Transcript Document

Arithmetic Sequences and Series
An introduction…………
1, 4, 7, 10, 13
35
2, 4, 8, 16, 32
9, 1,  7,  15
6.2, 6.6, 7, 7.4
,   3,   6
12
9,  3, 1,  1/ 3
20 / 3
1, 1/ 4, 1/16, 1/ 64 85 / 64
, 2.5, 6.25
9.75
27.2
3  9
62
Arithmetic Sequences
Geometric Sequences
ADD
To get next term
MULTIPLY
To get next term
Arithmetic Series
Sum of Terms
Geometric Series
Sum of Terms
Find the next four terms of –9, -2, 5, …
Arithmetic Sequence
2  9  5  2  7
7 is referred to as the common difference (d)
Common Difference (d) – what we ADD to get next term
Next four terms……12, 19, 26, 33
Find the next four terms of 0, 7, 14, …
Arithmetic Sequence, d = 7
21, 28, 35, 42
Find the next four terms of x, 2x, 3x, …
Arithmetic Sequence, d = x
4x, 5x, 6x, 7x
Find the next four terms of 5k, -k, -7k, …
Arithmetic Sequence, d = -6k
-13k, -19k, -25k, -32k
Vocabulary of Sequences (Universal)
a1  First term
an  nth term
n  number of terms
Sn  sum of n terms
d  common difference
nth term of arithmetic sequence  an  a1  n  1 d
sum of n terms of arithmetic sequence  Sn 
n
 a1  an 
2
Given an arithmetic sequence with a15  38 and d  3, find a1.
x
a1  First term
38
an  nth term
15
n  number of terms
NA Sn  sum of n terms
-3
d  common difference
an  a1  n  1 d
38  x  15  1 3 
X = 80
Find S63 of  19,  13, 7,...
-19 a1  First term
353
??
an  nth term
n  number of terms
63
x
Sn  sum of n terms
6
d  common difference
an  a1  n  1 d
??  19   63  1 6 
??  353
n
 a1  an 
2
63

 19  353 
2
Sn 
S63
S63  10521
Try this one: Find a16 if a1  1.5 and d  0.5
1.5 a1  First term
x
16
an  nth term
n  number of terms
NA Sn  sum of n terms
0.5
d  common difference
an  a1  n  1 d
a16  1.5  16  1 0.5
a16  9
Find n if an  633, a1  9, and d  24
9
a1  First term
633 an  nth term
x
n  number of terms
NA Sn  sum of n terms
24
d  common difference
an  a1  n  1 d
633  9   x  1 24
633  9  24x  24
X = 27
The sum of the first n terms of an infinite sequence
is called the nth partial sum.
Sn  n (a1  an)
2
Example 6. Find the 150th partial sum of the arithmetic sequence, 5,
16, 27, 38, 49, …
a1  5
d  11
 c  5 11  6
an  11n  6  a150  11150  6  1644
S150
150

 5  1644   75 1649   123,675
2
Example 7. An auditorium has 20 rows of seats. There are 20 seats in
the first row, 21 seats in the second row, 22 seats in the third row, and
so on. How many seats are there in all 20 rows?
d 1
c  20  1  19
an  a1   n 1 d  a20  20 19 1  39
20
S 20   20  39   10  59   590
2
Example 8. A small business sells $10,000 worth of sports memorabilia
during its first year. The owner of the business has set a goal of
increasing annual sales by $7500 each year for 19 years. Assuming that
the goal is met, find the total sales during the first 20 years this business
is in operation.
a1  10,000
d  7500
c  10,000  7500  2500
an  a1   n 1 d  a20  10,000 19  7500  152,500
20
S20  10,000  152,500   10 162,500   1,625,000
2
So the total sales for the first 2o years is $1,625,000
Geometric Sequences and Series
Start 04/21/2014
1, 4, 7, 10, 13
35
2, 4, 8, 16, 32
9, 1,  7,  15
6.2, 6.6, 7, 7.4
,   3,   6
12
9,  3, 1,  1/ 3
20 / 3
1, 1/ 4, 1/16, 1/ 64 85 / 64
, 2.5, 6.25
9.75
27.2
3  9
62
Arithmetic Sequences
Geometric Sequences
ADD
To get next term
MULTIPLY
To get next term
Arithmetic Series
Sum of Terms
Geometric Series
Sum of Terms
Vocabulary of Sequences (Universal)
a1  First term
an  nth term
n  number of terms
Sn  sum of n terms
r  common ratio
nth term of geometric sequence  an  a1r n1


a1 r n  1 

sum of n terms of geometric sequence  Sn  
r 1
Find the next three terms of 2, 3, 9/2, ___, ___, ___
3 – 2 vs. 9/2 – 3… not arithmetic
3 9/2
3

 1.5  geometric  r 
2
3
2
9 9 3 9 3 3 9 3 3 3
2, 3, ,  ,   ,   
2 2 2 2 2 2 2 2 2 2
9 27 81 243
2, 3, ,
, ,
2 4 8 16
If a1 
1
2
, r  , find a9 .
2
3
a1  First term
1/2
an  nth term
x
n  number of terms
9
Sn  sum of n terms
NA
r  common ratio
2/3
an  a1r n1
 1  2 
x    
 2  3 
9 1
28
27
128
x

8 
8
23
3
6561