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Lecture 17 Introduction into Electrophysiology Approaches to the Nernst eqn What is driving force for an ion moving across the membrane? The Goldman eqn Components of excitable membranes and their role in spike generation (Reading: chapters 11 and 23) Equilibrium (reversal) potential #2 #1 K+ Cl#3 K+ Cl- K+ Cl- equilibrium + + + K K - + Cl- - + Cl- At 37oC: let K+ cross cin e cout Cl- z kT (Boltzmann) (Nernst) RT cin ln zF cout 61.5 cin log (mV) z cout Erev K+ The distribution of charged particles in two wells separated by an electric potential difference G cin e kT cout G ze ze cin e kT cout Boltzmann Work of transfer of a charge across a gap or per mole: cin zF RT ln cout energy differences: zF cin e RT cout electric chemical Why logarithmic? nRT P V PV nRT 1 dG PdV nRT dV V V2 V2 G PdV nRT V1 V1 normalizing to the volume c2 V1 c1 V2 dV 1 dV nRT ln V2 ln V1 V V2 V1 nRT ln nRT ln V1 V2 c = n/V c2 RT ln c1 What is driving force? E (mV) K+ Cl- K+ Cl- K+ ClI K g K ( E EK ) I K+ Cl- I driving force V EK = 0 V EK < 0 But there are several types of ions inside and outside the cell, and each of them has its own reversal potential. Hmmm. How do they contribute to the effective membrane potential that is measured by a micro-electrode? The exact value of Em is given by Goldman eqn. _ K+ Na+ Cl- R1 K+ Na+ Cl- R2 _ + pK [K ]in pNa [ Na ]in pCl [Cl ]out RT ln F pK [K ]out pNa [ Na ]out pCl [Cl ]in Emem + Goldman eqn describes not an equilibrium, but a steady-state, thus pumps are required to maintain it. Bi-ionic system is described by Goldman eqn in its short form: K+ pK K+ pNa Na+ Na+ Emem 61.5 log [K ]in [K ]out p Na pK p Na pK [ Na ]in [ Na ]out (mV) Em = -70 mV Erev [K+]in = 150 mM [K+]out = 5 mM -90 mV [Na+]in = 15 [Na+]out = 150 +60 [Cl-]in = 9 [Cl-]out = 125 -70 [Ca2+]in = 10-4 [Ca2+]out = 2 +129 Conventions: Membrane potential is always measured “INSIDE” vs. “OUTSIDE” depolarization Erest= -70 mV hyperpolarization Action Potentials from B. Hille, Ion Channels of Excitable Membranes in Na+ pK +40 mV time K+ pNa spike K+ ENa=+60 mV out Na+ Erest=-70 mV EK = -90 mV Emem 61.5 log [K ]in [K ]out p Na pK p Na pK [ Na ]in [ Na ]out (mV) 8-12 The peak of K+ current coincides with the falling phase of the action potential What is necessary for spike generation? 3. Fast V-gated Na+ channels Na+ 4. Delayed V-gated K+ channels K+ 2K+ 3Na+ 1. Na/K pump K+ 2. Leakage K+ channel K+ Na+ +30 -70 K+ Na+ Rf Patch-clamp circuit stimulus voltage-gated channels Em +10 threshold = -50 -70 pore domain Fast Na+ channel C voltage sensor 4 subunits form a channel O refractory period I Delayed K+ channel Number of closed states n = 3-7 C1 C2 Cn O I Passage through several nonconductive states provides the delay for activation Ensemble response is the sum of multiple small stochastic currents of single channels from B. Hille, Ion Channels of Excitable Membranes Structure of V-gated channel with the inactivation gate The voltage sensors are not shown Inactivation of a K+ channel mutant without the inactivation gate can be rescued with a synthetic peptide