5.4 Medians and Altitudes

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Transcript 5.4 Medians and Altitudes

5.4 Medians and Altitudes

Say what?????

Vocabulary…

Concurrent- 3 or more lines, rays, or segments that intersect at the same point  Median of a Triangle – a segment from a vertex to the midpoint of the opposite side  Centroid – point of concurrency of 3 medians  Altitude of a Triangle – the perpendicular segment from a vertex to the opposite side or to the line that contains the opposite side – there are 3 in a

Orthocenter - the point where the 3 altitudes of a intersect 

Theorem 5.8: Concurrency of Medians of a

-the medians of a intersect at a point that is 2/3 the distance from each vertex to the midpoint of the opposite side.

Theorem 5.9: Concurrency of Altitudes of a

-the lines containing the altitudes of a are concurrent

In

RST

,

Q

is the centroid and

SQ

= 8

. Find

QW SW

.

and

SQ

= 2 3

SW

8 = 2 3

SW

Concurrency of Medians of a Triangle Theorem Substitute

8

for

SQ

.

12 =

SW

Multiply each side by the reciprocal, .

2

Then

QW

=

SW – SQ =

12 – 8 = 4.

So,

QW

= 4

and

SW =

12

.

With a partner, do #’s 1-2 on p.278

With a partner, do #’s 3-4 on p.279

 Practice

In Exercises

1–3,

use the diagram.

G

is the centroid of

ABC

.

1.

If

BG

= 9,

find

BF

.

ANSWER

13.5

2.

If

BD

= 12,

find

AD

.

ANSWER

12

3.

If

CD

= 27,

find

GC

.

ANSWER

18

 Find the orthocenter.

Find the orthocenter

P

in an acute, a right, and an obtuse triangle. (Draw 3 altitudes…drop perpendicular lines from vertex to opposite side.) SOLUTION Acute triangle Right triangle Obtuse triangle

P

is inside triangle.

P

is on triangle.

P

is outside triangle.

Can you answer these??????

  Look at the and answer the following: 1. Is BD a median of ABC?

 2. Is BD an altitude ABC?

 3. Is BD a perpendicular bisector?

B B   A D C A D C