Advanced Precalculus Notes 8.6 Vectors in Space

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Transcript Advanced Precalculus Notes 8.6 Vectors in Space

Advanced Precalculus Notes 8.6 Vectors in Space

Distance Formula in Space:

d

 

x

2 

x

1

y

2 

y

1

z

2 

z

1  2 Graph the point A(-1, 3, 2) and B(4, -2, 5) Find the distance between point A and B.

Find the Position Vector of the vector

v

P

1

P

2 if P 1 = (-1, 2, 3) and P 2 = (4, 6, 2)

If v = 2i +3j – 2k and w = 3i -4j + 5k find: a) v + w b) v w c) 3v d) 2v - 3w

e) ||v||

Find a unit vector in the same direction as v = 2i -3j -6k

Find the following dot products: v = 2i -3j +6k a) v ∙ w w = 5i + 3j - k b) w ∙ v c) v ∙ v d) ||v||

Angle between Vectors: cos   ||

u u

 ||  ||

v v

|| Find the angle between u = 2i -3j +6k v = 2i + 5j k

Direction Angles of a Vector: given vector v = ai +bj +ck cos  

a

||

v

|| angle between v and the unit vector i (the positive x-axis) cos  

b

||

v

|| angle between v and the unit vector j (the positive y-axis) cos  

c

||

v

|| angle between v and the unit vector k (the positive z-axis) Find the direction angles of v = - 3i +2j – 6k

cos 2   cos 2   cos 2   1        3 3 y-axis, and an acute angle with the positive z-axis.

V

v

[(cos  )

i

 (cos  )

j

 (cos  )

k

]

Assignment: page 637: 1 – 6, 9, 15, 29, 33, 39, 47, 51, 58, 59