Transcript Warm Up:

Warm Up:
Solve for the variable:
1. 105 = 2x + 5
50
2. 119 – x = 3x + 11
27
3. 2x – 7 = -4x + 1
𝟒
𝟑
Linear Pair
I: Two angles that share a common
vertex and together make a straight
line (180°).
M: What is the missing measure?
Vertical Angles
I: Two angles that share a common vertex and
are opposite of each other when two lines
cross. Angles will always be congruent.
M:
Acute Angle
I: Has a measure between 0° and
90°.
M:
67°
Right Angle
I: An angle that has a measure
equal to 90°.
M:
Obtuse Angle
I: An angle that has a measure
between 90° and 180°.
M:
140°
Complementary Angles
I: A pair of angles whose sum of
measures equals 90°.
M:
Find the missing measure.
x°
58°
Supplementary Angles
I: A pair of angles whose sum of
measures equals 180°.
M: Find the value of x.
x
x + 60
Angle Bisector
I: A ray (or line segment) that divides an angle
into two congruent angles.
M:
Practice
∠1 𝑎𝑛𝑑 ∠2are complementary. Solve for x and
the measure of both angles.
1.
∠1 = 5x + 2
∠2 = 2x + 4
x = 12; ∠1 = 62° and ∠2 = 28°
2.
∠1 = 12x + 4
∠2 = 9x + 2
x = 4; ∠1 = 52° and ∠2 = 38°
One of two complementary angles is 16 degrees
less than its complement. Find the measure of
both angles.
Two angles: x and x – 16
X = 53
X – 16 = 37
One of two supplementary angles is 98° greater
than its supplement. Find the measure of both
angles.
Two Angles: x and x + 98
X = 41
X + 98 = 139
5. One of two complementary angles is 57°
greater than twice its complement. Find the
measure of both angles.
Two Angles: x and 2x + 57
X = 11
2x + 57 = 79
6. One of two supplementary angles is 123° less
than twice its supplement. Find the measure
of both angles.
Two angles: x and 2x – 123
X = 101
2x – 123 = 79
7.
Find all missing angle measures
Given: m1 = 90°, m2 = 34°, and m6 = 137°
∠3 = 90°
∠ 4 = 146°
90°
∠5 = 146°
∠7 = 137°
∠8 = 43°
137°
34°
1 and 2 are complementary angles, state
the numerical value of x.
8. m1 = 2x, m2 = 3x
X = 18
9. m1 = 30 + x, m2 = 40 + x
x = 10
3 and 4 are supplementary angles, state
the numerical value of y.
10. m3 = 2y, m4 = 3y – 15
y = 39
11. m3 = 5m4, m4 = y
y = 30