Transcript Slide 1

CHOOSE YOUR
DISTRIBUTION
Binomial/Poisson/Normal
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1. A typist makes on average 2 mistakes per page. What is
the probability of a particular page having no errors on it?
2. The temperature my Kettle ‘boils’ water to have a mean
of 960C with standard deviation of 50c. What is the chance
of it ‘boiling’ water to less than 900C
3. A computer crashes once every 2 days on average. What
is the probability of there being 2 crashes in one week?
4. Components are packed in boxes of 20. The probability
of a component being defective is 0.1. What is the
probability of a box containing 2 defective components?
answers
1 A typist makes on average 2 mistakes per page. What is the
probability of a particular page having no errors on it?
We have an average rate here: lambda = 2 errors per page. We don't
have an exact probability (e.g. something like "there is a probability of
1/2 that a page contains errors"). Hence, Poisson distribution.
(lambda t) = 2.
Hence P(0) = 20 e(-2) /0! = 0.135.
or P.p.d x = 0 mean=2
 3 A computer crashes once every 2 days on average. What is the
probability of there being 2 crashes in one week?
Again, average rate given: lambda = 0.5 crashes/day.
Hence, Poisson. (lambda t) = (0.5 per day x 7 days) = 3.5/week & n = 2.
P(2) = 3.52 e(-3.5) /2! = 0.185.
or P.p.d x = 2 mean=3.5
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answers
2 The temperature my Kettle ‘boils’ water to, has a mean of
960C with standard deviation of 50c. What is the chance of it
‘boiling’ water to less than 900C.
z= (90-96)/5 =-1.2 (look up on table)
gives 0.3849, subtract from 0.5
P(x<90) = 0.1151
Or N.c.d: lower = -99999, upper = 90, σ= 5, μ=96
 4 Components are packed in boxes of 20. The probability of
a component being defective is 0.1. What is the probability of
a box containing 2 defective components?
Here we are given a definite probability, in this case, of defective
components, p = 0.1 and hence q = 0.9 = Prob. not defective.
Hence, Binomial, with n = 20. faulty
So P(2) = 20C2q18 p2 = 0.285
or B.p.d: n= 20 p=0.1 x=2
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Binomial/Poisson/Normal
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5. ICs are packaged in boxes of 10. The probability of an
ic being faulty is 2%. What is the probability of a box
containing 2 faulty ics?
6. The mean number of faults in a new house is 8. What is
the probability of buying a new house with exactly 1 fault?
7. A box contains a large number of washers; there are
twice as many steel washers as brass ones. Four washers are
selected at random from the box. What is the probability
that 0, 1, 2, 3, 4 are brass?
8. Washers are produce with weights that are distributed
with parameters mean = 4g and standard deviation = .5g.
What is the probability of a washer weighing more than
3g?
answers
5 The probability of an ic being faulty is 2%. What is the
probability of a box containing 2 faulty ics?
We have a probability of something being true or the same thing not
being true; in this case, an ic being faulty. Hence, Binomial distribution.
p = P(faulty) = 0.02, q = P(not faulty) = 0.98. n = 10. x=2
So, Prob of a box containing 2 faulty ics P(2) = 10C2 q8p2 = 0.015.
Or B.p.d n=10, p=0.02, x =2
 6 The mean number of faults in a new house is 8. What is the
probability of buying a new house with exactly 1 fault?
Here we have an average rate of faults occurring: 8 per house. Hence,
Poisson, with (lambda t) = (8 faults/house * 1 house) = 8.
n = 1 too, so P1 = 81e (-8) /1!= 0.0027.
Or P.p.d mean = 8, x = 1
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7 A box contains a large number of washers; there are twice as many
steel washers as brass ones. Four washers are selected at random from
the box. What is the probability that 0, 1, 2, 3, 4 are brass?
Here too we have a probability of brass (1/3) and of not brass --- i.e. steel --which is 2/3. Hence, use the Binomial distribution with p = 1/3 , q = 2/3
and n = 4. Use formulae for each x value
No. of brass so P(0) = 0.197, P(1) = 0.395, P(2) = 0.296, P(3) = 0.099 and
P(4) = 0.012.
or B.c.d n=4, p = 1/3, x=0, 1, 2, 3, 4
 8. Washers are produce with weights that are distributed with
parameters mean = 4g and standard deviation = .5g. What is the
probability of a washer weighing more than 3g?
z=3-4/0.5=-2
gives 0.4772 (add 0.5)
P(x>3) =0.9772
Or N.c.d lower = 3, upper = 999999, σ= 0.5, μ=4
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Typical Questions
Typical questions
1 A shop sells biscuits that are said to contain on average
5 chocolate chips each.
a What is the probability that a biscuits contains 4
chocolate chips?
b What percentage of biscuits would you expect to
contain less than 3 chocolate chips?
c Find the probability that half a biscuits contains exactly
2 chocolate chips.
d Another type of biscuit is found to have no chocolate
chips 5% of the time. What is the average number of
chips per biscuit?
A factory produces tyres. 5% of the tyres produced are
rejected because of defects.
Find the probability that in a batch of 10 tyres:
a none are defective;
b less than 2 are defective.
c at least 3 are defective
d Another company has studied the amount of defective
tyre per 10 tyre batch. They found that 88% of the
time they have a batch with no defects. What is the
chance that an individual tyre has a defect.
A multi-choice test has 10 questions with 4 options
for each. If I guess every answers, find the chance
of
A) getting them all wrong
B) getting at least 1 correct
C) passing (50% or more)
D) A teacher wants to set a test similar to the above
one that has a less than 0.5% chance of a student
guessing and getting all questions correct. What is
the least number of questions needed
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A test has a mean of 60% with a standard
deviation of 12%. Find the chance of:
A) scoring less than 30%
B) passing the test
What would you need to score above to
C) Put yourself in the top 20%
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I get sick 2.8 times per year, on average. Find the
probability of:
A) me not getting sick this year
B) getting sick this month
Another person finds they get sick at least once in a
year 65% of the time
C) How many times do they get sick per year.
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