Transcript Division into Cases and the Quotient
Discrete Structures
Chapter 4: Elementary Number Theory and Methods of Proof 4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem
Be especially critical of any statement following the word “obviously”. – Anna Pell Wheeler, 1883-1966
4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 1
Theorem 4.4.1 – The Quotient Remainder Theorem
Given any integer
n
and positive integer
d
, unique integers
q
and
r
s.t.
n
=
dq
+
r
and 0
r
<
d
4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 2
Definitions
• Given an integer
n
and a positive integer
d
,
n div d
= the integer quotient obtained when
n
divided by
d
.
is
n mod d
= the nonnegative integer remainder obtained when
n
is divided by
d
.
Symbolically, if
n
and
d
are integers and
d
> 0, then
n div d
=
q
and
n mod d
=
r
n = dq
+
r
Where
q
and
r
are integers and 0
r
<
d
.
4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 3
Example – pg. 189 # 8 & 9
• Evaluate the expressions.
8. a. 50
div
7 b. 50
mod
7 9. a. 28
div
5 b. 28
mod
5 4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 4
Theorems
•
Theorem 4.4.2 – The Parity Property
Any two consecutive integers have opposite parity.
•
Theorem 4.4.3
The square of any odd integer has the form 8
m
+ 1 for some integer
m.
4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 5
Definition
• For any real number
x
, the
absolute value of
x
, is denoted |
x
|, is defined as follows:
x
x x
if
x
if
x
0 0 4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 6
Lemmas
•
Lemma 4.4.4
For all real numbers
r
, -|
r
|
r
|
r
| •
Lemma 4.4.5
For all real numbers
r
, |-
r
| = |
r
| •
Lemma 4.4.6 – The Triangle Inequality
For all real numbers
x
and
y
, |
x
+
y
| |
x| +
|
y
| 4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 7
Example – pg. 189 # 24
• Prove that for all integers
m
and
n
, if
m mod
5 = 2 and
n mod
5 = 1, then
mn mod
5 = 2.
4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 8
Example – pg. 190 #36
• Prove the following statement.
The product of any four consecutive integers is divisible by 8.
4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 9
Example – pg. 190 #42
• Prove the following statement.
Every prime number except 2 and 3 has the form 6
q
+ 1 or 6
q
+ 5 for some integer
q
.
4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 10
Example – pg. 190 #45
• Prove the following statement.
For all real numbers
r c
r
c
, then |
r
|
c
.
and
c
with
c
0, if 4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 11
Example – pg. 190 # 49
• If
m
,
n
, and
d
are integers,
d
> 0, and
m mod d
that =
n mod d
, does it necessarily follow
m = n
? That
m
–
n
is divisible by
d
? Prove your answers.
4.4 Direct Proof and Counter Example IV: Division into Cases and the Quotient Remainder Theorem 12