bolts, 110
washers, and 99 nuts. How many sets,
each consisting of one bolt, two washers,
and one nut, can you construct from the
contents of one box?
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Limiting Reactant Concept
How much sulfur dioxide can be produced
by the reaction of 95.6 g of carbon
disulfide with 1.10 x102 g of oxygen?
CS2  3 O2  CO 2  2 SO 2
1 mol
3 mol
1 mol
2 mol
• Which is limiting reactant?
• What is maximum mass of sulfur dioxide that can be
produced?
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Percent Yield
Theoretical yield is calculated by assuming that
the reaction goes to completion
– -Determined from a limiting reactant calculation
Actual yield is the amount of a specified pure
product made from the reactants
– -In the laboratory, this is the amount of product
that is formed in your beaker, after it is purified
and dried
Percent yield indicates how much of the product
is obtained from the reaction
actual yield
% yield =
 100%
theoretical yield
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Percent Yield
A 10.0 g sample of ethanol, C2H5OH, was
boiled with excess acetic acid,
CH3COOH, to produce 14.8 g of ethyl
acetate, CH3COOC2H5. What is the
percent yield?
CH 3COOH + C2 H 5OH  CH 3COOC2 H 5  H 2O
1. Calculate the theoretical yield
•
2. Calculate the percent yield
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Types of Solutions
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Concentrations of Solutions
• Common unit of concentration:
g solute
number of molesof solut e
MW solute
molarit y
=
number of lit ersof solut ion liters solution
moles
M 
L
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Solution Preparation
Making a 1 M solution of sodium chloride
Then add addition
water until
the 1.0 L mark is
reached
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Concentrations of Solutions
• Calculate the molarity of a solution that
contains 12.5 g of sulfuric acid in 1.75 L
of solution.
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Concentrations of Solutions
• Determine the mass of calcium nitrate
required to prepare 3.50 L of 0.800 M
Ca(NO3)2 .
You do it!
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Diluting a Solution
A known amount of solvent is added to a known
concentration and known amount of solution
• -number of moles of solute in the two solutions
(concentrated and dilute) remains constant
• -mathematical relationship:
•
M1V1 = M2V2
• -Note: appropriate for dilutions, but not for
chemical reactions
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Diluting a Solution
• If 10.0 mL of 12.0 M HCl is added to
enough water to give 100. mL of
solution, what is the concentration of
the solution?
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Diluting a Solution
• What volume of 18.0 M sulfuric acid is
required to make 2.50 L of a 2.40 M
sulfuric acid solution?
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Solutions in Chemical Reactions
• -chemical reactions are most often
performed by using solutions of the
reactants
• -Combine the concepts of molarity and
stoichiometry
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Solutions in Chemical Reactions
• What volume of 0.500 M BaCl2 is
required to completely react with 4.32 g
of Na2SO4?
Na 2SO 4 + BaCl2  BaSO 4 + 2 NaCl
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Solutions in Chemical Reactions
• What volume of 0.200 M NaOH will
react with 50.0 mL 0f 0.200 M
aluminum nitrate, Al(NO3)3?
AlNO3 3  3 NaOH  AlOH3  3 NaNO3
You do it!
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Titrations
A method of determining the concentration of an
unknown solution by reacting it with a known
amount and concentration of a standard
solution
Standard solution: solution whose concentration has
been determined using a primary standard by
standardization
Primary standard: chemical compound which can be
used to accurately determine the concentration of
another solution
 Examples: include KHP and sodium carbonate
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Primary Standard
• Potassium hydrogen phthalate (KHP)
– molar mass of 204.2 g/mol.
O
CH
HC
O
CH
C
C
OH
+
HC
C
CH
O
C
C
HC
C
O -K+
HC
C
O
KOH
CH
OH
+
H2O
C
OH
acidic H
KHP
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Titrations
Standardization: process in which the concentration of
the standard solution is determined from the primary
standard
Indicator: substance that exists in different forms with
different colors depending on the concentration of
the H+ in solution
Examples: phenolphthalein and bromothymol blue.
Equivalence point: point at which stoichiometrically
equivalent amounts of the acid (H+) and base (OH-)
have reacted
End point: point at which the indicator changes color27
and the titration is complete
Titration
• Calculate the molarity of a NaOH solution if
27.3 mL of it reacts with 0.4084 g of KHP.
NaOH + KHP  NaKP + H 2 O
1 mol KHP
? mol+NaOH
= 0.4084 g
KHP

KHP
1 mol
KHP(aq)
NaOH(aq)
NaKP(aq)
+
? mol NaOH = 0.4084 g KHP

204.2g KHP H2O(l)
204.2 g KHP
1 mol NaOH
 0.00200 mol NaOH
1
mol
NaOH
1 mol KHP
 0.00200 mol NaOH
1 mol
0.00200
mol KHP
NaOH
? M NaOH =
 0.0733 M NaOH
0.0273 L NaOH
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Titrations
• What is the molarity of a KOH solution if
38.7 mL of the KOH solution is required
to react with 43.2 mL of 0.223 M HCl?
KOH(aq) + HCl(aq)
H2O(l) + KCl(aq)
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Titrations
• What is the molarity of a barium
hydroxide solution if 44.1 mL of 0.103
M HCl is required to react with 38.3 mL
of the Ba(OH)2 solution?
Ba(OH)2 + 2 HCl  BaCl2 + 2 H2O
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Titrations On Your Own
• Calculate the molarity of a sulfuric
acid solution if 23.2 mL of it reacts
with 0.212 g of Na2CO3.
H2SO4(aq) + Na2CO3(aq)  Na2SO4(aq) + H2O(l) + CO2(g)
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Transmittance and Absorption
Spectrum
Transmittance (T): ratio of the amount of
light that passes through a sample relative to
the initial amount of light entering the sample
Absorbance (A) = -log T = -log (P/Po)
Beer-Lambert Law (Beer’s Law):
A = ebc
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