Transcript Document
Introduction to Multiple Regression James R. Stacks, Ph.D. [email protected] The best way to have a good idea is to have lots of ideas Linus Pauling Standardized form of a regression equation with three predictor variables Z’c = b1Zp1 + b2Zp2 + b3Zp3 Predictor variables (standardized z scores) Z’c = b1Zp1 + b2Zp2 + b3Zp3 Z’c = b1Zp1 + b2Zp2 + b3Zp3 Standardized regression coefficients Z’c = b1Zp1 + b2Zp2 + b3Zp3 Predicted criterion score (zc – ze) Predictor variables (standardized z scores) Z’c = b1Zp1 + b2Zp2 + b3Zp3 Predicted criterion score (zc – ze) Standardized regression coefficients Z’c = b1Zp1 + b2Zp2 + b3Zp3 Predicted criterion score (zc – ze) Predicted criterion score (zc – ze) Z’c = b1Zp1 + b2Zp2 + b3Zp3 Recall that the predicted criterion score is the is the actual criterion score minus the error Zc = b1Zp1 + b2Zp2 + b3Zp3 + Ze Recall that multiplication of an entire equation by any value results in an equivalent equation: y=bx is the same as yx = bxx or as yx = bx2 The following demonstration of solving for standardized regression coefficients is taken largely from: Maruyama, Geoffrey M. (1998). Basics of structural equation modeling. Thousand Oaks, CA: Sage Publications, Inc. Let’s write three equivalent forms of the previous multiple regression equation by multiplying the original equation by each of the three predictor variables: ZcZp1 = b1Zp1Zp1 + b2Zp2Zp1 + b3Zp3Zp1 + ZeZp1 ZcZp2 = b1Zp1Zp2 + b2Zp2Zp2 + b3Zp3Zp2 + ZeZp2 ZcZp3 = b1Zp1Zp3 + b2Zp2Zp3 + b3Zp3Zp3 + ZeZp3 (Maruyama, Geoffrey M. (1998). Basics of structural equation modeling. Thousand Oaks, CA: Sage Publications, Inc.) Now notice all the zz cross products in the equations. Recall that the expected (mean) cross product is something we are familiar with. The unbiased estimate of the cross product for paired z values is: E(cross product) = S(zz)/(n-1) , or , Pearson r ! ZcZp1 = b1Zp1Zp1 + b2Zp2Zp1 + b3Zp3Zp1 + ZeZp1 ZcZp2 = b1Zp1Zp2 + b2Zp2Zp2 + b3Zp3Zp2 + ZeZp2 ZcZp3 = b1Zp1Zp3 + b2Zp2Zp3 + b3Zp3Zp3 + ZeZp3 (Maruyama, Geoffrey M. (1998). Basics of structural equation modeling. Thousand Oaks, CA: Sage Publications, Inc.) The Pearson product-moment correlation coefficient (written as r for sample estimate, r for parameter) r S n = Za Zb n-1 i=1 Where za and zb are z scores for each person on some measure a and some measure b, and n is the number of people So, I could just as easily write: rc p1 = b1r p1 p1 + b2 rp2 p1 + b3 rp3 p1 + re p1 rc p2 = b1r p1 p2 + b2 rp2 p2 + b3 rp3 p2 + re p2 rc p3 = b1r p1 p3 + b2 rp2 p3 + b3 rp3 p3 + re p3 (Maruyama, Geoffrey M. (1998). Basics of structural equation modeling. Thousand Oaks, CA: Sage Publications, Inc.) Now, let’s look at some interesting things about the correlation coefficients we have substituted rc p1 = b1r p1 p1 + b2 rp2 p1 + b3 rp3 p1 + re p1 rc p2 = b1r p1 p2 + b2 rp2 p2 + b3 rp3 p2 + re p2 rc p3 = b1r p1 p3 + b2 rp2 p3 + b3 rp3 p3 + re p3 Correlations of variables with themselves are necessarily unity, So the red values are 1 In regression, error by definition is the variance which does not correlate with any variable, thus the blue values are necessarily 0 (Maruyama, Geoffrey M. (1998). Basics of structural equation modeling. Thousand Oaks, CA: Sage Publications, Inc.) rc p1 = b1(1) + b2 rp2 p1 + b3 rp3 p1 rc p2 = b1r p1 p2 + b2 (1) + b3 rp3 p2 rc p3 = b1r p1 p3 + b2 rp2 p3 + b3 (1) The above system can be written in matrix form: rc p1 rc p2 rc p3 b1(1) + b2 rp2 p1 + b3 rp3 p1 = b1r p1 p2 + b2 (1) + b3 rp3 p2 b1r p1 p3 + b2 rp2 p3 + b3 (1) (Maruyama, Geoffrey M. (1998). Basics of structural equation modeling. Thousand Oaks, CA: Sage Publications, Inc.) rc p1 rc p2 rc p3 b1(1) + b2 rp2 p1 + b3 rp3 p1 = b1r p1 p2 + b2 (1) + b3 rp3 p2 b1r p1 p3 + b2 rp2 p3 + b3 (1) Note that the matrix on the right side above is a vector, and it is a product of a correlation matrix of the predictor variables and a b vector. rc p1 rc p2 rc p3 = (1) rp2 p1 rp3 p1 b1 r p1 p2 (1) rp3 p2 b2 r p1 p3 rp2 p3 (1) b3 (Maruyama, Geoffrey M. (1998). Basics of structural equation modeling. Thousand Oaks, CA: Sage Publications, Inc.) rc p1 rc p2 rc p3 1 = rp2 p1 r p1 p2 1 r p1 p3 rp2 p3 rp3 p1 b1 rp3 p2 b2 1 b3 The moral of this story is: assuming all the Pearson correlations among variables are known (they are easily