Transcript Document
CH 7 - Open Channel Flow
Brays Bayou
1. Uniform & Steady
2. Non-uniform and Steady
3. Non-Uniform and
Unsteady
Concrete Channel
Open Channel Flow
1. Uniform & Steady - Manning’s Eqn in prismatic
channel - Q, v, y, A, P, B, S and roughness are all
constant
2. Critical flow - Specific Energy Eqn (Froude No.)
3. Non-uniform flow - gradually varied flow (steady
flow) - determination of floodplains
4. Unsteady and Non-uniform flow - flood waves
Uniform Open Channel Flow
Manning’s Eqn for velocity or flow
1 2 /3
v R
S S.I. units
n
1.49 2 /3
v
R
S English units
n
where
n = Manning’s roughness coefficient
R = hydraulic radius = A/P
S = channel slope
Q = flow rate (cfs) = v A
Normal depth is function of flow rate, and
geometry and slope. One usually solves for normal
depth or width given flow rate and slope information
B
b
Normal depth implies that flow rate, velocity, depth,
bottom slope, area, top width, and roughness remain
constant within a prismatic channel as shown below
UNIFORM FLOW
B
Q
V
y
S0
A
B
n
= Const
= C
= C
= C
= C
= C
= C
y
V
So
A
1 + Z2
1
a
z
Common Geometric Properties
Cot a = z/1
Optimal Channels - Max R and Min P
H = z + y + av2/2g = Total Energy
E = y + av2/2g = Specific Energy
a often near 1.0 for most channels
Energy Coeff.
a = S vi2 Qi
V2 QT
H
Uniform Flow
Energy slope = Bed slope or dH/dx = dz/dx
Water surface slope = Bed slope = dy/dz = dz/dx
Velocity and depth remain constant with x
My son Eric
Critical Depth and Flow
Critical depth is used to characterize channel flows -based on addressing specific energy E = y + v2/2g :
E = y + Q2/2gA2
where Q/A = q/y and q = Q/b
Take dE/dy = (1 – q2/gy3) and set = 0.
const
q=
E = y + q2/2gy2
y
Min E Condition, q = C
E
Solving dE/dy = (1 – q2/gy3) and set = 0.
For a rectangular channel bottom width b,
1. Emin = 3/2Yc for critical depth y = yc
2. yc/2 = Vc2/2g
3. yc = (Q2/gb2)1/3
Froude No. = v/(gy)1/2
We use the Froude No. to characterize critical flows
Y vs E
E = y + q2/2gy2
q = const
Critical Flow in Open Channels
In general for any channel shape, B = top width
(Q2/g) = (A3/B)
at y = yc
Finally Fr = v/(gy)1/2 = Froude No.
Fr = 1 for critical flow
Fr < 1 for subcritical flow
Fr > 1 for supercritical flow
Non-Uniform Open Channel Flow
With natural or man-made channels, the
shape, size, and slope may vary along
the stream length, x. In addition,
velocity and flow rate may also vary
with x. Non-uniform flow can be best
approximated using a numerical method
called the Standard Step Method.
Non-Uniform Computations
Typically start at downstream end with known water level - yo.
Proceed upstream with calculations using new water levels as they
are computed.
The limits of calculation range between normal and critical depths.
In the case of mild slopes, calculations start downstream.
In the case of steep slopes, calculations start upstream.
Calc.
Q
Mild Slope
Non-Uniform Open Channel Flow
Let’s evaluate H, total energy, as a function of x.
H z y a v / 2g
2
dH dz dy a dv
dx dx dx 2 g dx
2
Take derivative,
Where
H = total energy head
z = elevation head,
av2/2g = velocity head
Replace terms for various values of S and
So. Let v = q/y = flow/unit width - solve for
dy/dx, the slope of the water surface
dy q
–S So 1 3 since v = q / y
dx gy
2
1 d 2
1 d q q
v
2
2g dx
2g dx y
g
2
2
1 dy
3
y dx
Given the Froude number, we can simplify
and solve for dy/dx as a fcn of measurable
parameters
Fr v / gy
2
2
dy
So S
So S
2
2
dx 1 v / gy 1 Fr
*Note that the eqn blows up when Fr = 1 and goes to
zero if So = S, the case of uniform OCF.
where
S = total energy slope
So = bed slope,
dy/dx = water surface slope
Yn > Yc
Uniform Depth
Mild Slopes where -
Yn > Yc
Now apply Energy Eqn. for a reach of length L
v1
v 2
y1 = y2 S S o L
2 g
2 g
2
2
v1
v2
y 1 2 g y 2 2g
L
S S0
2
2
This Eqn is the basis for the Standard Step Method
Solve for L = Dx to compute water surface profiles
as function of y1 and y2, v1 and v2, and S and S0
Backwater Profiles - Mild Slope Cases
Dx
Backwater Profiles - Compute Numerically
Compute
y3
y2 y1
Routine Backwater Calculations
1. Select Y1 (starting depth)
2. Calculate A1
(cross sectional area)
3. Calculate P1
(wetted perimeter)
4. Calculate R1 = A1/P1
5. Calculate V1 = Q1/A1
6. Select Y2 (ending depth)
7. Calculate A2
8. Calculate P2
9. Calculate R2 = A2/P2
10. Calculate V2 = Q2/A2
Backwater Calculations (cont’d)
1. Prepare a table of values
2. Calculate Vm = (V1 + V2) / 2
Energy Slope Approx.
3. Calculate Rm = (R1 + R2) / 2
nV
m
Manning’s
4. Calculate S
2
3
1.49Rm
2
y1 v12 y 2 v 22
2g 2g
5. Calculate L = ∆X from first equation L
S S0
6. X = ∑∆Xi for each stream reach (SEE SPREADSHEETS)
100 Year Floodplain
Bridge
D
Floodplain
Tributary
C
QD
QC
Main Stream
Bridge Section
B
QB
A
Cross Sections
QA
Cross Sections
The Floodplain
Top Width
Floodplain Determination
The Woodlands
The Woodlands planners wanted to design the
community to withstand a 100-year storm.
In doing this, they would attempt to minimize any
changes to the existing, undeveloped floodplain as
development proceeded through time.
HEC RAS (River Analysis
System, 1995)
HEC RAS or (HEC-2)is a computer model designed for
natural cross sections in natural rivers. It solves the
governing equations for the standard step method,
generally in a downstream to upstream direction. It can
Also handle the presence of bridges, culverts, and
variable roughness, flow rate, depth, and velocity.
HEC - 2
Orientation - looking downstream
River
Multiple Cross Sections
HEC RAS (River Analysis
System, 1995)
HEC RAS Bridge CS
HEC RAS Input Window
HEC RAS Profile Plots
3-D Floodplain
HEC RAS Cross Section
Output Table
Brays Bayou-Typical Urban System
• Bridges cause unique
problems in hydraulics
Piers, low chords, and top
of road is considered
Expansion/contraction
can cause hydraulic losses
Several cross sections
are needed for a bridge
288 Bridge causes a 2 ft
Backup at TMC and is
being replaced by TXDOT
288 Crossing