Transcript Lecture 10

Liquids and Gasses Matter that “Flows”

Density and Specific Gravity

  Density is mass per unit volume 

m V

SI unit is

kg m

3   But this is also used

g cm

3

Specific Gravity

 Ratio of density to the density of water at 4 o C.

 Density of water at 4 o C=1 g/cm 3  The 4 o C is important since water’s density changes with temperature  It has nothing to do with gravity  Relative density would be a better term

Pressure

 A static fluid will exert a force perpendicular to any surface it is in contact with   Pressure is defined as Force per unit Area

p

F

A

Note this is scalar  SI unit of N/m 2 =pascal=pa

Atmospheric Pressure

 The big volume of air above us exerts pressure downwards.

p

 Pressure at sea level  1

atm

 1 .

013

x

10 5

pa a

 Changes depending on elevation, temperature, weather condition etc.

Pressure at depth

 constant all throughout the liquid.  Fluid is incompressible  Force is from weight of liquid

p p

 

F

 

A hg

mg A

 

Vg A

 

Ahg A

Pressure at depth

 If fluid is compressible (gasses) density changes with height and equation is only valid for very thin slices.

Pascal’s Law

 Equations independent of Area, only height matters.

 Pressure is the same at any two points at the same level of the fluid.

If pressure is applied to one end it is distributed throughout the fluid and to the walls of the container

Pascal’s Law Application

 Hydraulic Lift

p

F

1

A

1 

F

2

A

2  However, volume of the liquid remains the same

V

1

A

1  

x V

2 1 

A

2 

x

2

Hydraulic Lift

F

1

F

2 

A

1

A

2  

x

2 

x

1

F

1 

x

1 

F

2 

x

2  Work done by F1 = Work done by F2

Example

 A car lift used in a service station uses compressed air to exert a force on a small piston with a circular cross section of radius 5.00cm. The pressure is transmitted by a liquid to a second piston of radius 15.0 cm. What force must the compressed air exert to lift a car weighing 13300N? What air pressure produces this force?

Example

p

F

1 

A

1

F

2

A

2

F

1 

A

1

A

2

F

2  

r

1 2 

r

1 2

F

2 

F

1  5 2 13300 15 2

F

 1480

N

1 Note: no need to convert to meters since units cancel

p

F

1

A

1 

F

2

A

2

p

  1480

N

( 0 .

05 ) 2  188000

Pa

Absolute Pressure and Gauge Pressure

 Absolute Pressure  Total Pressure within a vessel  Gauge Pressure  Excess Pressure above atmospheric pressure  Gauge Pressure – Ex. A tire shows 220kPa  Absolute Pressure of tire is 220kPa+1atm=320kPA  Flat tire actually has 1 atm of pressure inside

Pressure Gauges - Manometer

 Many different devices used to measure pressure  Manometer – consists of a U-shaped tube filled with a liquid of known density. It is open in one end and the other end is connected to a container filled with gas whose pressure to be measured.

Pressure Gauges - Manometer

 Bottom of tube has same pressure

p

p

p

 

gy

1

p atm

 

p atm

g

(

y

2   

gy y

1 ) 2

p atm

 

gh

 Gauge pressure is proportional to height difference

Pressure Gauges - Barometer

 Mercury barometer – consists of filled tube of mercury closed on one end and the other end is inverted into a dish of mercury.  Pressure in the closed end of the tube can be approximated to be zero.

Pressure Gauges - Barometer

p atm p atm

  

gh

 

gh p

0  mmHg or Torr, is another common unit of measure of pressure. But it is affected by temperature (density of Hg changes) as well as gravity.

Buoyancy

 Bodies immersed in water will weigh less  Bouyant Force is exerting an upward force  Assume a submerged object with uniform cross section area A

Bouyancy

B

B

B

B

B

F B

F T P B A

P T A

( 

gh B

A

A

(

P B

gh T

)

A

g

(

h

) 

Vg B

mg

P T

)

Bouyancy

 Archimedes’ Principle When a body is immersed in a fluid, the fluid exerts an upward force on the body equal to the weight of the fluid displaced by the body.

Example

 Archimedes was supposedly tasked to determine if the crown of the king was pure gold. He solved this by first weighing the crown in air, and then weighing the crown when submerged in water. Suppose the scale read 7.84N in air and 6.84N in water, what is the crown made of?

Example

F

 0 0 

T

1 

mg T

1 

mg

0 

T

2 

B

mg T

2 

mg

B T

1  7 .

84 1 

T

2  

B

6 .

84   

w Vg

w Vg

w Vg

1  

w Vg V V

 1 

w g

 1 1000 ( 9 .

8 )  1 .

02

x

10  4

m

3 

c

m c V

 7 .

84 ( 1 .

02

x

10  4 ) 9 .

