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Problem 1
Output Work, Input Work, Slope
Complete the following:
In your journal,
Draw a picture of an inclined plane
 Place the following labels and values in
the correct locations:

Load Force = 20 Newton’s
Load Distance = 3 m
Effort Force = 15 Newton’s
Effort Distance = 5 m
Rise = 3 m
Run = 4m
Calculate Output Work?
Calculate Input Work?
What is the slope of the incline?
Slope = Rise
Run
<---------Rise--------3 m---------------
Slope = .75
Slope = .75
Slope
Slope = 3 (rise)
4 (run)
Slope = Rise
Run
<--------------------Run---4 m--------------------
Slope = Rise
Run
---------Load Distance---3 m---------
<---------Rise--------3 m---------------
--------Load Force----20 Newton’s----
OW = LF x LD
Slope = .75
OW = 60 Joules
OW = 60 Joules
Output
OW = 20 x Work
3 = 60
(LF)
(LD)
Joules
Output Work = Load Force x Load Distance
<--------------------Run---4 m--------------------
Slope = Rise
Run
---------Load Distance---3 m---------
<---------Rise--------3 m---------------
--------Load Force----20 Newton’s---
OW = LF x LD
IW = EF x ED
Slope = .75
OW = 60 Joules
IW = 75 Joules
IW = 75 Joules
Input
Work
IW = 15 x 5 = 75
(EF)
(ED)
Joules
Input Work = Effort Force x Effort Distance
<--------------------Run---4 m--------------------
Problem 2
IW, OW, Slope, IMA, AMA, Efficiency
Complete the following:
In your journal,
Draw a picture of an inclined plane
 Place the following labels and values in
Calculate Output Work?
the correct locations:






Load Force = 15 Newton’s
Load Distance = 6 m
Effort Force = 11 Newton’s
Effort Distance = 10 m
Run = 8m
Calculate Input Work?
What is the slope of the
incline?
What is the IMA?
What is the AMA?
What is the efficiency?
<---Rise—(same as Load Distance)------6 m--------
Slope = Rise
Run
Slope = .75
Slope
Slope = 6 (rise)
8 (run)
Slope = Rise
Run
<--------------------Run---8 m--------------------
Slope = .75
Slope = .75
Slope = Rise
Run
---------Load Distance---6 m---------
<---------Rise--------6 m---------------
--------Load Force----15 Newton’s----
OW = LF x LD
OW = 90 Joules
OW = 90 Joules
Output Work
OW = 15 x 6 = 90
(LF)
(LD)
Joules
Output Work = Load Force x Load Distance
<--------------------Run---8 m--------------------
Slope = .75
Slope = Rise
Run
---------Load Distance---6 m---------
<---------Rise--------6 m---------------
--------Load Force----15 Newton’s---
OW = LF x LD
IW = EF x ED
OW = 90 Joules
IW = 110 Joules
IW = 110 Joules
Input
Work
IW = 11 x 10 = 110
(EF)
(ED)
Joules
Input Work = Effort Force x Effort Distance
<--------------------Run---8 m--------------------
Slope = .75
Slope = Rise
Run
OW = 90 Joules
---------Load Distance---6 m---------
<---------Rise--------6 m---------------
--------Load Force----15 Newton’s---
OW = LF x LD
IW = EF x ED
IW = 110 Joules
IMA = ED ÷ LD
IMA = 1.67
IMA
IMA = 10 ÷ 6 = 1.67
(ED)
(LD)
IMA = Effort Distance
÷
Load Distance
<--------------------Run---8 m--------------------
IMA = 1.67
Slope = .75
Slope = Rise
Run
OW = 90 Joules
---------Load Distance---6 m---------
<---------Rise--------6 m---------------
--------Load Force----15 Newton’s---
OW = LF x LD
IW = EF x ED
IMA = ED ÷ LD
IW = 110 Joules
IMA = 1.67
AMA = LF ÷ EF
AMA = 1.36
AMA
AMA = 15 ÷ 11 = 1.36
(LF)
(EF)
AMA = Load Force ÷ Effort Force
<--------------------Run---8 m--------------------
AMA = 1.36
Slope = .75
Slope = Rise
Run
OW = 90 Joules
---------Load Distance---6 m---------
<---------Rise--------6 m---------------
--------Load Force----15 Newton’s---
OW = LF x LD
IW = EF x ED
IW = 110 Joules
IMA = ED ÷ LD
IMA = 1.66
AMA = LF ÷ EF AMA = 1.36
Efficiency = 82%
Eff = OW ÷ IW
x 100
Efficiency
Efficiency = (90 ÷ 110) = .82
(OW)
(IW)
.82 x 100 = 82 %
Efficiency = (OW ÷ IW) x 100
<--------------------Run---8 m--------------------
Eff = 82%
Problem 3
IW, OW, Slope, IMA, AMA, Efficiency
Complete the following:
In your journal,
Draw a picture of an inclined plane
 Place the following labels and values in
Calculate Output Work?
the correct locations:






