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Reinforced Concrete Design-8

Design of 2 way Slabs

By

Dr. Attaullah Shah

Swedish College of Engineering and Technology Wah Cantt.

One way vs Two way slab system

L>2S

As ≥ Temp. steel Min. Spacing ≥

main steel ≥ 4/3 max agg. ≥ 2.5 cm (1in) Max. Spacing ≤ 3 t ≤ 45 cm (17in)

Min slab thickness =

Shear Strength of Slabs

In two-way floor systems, the slab must have adequate thickness to resist both bending moments and shear forces at critical section. There are three cases to look at for shear.

1.

Two-way Slabs supported on beams 2.

Two-Way Slabs without beams 3.

Shear Reinforcement in two-way slabs without beams.

Shear Strength of Slabs Two-way slabs supported on beams

The critical location is found at d distance from the column, where 

V

c    2

f

c

bd

 The supporting beams are stiff and are capable of transmitting floor loads to the columns.

Shear Strength of Slabs

The shear force is calculated using the triangular and trapezoidal areas. If no shear reinforcement is provided, the shear force at a distance d from the beam must equal

V

ud  

V

c    2

f

c

bd

 where,

V

ud 

w

u    

l

2 2 

d

   

Shear Strength of Slabs Two-Way Slabs without beams

There are two types of shear that need to be addressed 1.

One-way shear or beam shear at distance d from the column 2.

Two-way or punch out shear which occurs along a truncated cone.

Shear Strength of Slabs

1.

One-way shear or beam shear at distance d from the column 2.

Two-way or punch out shear which occurs along a truncated cone.

Shear Strength of Slabs

One-way shear considers critical section a distance d from the column and the slab is considered as a wide beam spanning between supports.

V

ud  

V

c    2

f

c

bd

Shear Strength of Slabs

Two-way shear fails along a a truncated cone or pyramid around the column. The critical section is located d/2 from the column face, column capital, or drop panel.

Shear Strength of Slabs

If shear reinforcement is not provided, the shear strength of concrete is the smaller of: 

V

c      2  b 4 c   

f

c

b

o

d

   4

f

c

b

o

d

 b o b c = = perimeter of the critical section ratio of long side of column to short side

Shear Strength of Slabs

If shear reinforcement is not provided, the shear strength of concrete is the smaller of: 

V

c      a s

d b

o 

2

  

f

c

b

o

d

a s is 40 for interior columns, 30 for edge columns, and 20 for corner columns.

Shear Strength of Slabs Shear Reinforcement in two-way slabs without beams

.

For plates and flat slabs, which do not meet the condition for shear, one can either - Increase slab thickness - Add reinforcement Reinforcement can be done by shearheads, anchor bars, conventional stirrup cages and studded steel strips.

Shear Strength of Slabs Shearhead

consists of steel I-beams or channel welded into four cross arms to be placed in slab above a column. Does not apply to external columns due to lateral loads and torsion.

Shear Strength of Slabs Anchor bars

consists of steel reinforcement rods or bent bar reinforcement

Shear Strength of Slabs Conventional stirrup cages

Shear Strength of Slabs Studded steel strips

Shear Strength of Slabs

The reinforced slab follows section 11.12.4 in the ACI Code, where V n can not

V

c  4

f

c

b

o

d V

n 

V

c 

V

s  6

f

c

b

o

d V

s 

A

v

f

y

d

The spacing, s, can not exceed d/2.

s

If a shearhead reinforcement is provided

V

n  7

f

c

b

o

d

Example Problem

Determine the shear reinforcement required for an interior flat panel considering the following: V u = 195k, slab thickness = 9 in., d = 7.5 in., f c = 3 ksi, f y = 60 ksi, and column is 20 x 20 in.

Example Problem

Compute the shear terms find b 0 for 

V

c  

4

f b d

c 0

b

0  4    column width  110 in.

d

     

Example Problem

Compute the maximum allowable shear 

V

c   4

f b d

c 0    1 k 1000 lbs  135.6 k V u =195 k > 135.6 k Shear reinforcement is need!

Example Problem

Compute the maximum allowable shear 

V

c   6

f b d

c 0    1 k 1000 lbs  203.3 k So  V n >V u Can use shear reinforcement

Example Problem

Use a shear head or studs as in inexpensive spacing. Determine the a for 

V

c   2

f b d

c 0

b

0  4   column width  2

a

 

Example Problem

Determine the a for

V

u   2 19500 lb 

f b d

c 0 41.8 in.

  2

a

   7.5 in.

 The depth = a+d = 41.8 in. +7.5 in. = 49.3 in.  50 in.