8  

c

gold

7840

kg m

3  19300

kg m

3

Bouyancy

B

An object will float if 

W object

l V object g

m object g

l V object g

l

 

object

 

object V object g

Fluid Flow – Fluid Dynamics

 Complicated, but can be simplified with certain assumptions  Ideal Fluid  Incompresible- same density throughout  Not viscous - has no internal friction  Minimal turbulence 

Fluid Flow

 Assume the flow is steady

flow

 

m flow flow

  

t

 

V

t

Av

 

A

l

t

 Flow rate is constant  1

A

1

v

1   2

A

2

v

2

Fluid Flow

  1

A

1

v

1   2

A

2

v

2 Since incompresible

A

1

v

1 

A

2

v

2  Continuity Equation

Example

 A water hose of 2.50cm diameter is used by a gardener to fill a 30.0L bucket. The gardener notes that it takes 1.00min to fill the bucket. A nozzle with an opening of cross-sectional area 0.500cm

2 is attached and held so water is projected horizontally from a point 1.00m above ground. Over what horizontal distance can the water be projected?

Example

Flow

A

1

v

1 30

L

 0 .

03

m

min 0 .

0005

m

3

s

60

s

 3

Av

 0 .

0005

m

3

s v

 0 .

0005

m

3

s

0 .

00005

m

2  10 .

0

m s

Example

v

 10 .

0

m s t y

   1 2

gt

2  2 /

g

  2 /( 9 .

8 )(  1 )

t

 0 .

45

s R R

v x t

 4 .

 5

m

10 ( 0 .

45 )

Bernoulli’s Equation

 Pressure in a fluid depends on velocity and height  Assuming ideal fluid, fluid at certain cross section will do work on other parts of the fluid.

W W

2 1  

F

1

d

1  

F

2

d

2

p

1

A

1

d

1  

p

2

A

2

d

2

Bernoulli’s Equation

W g

 

mgh

 

mg

(

y

2 

y

1 )

W

W

1 

W

2 

W g W

K

 

p

1

A

1

d

1

p

1

A

1

d

1  

p

2

A

2

d

2

p

2

A

2

d

2  

mg

(

y

2

mg

(

y

2  

y

1 )

y

1 ) 1

mv

1 2 2

m

 

V

p

1

A

1

d

1  

Ad

mgy

1  1 2

mv

2 2 

p

2

A

2

d

2 

mgy

2 1 2 

v

1 2 

p

1  

gy

1  1 2 

v

2 2 

p

2  

gy

2

Example

 Water enters a house through a pipe with an inside diameter of 2.0 cm at an absolute pressure of 4.0x10

5 Pa. A 1.0cm diameter pipe leads to the second floor bathroom 5.0 m above. When the flow speed at the inlet pipe is 1.5 m/s, find the flow speed, pressure and volume flow in the bathroom.

Example

A

1

v

1 

A

2

v

2

v

2

v

2  

A

1

v

1

A

2   ( 0 ( 1 ) 2 .

5 ) 2 1 .

5  6

m s

1 2 

v

1 2 

p

1  

gy

1  1 2 

v

2 2 

p

2  

gy

2 1 2 ( 1000 )( 1 .

5 ) 2

p

2  3 .

34

x

10 5 

Pa

4 .

0

x

10 5  0  1 2 ( 1000 ) 6 2 

p

2  ( 1000 )( 9 .

8 )( 5 )

Example

Flow Flow

A

1

v

1   ( 0 .

5

x

10  2 ) 2 6

Flow

 4 .

7

x

10  4

m

3

s

Problems

 Giancoli 10-20  In working out Pascal’s principle, Pascal showed dramatically how force can be multiplied with fluid pressure. He placed a long thin tube of radius r=0.30cm, vertically into a wine barrel of radius R=21cm. He found that when the barrel was filled with water and the tube filled to a height of 12m, the barrel burst. Calculate (a) the mass of water in the tube? (b) the net force exerted on the barrel lid just before rupture.

Serway 14-20

 A U tube of uniform cross-secitonal area, open to the athmosphere, is partially filled with mercury. Water is then poured into both arms. If the equilibrium configuration fo the tube is as shown with h 2 =1.00cm, find h 1 .

Young and Friedman 14.31

 A cubical block of wood, 10 cm on a side, floats in the interface of oil and water with its lower surface, 1.50cm below the interface. The density of oil is 790kg/m 3 . (a) what is the gauge pressure at the upper face of the block? (b) What is the gauge pressure at the lower face of the block? (c) What are the mass and density of the block?

Young and Friedman 14.46

 A golf course sprinkler system discharges water from a horizontal pipe at the rate of 7200cm 3 /s. At one point in the pipe, where the radius is 4.00cm, the absolute pressure is 2.40x10

5 Pa. At a second point in the pipe, the water passes through a connection where the radius is 2.00cm. What is the absolute pressure as it flows through the constriction?