Load Force = 120 Newton’s
Load Distance = 12 m
Effort Force = 80 Newton’s
Effort Distance = 22.5 m
Run = 20 m
Calculate Input Work?
What is the slope of the
incline?
What is the IMA?
What is the AMA?
What is the efficiency?
<---Rise—(same as Load Distance)------12 m--------
Slope = Rise
Run
Slope = .6
Slope
Slope = 12 (rise)
20 (run)
Slope = Rise
Run
<--------------------Run---20 m--------------------
Slope = .6
Slope = .6
Slope = Rise
Run
-------Load Distance---12 m---------
<---------Rise--------12 m---------------
-----Load Force----120 Newton’s----
OW = LF x LD
OW = 1440 Joules
OW = 1440 Joules
Output Work
OW = 120 x 12 = 1440
(LF)
(LD)
Joules
Output Work = Load Force x Load Distance
<--------------------Run---20 m--------------------
Slope = .75
Slope = Rise
Run
OW = 1440 Joules
---------Load Distance---12 m-------
<---------Rise--------12 m------------
--------Load Force----120 Newton’s-
OW = LF x LD
IW = EF x ED
IW = 1800 Joules
IW = 1800 Joules
Input
Work
IW = 80 x 22.5 = 1800
(EF)
(ED)
Joules
Input Work = Effort Force x Effort Distance
<--------------------Run---20 m--------------------
Slope = .75
Slope = Rise
Run
OW = 1440 Joules
-----Load Force----120 Newton’s---
------Load Distance---12 m---------
<---------Rise--------12 m---------------
OW = LF x LD
IW = EF x ED
IW = 1800 Joules
IMA = ED ÷ LD
IMA = 1.88
IMA = 1.88
IMA
IMA = 22.5 ÷ 12 = 1.88
(ED)
(LD)
IMA = Effort Distance
÷
Load Distance
<--------------------Run---20 m--------------------
Slope = .75
Slope = Rise
Run
OW = 1440 Joules
-------Load Distance---12 m---------
<---------Rise--------12 m---------------
------Load Force----120 Newton’s---
OW = LF x LD
IW = EF x ED
IMA = ED ÷ LD
IW = 1800 Joules
IMA = 1.88
AMA = LF ÷ EF
AMA = 1.5
AMA
AMA = 120 ÷ 80 = 1.5
(LF)
(EF)
AMA = Load Force ÷ Effort Force
<--------------------Run---20 m--------------------
AMA = 1.5
Slope = .75
Slope = Rise
Run
OW = 1440 Joules
-----Load Distance---12 m---------
<---------Rise--------12 m---------------
-----Load Force----120 Newton’s---
OW = LF x LD
IW = EF x ED
IW = 1800 Joules
IMA = ED ÷ LD
IMA = 1.88
AMA = LF ÷ EF AMA = 1.5
Efficiency = 80%
Efficiency
Eff = OW ÷ IW
x 100
Efficiency = (1440 ÷ 1800) = .80
(OW)
(IW)
.80 x 100 = 80 %
Efficiency = (OW ÷ IW) x 100
<--------------------Run---20 m--------------------
Eff = 80%
Problem 4
IW, OW, Slope, IMA, AMA, Efficiency
Complete the following:
In your journal,
Draw a picture of an inclined plane
 Place the following labels and values in
the correct locations:
Calculate Output Work?






Load Force = 18 Newton’s
Load Distance = 6 m
Effort Force = 12 Newton’s
Effort Distance = 10 m
Run = 8m
Calculate Input Work?
What is the slope of the
incline?
What is the IMA?
What is the AMA?
What is the efficiency?
Slope = .75
<---Rise—(same as Load Distance)------6 m--------
Slope = Rise
Run
Slope = .75
Slope
Slope = 6 (rise)
8 (run)
Slope = Rise
Run
Click to continue
<--------------------Run---8 m--------------------
Slope = .75
Slope = Rise
Run
---------Load Distance---6 m---------
<---------Rise--------6 m---------------
--------Load Force----18 Newton’s----
OW = LF x LD
OW = 108 Joules
OW = 108 Joules
Output Work
OW = 18 x 6 = 108
(LF)
(LD)
Joules
Click to continue
Output Work = Load Force x Load Distance
<--------------------Run---8 m--------------------
Slope = .75
Slope = Rise
Run
---------Load Distance---6 m---------
<---------Rise--------6 m---------------
--------Load Force----18 Newton’s---
OW = LF x LD
IW = EF x ED
OW = 108 Joules
IW = 120 Joules
IW = 120 Joules
Input
Work
IW = 12 x 10 = 120
(EF)
(ED)
Joules
Click to continue
Input Work = Effort Force x Effort Distance
<--------------------Run---8 m--------------------
Slope = .75
Slope = Rise
Run
OW = 108 Joules
---------Load Distance---6 m---------
<---------Rise--------6 m---------------
--------Load Force----18 Newton’s---
OW = LF x LD
IW = EF x ED
IW = 120 Joules
IMA = ED ÷ LD
IMA = 1.67
IMA
IMA = 10 ÷ 6 = 1.67
(ED)
(LD)
Click to continue
IMA = Effort Distance
÷
Load Distance
<--------------------Run---8 m--------------------
IMA = 1.67
Slope = .75
Slope = Rise
Run
OW = 108 Joules
---------Load Distance---6 m---------
<---------Rise--------6 m---------------
--------Load Force----18 Newton’s---
OW = LF x LD
IW = EF x ED
IMA = ED ÷ LD
IW = 120 Joules
IMA = 1.67
AMA = LF ÷ EF
AMA = 1.5
AMA
AMA = 18 ÷ 12 = 1.5
(LF)
(EF)
Click to continue
AMA = Load Force ÷ Effort Force
<--------------------Run---8 m--------------------
AMA = 1.5
Slope = .75
Slope = Rise
Run
OW = 108 Joules
---------Load Distance---6 m---------
<---------Rise--------6 m---------------
--------Load Force----18 Newton’s---
OW = LF x LD
IW = EF x ED
IW = 120 Joules
IMA = ED ÷ LD
IMA = 1.66
AMA = LF ÷ EF AMA = 1.5
Efficiency = 90%
Eff = OW ÷ IW
x 100
Efficiency
Efficiency = (108 ÷ 120) = .90
(OW)
(IW)
.90 x 100 = 90%
Click to continue
Efficiency = (OW ÷ IW) x 100
<--------------------Run---8 m--------------------
Eff = 90%