Example Problem

Determine shear reinforcement 

V

s 

V

u   

V

c  59.4 k The  V s per side is  V s / 4 = 14.85 k

Example Problem

Determine shear reinforcement

V

s  14.85 k 0.75

 19.8 k Use a #3 stirrup A v = 2(0.11 in 2 ) = 0.22 in 2

V

s 

A f d

v y

s A f d

v y

V

s

Example Problem

Determine shear reinforcement spacing

s

A f d

v y

V

s   0.22 in 2   19.8 k  5.0 in.

Maximum allowable spacing is

d

2  7.5 in.

 3.75 in.

2 

Example Problem

Use s = 3.5 in.

# of stirrups  50 in.

3.5 in.

 14.3  Use 15 stirrups The total distance is 15(3.5 in.)= 52.5 in.

Example Problem

The final result: 15 stirrups at total distance of 52.5 in. So that a = 45 in. and c = 20 in.

Direct Design Method for Two-way Slab

Method of dividing total static moment M o positive and negative moments.

into Limitations on use of Direct Design method 1.

Minimum of 3 continuous spans in each direction. (3 x 3 panel) 2.

Direct Design Method for Two-way Slab

Limitations on use of Direct Design method 3.

Successive span in each direction shall not differ by more than 1/3 the longer span.

4.

Columns may be offset from the basic rectangular grid of the building by up to 0.1 times the span parallel to the offset.

Direct Design Method for Two-way Slab

Limitations on use of Direct Design method 5.

All loads must be due to gravity only (N/A to unbraced laterally loaded frames, from mats or pre-stressed slabs) 6.

load

Direct Design Method for Two-way Slab

Limitations on use of Direct Design method 7.

For panels with beams between supports on all sides, relative stiffness of the beams in the 2 perpendicular directions.

a 1

l

2 2 a 2

l

1 2 Shall not be less than 0.2 nor greater than 5.0

Definition of Beam-to-Slab Stiffness Ratio,

a Accounts for stiffness effect of beams located along slab edge reduces deflections of panel adjacent to beams.

a 

flexural stiffness flexural stiffness of beam of slab

Definition of Beam-to-Slab Stiffness Ratio,

a a  4E cb

I

b /

l

4E cs

I

s /

l

 4E cb

I

b 4E cs

I

s E cb I I b s  Modulus of elasticity E sb  Modulus of elasticity of slab concrete  Moment of inertia  Moment of inertia of of of beam concrete uncracked uncracked beam slab With width bounded laterally by centerline of adjacent panels on each side of the beam.

Two-Way Slab Design

Static Equilibrium of Two-Way Slabs

Analogy of two-way slab to plank and beam floor Section A-A: Moment per ft width in planks Total Moment 

M

f 

M

wl

1 2 k ft/ft 8    2

l

1 2 8 k ft

Two-Way Slab Design

Static Equilibrium of Two-Way Slabs

Analogy of two-way slab to plank and beam floor Uniform load on each beam Moment in one beam (Sec: B-B) 

wl

1 k/ft 2 

M

lb 

wl

1 2

l

2 2 k ft 8

Two-Way Slab Design

Static Equilibrium of Two-Way Slabs

M

   1

l

2 2 k ft Total Moment in both beams 8 Full load was transferred east-west by the planks and then was transferred north-south by the beams; The same is true for a two-way slab or any other floor system.

Basic Steps in Two-way Slab Design

1.

Choose layout and type of slab.

2.

Choose slab thickness to control deflection. Also, check if thickness is adequate for shear.

3.

Choose Design method − Equivalent Frame Method- use elastic frame analysis to compute positive and negative moments − Direct Design Method - uses coefficients to compute positive and negative slab moments

Basic Steps in Two-way Slab Design

4.

Calculate positive and negative moments in the slab.

5.

Determine distribution of moments across the width of the slab. - Based on geometry and beam stiffness.

6.

Assign a portion of moment to beams, if present.

7.

8.

Design reinforcement for moments from steps 5 and 6.

Check shear strengths at the columns

Minimum Slab Thickness for two-way construction

Maximum Spacing of Reinforcement At points of max. +/- M:

s

and

s

 2

t

 ACI 13.3.2

  18 in.

 ACI 7.12.3

 Min Reinforcement Requirements

A

 

A

 

Distribution of Moments

Slab is considered to be a series of frames in two directions:

Distribution of Moments

Slab is considered to be a series of frames in two directions:

Distribution of Moments

Total static Moment, M o where

M

0 

w

u

l

2

l

n 2  ACI 13 3  8

w

u  factored load per unit area

l

2  transvers e width of the strip

l

n  clear span between columns  for circular columns, calc.

l

n using h  0.886d

c 

Column Strips and Middle Strips

Moments vary across width of slab panel  Design moments are averaged over the width of column strips over the columns & middle strips between column strips.

Column Strips and Middle Strips

Column strips Design w/width on either side of a column centerline equal to smaller of 0 .

