Transcript Slide 1

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Synthesis – 1 product
Decomposition – 1 reactant
Single displacement – 1 element & 1
compound react to produce a different
element & a different compound
Double displacement – 2 compounds react
to form two different compounds.
Neutralization – acid and base in the
reactants & water as one of the products.
Combustion – O2 as a reactant & CO2 and
H2O as the products.
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Does your reaction have two (or more)
substances combining to form one
compound? If yes, then it's a synthesis
reaction.
2 H2(g) + O2(g)  2 H2O(l)
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Na(s) + Cl2(g)  NaCl(s)
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Does your reaction have one compound
breaking down to make two or more smaller
substances? If yes, then it's a decomposition
reaction.
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2 HgO(l)  2 Hg(l) + O2(g)
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NaHCO3(s)Na2CO3(s)+ H2O(l) + CO2(g)
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Does your reaction start with a compound
and an element and produce a different
compound and a different element? If yes,
then it's a single displacement reaction .
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CuCl2(aq) + Mg(s)  MgCl2(aq) + Cu(s)
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KCl(aq) + F2(g)  KF(aq) + Cl2(g)
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A double displacement reaction starts with
two compounds and makes two new
compounds.
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FeCl3(aq)+MgSO4(aq)Fe2(SO4)3(s)+MgCl2(aq)
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NaCl(aq) + AgNO3(aq)  NaNO3(aq) + AgCl(s)
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Does your reaction have an acid as one of
your reactants and water as one of the
products? If yes, then it's an acid-base or
neutralization reaction.
HCl(aq) + NaOH(aq)  NaCl(aq) + H2O(l)
acid
base
Ca(OH)2(aq) + H3PO4(aq)  H2O(l) +
Ca3(PO4)2(aq)
base
acid
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Does your reaction have oxygen as one of it's
reactants and carbon dioxide and water as
products? If yes, then it's a combustion
reaction.
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CH4(g) + O2(g)  CO2(g) + H2O(g)
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C8H18(g) + O2(g)  CO2(g) + H2O(g)
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To predict the products for any equation, you
must first determine the type of reaction by
looking at the reactants.
Synthesis – 1 product
Decomposition – 1 reactant
Combustion – O2 as a reactant & CO2 and H2O
as the products.
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2 or more reactants and you’re told that
there’s only one product = synthesis
When writing the products, you must look at
the charges of the ions. The equations will
most likely not be balanced!
Example: Al(s) + Br2(l) 
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Example: Ca(s) + N2(g) 
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1 reactant = decomposition (if you have a
decomposition, then it will be a compound
splitting up into its elements)
Remember the “7” diatomic molecules and to
write them with a “2” if by themselves.
Example: CCl4(l) 
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Example: Mg3N2(s) 
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hydrocarbon (compound with C & H) + O2 =
combustion (always have CO2 and H2O as
your products)
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Example: CH4(g) + O2(g) 
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Example: C3H8O(g) + O2(g) 
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C8H18 + O2 
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Ba(NO3)2 
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Mg + O2
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Single displacement – 1 element & 1
compound react to produce a different
element & a different compound
Double displacement – 2 compounds react to
form two different compounds.
Neutralization – acid and base in the
reactants & water as one of the products.
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1 element & 1 compound = single
displacement (replacement)
In the products, you can’t have two positive
ions or two negative ions combined together,
only one positive and one negative ion.
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Example: Mg(s) + Zn(NO3)2(aq) 
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Example: Cl2(g) + KF(aq) 
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2 ionic compounds = double displacement
(replacement). As before, you can’t put two
positive ions or two negative ions together.
Example:
AgNO3(aq) + NaCl(aq) 
Example:
Fe2(SO4)3(aq)+ Na3PO4
(aq)
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1 acid (starts with H) & 1 base (ends with
OH) = acid-base or neutralization
(always makes H2O as one product)
Water gets rid of all hydrogen and
hydroxide ions. The other compound
comes from the leftover ions.
Example: HCl(aq) + KOH(aq) 
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Example: Ca(OH)2(aq)+ H2SO4(aq)
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If a substance is an aqueous solution (aq), it
is a substance that dissolves in water, or is
soluble in water.
If a substance is insoluble, it will not dissolve
in water, and when formed as the result of a
reaction will appear as a precipitate (solid).
If a substance is slightly soluble or partially
soluble in water, only a small portion of that
substance will dissolve in water.
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Electrolyte – solution that that has the ability
to conduct electricity.
When an ionic compound dissolves in water it
separates into ions and is called a strong
electrolyte, for example NaCl dissolved in
water.
Compounds that dissolve in water but do not
conduct electricity are called nonelectrolytes,
for example, sugar dissolving in water.
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In order for a
compound to be an
aqueous solution, one
of the ions (either the
positive ion or the
negative ion) must be
soluble in water, but
not both
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Ca(NO3)2
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CuOH
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CaCl2
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(NH4)2SO4
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Zn3(PO4)2
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SrO
FeCO3
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In all precipitation reactions, the ions of one
substance are exchanged with the ions of
another substance when their aqueous
solutions are mixed
At least one of the products formed is
insoluble in water
KI(aq) + AgNO3(aq)  KNO3(aq) + AgIs
K+
Ag+
K+
Ag
I-
NO3-
NO3-
I
Here is what we’ve already covered
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Determine what ions each aqueous reactant
has
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Exchange Ions
◦ (+) ion from one reactant with (-) ion from other
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Balance Charges of combined ions to get
formula of each product
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Determine Solubility of Each Product in
Water
◦ solubility rules/table
◦ if any of the products are insoluble or
slightly soluble, a precipitate will form
◦ If all substances formed are aqueous
solutions then no precipitate will form and
there is really no reaction, just ions floating
around in water.
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Predict the products given each of the
following reactants. Also denote which
compound forms a precipitate:
Cu(NO3)2(aq) + KOH(aq) 
FeCl3(aq) + Mg3(PO4)2(aq) 
NaBr(aq) + KNO3(aq) 
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Equations which describe the chemicals in
aqueous solution and their product molecules
are called molecular equations
KCl(aq) + AgNO3(aq)  KNO3(aq) + AgCl(s)
equations which describe the actual ions and
molecules in the solutions as well as the
molecules of solid, liquid and gas not dissolved
are called ionic equations
K+(aq)+Cl-(aq)+Ag+(aq)+NO3-(aq)K+(aq)+NO3-(aq)+AgCl(s)
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ions that are both reactants and products are
called spectator ions
K+(aq)+Cl-(aq)+Ag+(aq)+NO3-(aq)K+(aq) + NO3- (aq) + AgCl(s)
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an ionic equation in which the spectator ions
are dropped is called a net ionic equation
Cl- (aq) + Ag+ (aq) AgCl(s)
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Write the molecular, complete ionic and
net ionic equations for the following
equations. Also identify any spectator
ions :
Cu(NO3)2(aq) + KOH(aq)  KNO3(aq) + Cu(OH)2(s)
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Write the molecular, complete ionic and net
ionic equations for the following equations.
Also identify any spectator ions :
Fe2(SO4)3(aq)+Pb(ClO3)2(aq)Fe(ClO3)3(aq)+PbSO4(s)
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Write the molecular, complete ionic
and net ionic equations for the
following equations. Also identify
any spectator ions :
KCl(aq) + (NH4)2SO4(aq)  K2SO4(aq) + NH4Cl(aq)