Transcript No Slide Title

A 3.51 g sample of benzene, C6H6, was burned in a
bomb calorimeter in an excess of oxygen. The
initial temperature was 25.00oC and rose to
37.18oC. The heat capacity of the calorimeter and
contents was 12.05 kJ/oC.
Find q (heat given off) for the
combustion of 1 mol of benzene.
A 3.51 g sample of benzene, C6H6, was burned in a
bomb calorimeter in an excess of oxygen. The
initial temperature was 25.00oC and rose to
37.18oC. the heat capacity of the calorimeter and
contents was 12.05 kJ/oC.
Find q for the combustion of 1 mol of benzene.
C6H6(l) + 15/2 O2(g)  6CO2(g) + 3H2O(l)
3.51 g
T = 12.18oC
12.05kJ
o
C
What units do we
desire?
A 3.51 g sample of benzene, C6H6, was burned in a
bomb calorimeter in an excess of oxygen. The
initial temperature was 25.00oC and rose to
37.18oC. the heat capacity of the calorimeter and
contents was 12.05 kJ/oC.
Find q for the combustion of 1 mol of benzene.
C6H6(l) + 15/2 O2(g)  6CO2(g) + 3H2O(l)
3.51 g
T =
12.18oC
12.05kJ
o
C
kJ

mol Bz
If we could find the
number of kJ and the
number of moles of
benzene, we could divide
the kJ by the moles to
get our answer!
kJ

mol Bz
A 3.51 g sample of benzene, C6H6, was burned in a bomb
calorimeter in an excess of oxygen. The initial temperature
was 25.00oC and rose to 37.18oC. the heat capacity of the
calorimeter and contents was 12.05 kJ/oC.
Find q for 1 mol of benzene.
C6H6(l) + 15/2 O2(g)  6CO2(g) + 3H2O(l)
3.51 g
T = 12.18oC
12.05kJ
o
C
12.05kJ 12.18 oC
o
C
m ol
3.51 g
78.05 g
kJ

mol Bz
= 146.8 kJ
= 0.04497 mol BZ
Find q for 1 mol of benzene.
C6H6(l) + 15/2 O2(g)  6CO2(g) + 3H2O(l)
3.51 g
T = 12.18oC
12.05kJ
o
C
12.05kJ 12.18 oC
o
C
m ol
3.51 g
78.05 g
kJ

mol Bz
= 146.8 kJ
= 0.04497 mol BZ
And now?
Find q for 1 mol of benzene.
C6H6(l) + 15/2 O2(g)  6CO2(g) + 3H2O(l)
3.51 g
T = 12.18oC
12.05kJ
o
C
12.05kJ 12.18 oC
o
C
m ol
3.51 g
78.05 g
146.8 kJ
0.04497 mol Bz
kJ

mol Bz
= 146.8 kJ
= 0.04497 mol BZ
 3264
kJ
mol Bz
Find q for 1 mol of benzene.
C6H6(l) + 15/2 O2(g)  6CO2(g) + 3H2O(l)
3.51 g
T = 12.18oC
12.05kJ
o
C
12.05kJ 12.18 oC
78.05 g
o
C
3.51 g mol
kJ
= 3264
mol Bz