25

l

2 0 .

25

l

1 l 1 = length of span in direction moments are being determined.

l 2 = length of span transverse to l 1

Column Strips and Middle Strips

Middle strips: Design strip bounded by two column strips.

Positive and Negative Moments in Panels

M 0 is divided into + M and -M Rules given in ACI sec. 13.6.3

Moment Distribution

Positive and Negative Moments in Panels

M 0 is divided into + M and -M Rules given in ACI sec. 13.6.3 

M

u  

M

u 

M

0 

w

u

l

2

l

n 2 8

Longitudinal Distribution of Moments in Slabs

For a typical interior panel, the total static moment is divided into positive moment 0.35 M o moment of 0.65 M o . and negative For an exterior panel, the total static moment is dependent on the type of reinforcement at the outside edge.

Distribution of M 0

Moment Distribution

The factored components of the moment for the beam.

Transverse Distribution of Moments

The longitudinal moment values mentioned are for the entire width of the equivalent building frame. The width of two half column strips and two half-middle stripes of adjacent panels.

Transverse Distribution of Moments

Transverse distribution of the longitudinal moments to middle and column strips is a function of the ratio of length l 2 /l 1 , a 1 , and b t .

Transverse Distribution of Moments

Transverse distribution of the longitudinal moments to middle and column strips is a function of the ratio of length l 2 /l 1 , a 1 , and b t .

a 1 

E

cb

I

b b t

E

cs

I

s 

E

cb

C

2

E

cs

I

s

C

     1  0 .

63

x y

  

x

3

y

3 torsional constant

Distribution of M 0

ACI Sec 13.6.3.4

For spans framing into a common support negative moment sections shall be designed to resist the larger of the 2 interior M u ’s ACI Sec. 13.6.3.5

Edge beams or edges of slab shall be proportioned to resist in torsion their share of exterior negative factored moments

Factored Moment in Column Strip

a 1  Ratio of flexural stiffness of beam to stiffness of slab in direction l 1 .

b t  Ratio of torsional stiffness of edge beam to flexural stiffness of slab(width= to beam length)

Factored Moment in an Interior Strip

Factored Moment in an Exterior Panel

Factored Moment in an Exterior Panel

Factored Moment in Column Strip

a 1  Ratio of flexural stiffness of beam to stiffness of slab in direction l 1 .

b t  Ratio of torsional stiffness of edge beam to flexural stiffness of slab(width= to beam length)

Factored Moment in Column Strip

a 1  Ratio of flexural stiffness of beam to stiffness of slab in direction l 1 .

b t  Ratio of torsional stiffness of edge beam to flexural stiffness of slab(width= to beam length)

Factored Moment in Column Strip

a 1  Ratio of flexural stiffness of beam to stiffness of slab in direction l 1 .

b t  Ratio of torsional stiffness of edge beam to flexural stiffness of slab(width= to beam length)

Factored Moments

Factored Moments in beams (ACI Sec. 13.6.3) Resist a percentage of column strip moment plus moments due to loads applied directly to beams.

Factored Moments

Factored Moments in Middle strips (ACI Sec. 13.6.3) The portion of the + M u and - M u not resisted by column strips shall be proportionately assigned to corresponding half middle strips.

Each middle strip shall be proportioned to resist the sum of the moments assigned to its 2 half middle strips.

ACI Provisions for Effects of Pattern Loads

The maximum and minimum bending moments at the critical sections are obtained by placing the live load in specific patterns to produce the extreme values. Placing the live load on all spans will not produce either the maximum positive or negative bending moments.

ACI Provisions for Effects of Pattern Loads

1.

The ratio of live to dead load. A high ratio will increase the effect of pattern loadings.

2.

The ratio of column to beam stiffness. A low ratio will increase the effect of pattern loadings.

3.

Pattern loadings. Maximum positive moments within the spans are less affected by pattern loadings.

Reinforcement Details Loads

After all percentages of the static moments in the column and middle strip are determined, the steel reinforcement can be calculated for negative and positive moments in each strip.

M

u  

A

s

f

y

d

a

2 

R

u

bd

2

Reinforcement Details Loads

Calculate R  =0.9. A s u and determine the steel ratio r , where = r bd. Calculate the minimum A s from ACI codes. Figure 13.3.8 is used to determine the minimum development length of the bars.

R

u  

w

u

f

c  1  0 .

59

w

u 

w

u  r

f

y

f

c

Minimum extension for reinforcement in slabs without beams(Fig. 13.3.8)

Moment Distribution

The factored components of the moment for the beam.

Transverse Distribution of Moments

The longitudinal moment values mentioned are for the entire width of the equivalent building frame. The width of two half column strips and two half-middle stripes of adjacent panels.

Limitations of Direct Design Method