Basic Concepts - Oakland University

Download Report

Transcript Basic Concepts - Oakland University

Circuit Theorems

Discussion D2.5

Sections 2-9, 2-11 1

Circuit Theorems

Linear Circuits and Superposition

• Thevenin's Theorem • Norton's Theorem • Maximum Power Transfer 2

Linear Circuits

• A linear circuit is one whose output is directly proportional to its input. • Linear circuits obey both the properties of homogeneity (scaling) and additivity. 3

4

Superposition Principle

Because the circuit is linear we can find the response of the circuit to each source acting alone, and then add them up to find the response of the circuit to all sources acting together. This is known as the

superposition principle

.

The superposition principle states that the voltage across (or the current through) an element in a linear circuit is the algebraic sum of the voltages across (or currents through) that element due to each independent source acting alone.

5

Turning sources off

Current source:

i

i s

a

i s

We replace it by a current source where

i s

 0 b An open-circuit Voltage source: DC

v s

+

v

v s

We replace it by a voltage source where

v s

 0

i

An short-circuit 6

Steps in Applying the Superposition Principle

1. Turn off all independent sources except one. Find the output (voltage or current) due to the active source.

2. Repeat step 1 for each of the other independent sources.

3. Find the total output by adding algebraically all of the results found in steps 1 & 2 above.

In some cases, but certainly not all, superposition can simplify the analysis.

7

Example: In the circuit below, find the current

i

by superposition  24V DC   Turn off the two voltage sources (replace by short circuits).

DC 12V

i

 3A  12V 

v

1 

i

1 

v

2 3A 8

   

1 4

12V 

v

1 

i

1 

i

1  1 

1 4

 

v

1    5 6

v

1  1 4

v

2  0

v

2 3A

v

2  10 3

v

1

v

1  3  1 4

v

1  3 8

v

2  3

v

1 10 8  2 8  3 9

Example: In the circuit below, find the current

i

by superposition  24V DC   Turn off the 24V & 3A sources: DC 12V

i

 3A 

i

1   DC 12V

i

2 

i

2 O.C.

10

  DC 12V  

i

2  O.C.

16  3 DC 12V   O.C.

i

2 

i

2  12 6  2 DC 12V  O.C.

i

2 11

Example: In the circuit below, find the current

i

by superposition  24V DC   Turn off the 3A & 12V sources: DC 12V

i

 3A  24V DC

i

2  

i

3 

i

3 O.C.

12

   

4

4

 

i

2      

24 0

  

i

3

i

2 

i

3  24V DC 16

i

2  4

i

3   24  4

i

2  7

i

3  0 O.C.

i

2  7 4

i

3

i

3 

i

3   1    24 13

 DC 12V 

i

 24V DC  3A

i

1

i

2

i

3  12V 

v

1 

i

1

i

1  1 

v

2 3A 

i

1  DC 12V 

i

2

i

2

i

2  2  O.C.

 2A 

i

2  24V DC  

i

3

i

3

i

3   1 14 O.C.

Circuit Theorems

• • Linear Circuits and Superposition

Thevenin's Theorem

• Norton's Theorem • Maximum Power Transfer 15

Thevenin's Theorem

In many applications we want to find the response to a particular element which may, at least at the design stage, be variable. Linear Circuit V b a + Variable R Each time the variable element changes we have to re-analyze the entire circuit. To avoid this we would like to have a technique that replaces the linear circuit by something simple that facilitates the analysis. A good approach would be to have a simple

equivalent circuit

to replace everything in the circuit except for the variable part (the load). 16

Thevenin's Theorem

Thevenin’s theorem

states that a linear two-terminal resistive circuit can be replaced by an equivalent circuit consisting of a voltage source

V Th

in series with a resistor

R Th

, where

V Th

open-circuit voltage at the terminals, and

R Th

is the is the input or equivalent resistance at the terminals when the independent sources are all turned off.

i

a

i

a Linear Circuit

R L

DC

V Th R Th R L

b

R in

b

R in

17

Thevenin's Theorem

Thevenin’s theorem states that the two circuits given below are equivalent as seen from the load

R L

that is the same in both cases.

i

a

i

a

R Th

Linear Circuit

R L

DC

V Th R L

b

R in

b

R in V Th

= Thevenin’s voltage =

V ab

open-circuit voltage =

V OC

with

R L

disconnected (=  ) = the 18

Linear Circuit

Thevenin's Theorem

i

a

i

a

R L

DC

V Th R Th R L

b

R in

b

R in R Th

= Thevenin’s resistance = the input resistance with all

independent

sources turned off (voltage sources replaced by short circuits and current sources replaced by open circuits). This is the resistance seen at the terminals

ab

when all independent sources are turned off. 19

DC 10V DC 10V       b

Example

a

v OC

 2 10V  5V 

V Th

b a

i SC

 2 10 2  2 3 3  10 4  2.5A



R Th

V Th i SC

 5 2.5

R Th

a DC

V Th

 5V  a b 

R Th

b 20

Circuit Theorems

• Linear Circuits and Superposition • Thevenin's Theorem •

Norton's Theorem

• Maximum Power Transfer 21

Norton's Theorem

Norton’s equivalent circuit

can be found by transforming the Thevenin equivalent into a current source in parallel with the Thevenin resistance. Thus, the Norton equivalent circuit is given below.

i

a

I N

V Th R Th R N

R Th R L

b Formally, Norton’s Theorem states that a linear two terminal resistive circuit can be replaced by an equivalent circuit consisting of a current source

I N

in parallel with a resistor

R N

, where

I N

short-circuit current through the terminals, and

R N

is the is the input or equivalent resistance at the terminals when all independent sources are all turned off.

22

Circuit Theorems

• Linear Circuits and Superposition • Thevenin's Theorem • • Norton's Theorem

Maximum Power Transfer

23

Maximum Power Transfer

In all practical cases, energy sources have non-zero internal resistance. Thus, there are losses inherent in any real source. Also, in most cases the aim of an energy source is to provide power to a load. Given a circuit with a known internal resistance, what is the resistance of the load that will result in the maximum power being delivered to the load?

Consider the source to be modeled by its Thevenin equivalent.

i

a

R Th R L

DC

V Th

b 24

DC

V Th R Th i

a

R L

b The power delivered to the load (absorbed by

R L

) is

p

 2

i R L

V Th

R Th

R L

 2

R L

This power is maximum when

R L

 0 

p

R L

V Th

2 

R Th

R L

  2  2

R L

R Th

R L

  3  0 25

dp dR L

V Th

2 

R Th

R L

  2

R Th

R L

 2

R L

 2

R L

R Th

R L

  3  0

R L

R Th

Thus, maximum power transfer takes place when the resistance of the load equals the Thevenin resistance

R Th

. Note also that

p

max 

V Th

R Th

R L

 2

R L R L

R Th p

max 

V Th

 2

R Th

 2

R Th

V Th

2 4

R Th

Thus, at best, one-half of the power is dissipated in the internal resistance and one-half in the load.

26