Chapter 7 Lesson 4 - Mrs.Lemons Geometry

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Transcript Chapter 7 Lesson 4 - Mrs.Lemons Geometry

Chapter 7 Lesson 4

Objective: To find the areas of rhombuses and kites.

Theorem 7-11

: Area of a Rhombus or a Kite The area of a rhombus or a kite is half the product of the lengths of its diagonals.

A

 1 2

d

1

d

2

d 2 d 1 Rhombuses and kites have perpendicular diagonals.

Example 1:

Finding the Area of a Kite

Find the area of kite KLMN. KM=2+5=7 LN=3+3=6

A A

  1 2 2 1

d

1

d

2 ( 7 )( 6 )

A

 1 2 ( 42 )

A

 21

m

2 L K 2m 3m 3m N 5m M

Example 2:

Finding the Area of a Kite

Find the area of kite KLMN. KM=1+4=5 LN=3+3=6

A A

  1 2 2 1

d

1

d

2 ( 5 )( 6 )

A

 1 2 ( 30 )

A

 15

m

2 L K 1m 3m 3m N 4m M

Example 3:

Finding the Area of a Kite

Find the area of kite with diagonals that are 12 in. and 9 in. long.

A A

  1 2 2 1

d

1

d

2 ( 12 )( 9 )

A

 1 2 ( 108 )

A

 54

m

2

The diagonals of a rhombus bisect each other.

Example 4:

Finding the Area of a Rhombus

B 15m Find the area of rhombus ABCD.

∆BEC is a right triangle. Use the Pythagorean Theorem to find BE.

A E 12m

a

12 2 2 144

b

   2

b b

2 2

b

 2    81

c

2 15 2 225

b

2

b

  9 81

AC

=12+12=

24 BD

=9+9=

18

A A A

   1 2 1 2 2 ( 18 )( 24 ) ( 2 432 )

A

 216m 2 D C

Example 5:

Finding the Area of a Rhombus

B Find the area of rhombus ABCD.

∆BEC is a right triangle. Use the Pythagorean Theorem to find BE.

a

12 2 2 144

b

   2

b b b

 2 2 2    25

c

2 13 2 169

b b

2   5 25

AC

=12+12=

24 BD

=5+5=

10

A A A

   1 2 1 2 2 ( 10 )( 24 ) ( 2 240 )

A

 A 120m 2 24m 12m E D 12m 13m C

Assignment pg. 376 - 378 #14-20;23;28-38