calculated), we can use the equation above to solve for the b vector, which is the standardized regression coefficients. Z’c = b1Zp1 + b2Zp2 + b3Zp3 (Maruyama, Geoffrey M. (1998). Basics of structural equation modeling. Thousand Oaks, CA: Sage Publications, Inc.) rc p1 rc p2 rc p3 1 = rp2 p1 r p1 p2 1 r p1 p3 rp2 p3 rp3 p1 b1 rp3 p2 b2 1 b3 This is a matrix equation which can be symbolized as: Riy = RiiBi From algebra, such an equation can obviously be solved for Bi by dividing both sides by Rii, but there is no such thing as division in matrix math The matrix notation used here corresponds to your text: Tabachnik, Barbara G. & Fidell, Linda S. (2001). Using multivariate statistics., 4th Edition. Needham Heights, MA: Allyn & Bacon What is necessary to accomplish the same goal is to multiply both sides of the equation by the inverse -1 of ii, written as ii . R R -1 -1 Rii Riy = Rii Rii Bi therefore -1 Rii Riy = Bi If you have studied the appendix assigned on matrix algebra,you know that, while matrix multiplication is quite simple, matrix inversion is a real chore! The matrix notation used here corresponds to your text: Tabachnik, Barbara G. & Fidell, Linda S. (2001). Using multivariate statistics., 4th Edition. Needham Heights, MA: Allyn & Bacon rc p1 rc p2 rc p3 = 1 rp2 p1 rp3 p1 b1 r p1 p2 1 rp3 p2 b2 r p1 p3 rp2 p3 1 b3 Riy = Rii Bi To get the solution we must find the inverse of the green shaded matrix Rii in order to get Rii-1 for the equation : -1 Rii Riy = Bi The matrix notation used here corresponds to your text: Tabachnik, Barbara G. & Fidell, Linda S. (2001). Using multivariate statistics., 4th Edition. Needham Heights, MA: Allyn & Bacon The following method of inverting a matrix is taken largely from: Swokowski, Earl W. (1979) Fundamentals of College Algebra. Boston, MA: Prindle, Weber & Scmidt The first step is to form a matrix which has the same number of rows as the original correlation matrix of predictors, but has twice as many columns. The original predictor correlations are placed in the left half, and an equal order identity matrix is place in the Earl W. (1979) Fundamentals of College right half: (Swokowski, Algebra. Boston, MA: Prindle, Weber & Scmidt) (Predictor correlations) (Identity matrix) Though a series of calculations called elementary row transformations, the goal is to change all the numbers in the matrix so that the identity matrix is on the left, and a new matrix is on the right: (Swokowski, Earl W. (1979) Fundamentals of College Algebra. Boston, MA: Prindle, Weber & Scmidt) Identity Matrix Inverse Matrix Swokowski, Earl W. (1979) Fundamentals of College Algebra. Boston, MA: Prindle, Weber & Scmidt “ MATRIX ROW TRANSFORMATION THEOREM Given a matrix of a system of linear equations, each of the following transformations results in a matrix of an equivalent system of linear equations: (i) Interchanging any two rows (ii) Multiplying all of the elements in a row by the same nonzero real number k. (iii) Adding to the elements in a row k times the corresponding elements of any other row, where k is any real number. “ 1st transformation: a2j = a2j + (-.488) a1j 2nd transformation: a3j = a3j + (-.354) a1j 3rd transformation: a2j = a2j . / 1 .761856 4th transformation: a3j = a3j + (-.199248) a2j 5th transformation: a3j = a3j . / 1 .822574723 6th transformation: a1j = a1j + (-.488) a2j 7th transformation: a1j = a1j + (-.226373488) a3j 8th transformation: a2j = a2j + (-.261529737) a3j Inverted matrix on right Original matrix on left inverse of predictor correlations predictor/criterion correlations beta vector b1 = b2 b3 -1 Rii Riy = Bi OUR CALCULATIONS VALUES FROM SPSS -.257 b1 .873 b2 .150 b3 The difference has to do with rounding error. There are so many transformations in matrix math that all computations must be carried out with many, many significant figures, because the errors accumulate. I only used what was visible in my calculator. Good matrix software should use much more precision. This is a relatively brief equation to solve. Imagine the error that can accumulate with hundreds of matrix transformations. This is a very important point, and one should always be certain the software is using the appropriate degree of precision., The regression equation can then be written: Z’c = (-.255)Zp1 + (.872)Zp2 + (.149) Zp3