Transcript Title
SM2-10: Yielding & rupture criteria YIELDING AND RUPTURE CRITERIA (limit hypothesis) M.Chrzanowski: Strength of Materials 1/14 SM2-10: Yielding & rupture criteria The knowledge of stress and strain states and displacements in each point of a structure allows for design of its members. The dimensions of these members should assure functional and safe exploitation of a structure. In the simplest case of uniaxial tension (compression) it can be easily accomplished as stress matrix is represented by one component 1 only, and displacement along bar axis can be easily measured to determine axial strain 1 Measurements taken during the ? expl tensile test allow also for determination of material characteristics: elastic and plastic expl<<Rm limits as well as ultimate strength. expl<RH With these data one can easily design tensile member of a structure to assure its safety. expl = 1 =RH /s M.Chrzanowski: Strength of Materials 1 Rm RH Ultimate strength Elastic limit s-1 arctanE 1 Safety coefficient 2/14 SM2-10: Yielding & rupture criteria In the more complex states of stress (for example in combined bending and shear) the evaluation of safe dimensioning (related to elastic limit) becomes ambiguous. txz tzx z Do we need to satisfy two independent conditions x< RH x x tzx txz tx< RH where RHt i RHs denote elastic limits in tension and shear, respectively? x z x Transformation to the principal axis of stress matrix does not help either, as we do not know whether the modulus of combined stresses is smaller then RH … Thus, we need to formulate a hypothesis defining which stress components should be taken as basis for safe structure design. M.Chrzanowski: Strength of Materials 3/14 SM2-10: Yielding & rupture criteria In general case of 3D state of stress we introduce a function in 9-dimensional space of all stress components (or 3-dimensional in the case of principal axes) which are called the exertion function: W F ( ij ) f (1 , 2 , 3 ) 0 Wlim W Wlim In uniaxial sate of stress: We postulate that exertion function will take the same value in given 3D state of stress as that in uniaxial case. The solution of this equation with respect to 0: W W0 F ( 0 ) W F ( ij ) F ( 0 ) 0 ( ij ) is called substitute stress according to the adopted hypothesis defining function F and thus – function , as well. M.Chrzanowski: Strength of Materials 4/14 SM2-10: Yielding & rupture criteria Let the exertion measure be: p mW p stress vector in main principal axis 2 RNR N RN 3 2 W p 12 22 32 W0 02 W W0 The ratio: f 1, 2 , 2 12 22 32 0 RN R 0 0 N 1 RN gives „the distance” from unsafe state. This distance can be dealt with as the 1 exertion in a given point. SUCH A HYPOTHESIS DOES NOT EXIST ! A very similar one, which does exist mW max1 , 2 , 3 is called Gallieo-Clebsh-Rankine hypothesis Associated function appears to bo not-analytical one (derivatives on edges are indefinable) M.Chrzanowski: Strength of Materials 5/14 SM2-10: Yielding & rupture criteria GALIEO-CLEBSH-RANKINE hypothesis (GCR) mW max1 , 2 , 3 2 RN RN 1 RN 1 RN RN 1 RN 2 RN RN 2 RN 3 RN RN 3 RN RN RN 3 RN For plane stress state it reduces to a square. M.Chrzanowski: Strength of Materials It is seen, that materials which obey this hypothesis are isotopic with respect to their strength. They are also isonomic, as their strength properties are identical for tension and compression. 6/14 2 RN SM2-10: Yielding & rupture criteria 1 Exertion ≤ 100% Exertion ≤ 80% 1 1 RN 1 Exertion ≤ 60% Exertion ≤ 40% 1 Exertion 0% 1 2 RN 1 1 1 RN 1 M.Chrzanowski: Strength of Materials 7/14 SM2-10: Yielding & rupture criteria GALILEO hypothesis 2 Material isonomic and isotropic RNr RNtesion RNcomrpessio n RNr sc N R Material insensitive to compression. (classical Galileo hypothesis) mW max 1 , 2 , 3 1 RNsc Material isotropic but not isonomic where a a when a>0 0 when a<0 M.Chrzanowski: Strength of Materials RNtension RNcompressio n 8/14 SM2-10: Yielding & rupture criteria 2 1 t For torsion: COULOMB-TRESCA-GUEST hypothesis CTG 2 t 0 T 0 t 2 RNr RNr Many materials are sensitive to torsion This hexagon represents CoulombTresca hypothesis (for plane stress state); the measure of exertion is maximum shear stress: R mW maxt1 , t 2 , t 3 1 2 2 3 3 1 mW max , , 2 2 2 In uniaxial state of stress: mW0 max o 2 M.Chrzanowski: Strength of Materials RNr sc N RNsc 1 Uniaxial tension 1 RNr 0 max1 2 , 2 3 , 3 1 9/14 SM2-10: Yielding & rupture criteria HUBER-MISES-HENCKY hypothesis HMH 2 Small but important improvement has been made by M.T. Huber followed by von Mises and Hencky: RN It is distortion energy only which decides on the material exertion: 1 D D 2 1 1 f v D D A A 2 2 mW f RN RN For elastic materials (Hooke law obeys): 1 1 1 2 2 2 3 2 3 1 2 ij ij 3 m2 4G 6G In uniaxial state of stress: f 0f 1 2 02 6G 0 1 2 1 RN 1 2 2 2 3 2 3 1 2 In 3D space of principal stresses (Haigh space) this hypothesis is represented by a cylinder with open ends. In 2D plane stress state for 3 0 is an ellipse shown above. M.Chrzanowski: Strength of Materials 10/14 SM2-10: Yielding & rupture criteria Hypothesis GCR Maximum normal stress Exertion measure CTG Maximum shear stress 2 2 RN RN RN RN 1 Substitute stress for beams 0 max(1 , 2 ) 0 1 x x2 4t xy2 2 M.Chrzanowski: Strength of Materials RN RN RN RN Substitute stress Circular cylinder with uniformly inclined axis 2 RN 2D image Deformation energy Hexagonal prism with uniformly inclined axis Cube with sides equal to 2R 3D image HMH 0 1 2 0 x2 4t xy2 1 RN RN 1 RN 0 12 22 1 2 0 x2 3t xy2 11/14 SM2-10: Yielding & rupture criteria stop M.Chrzanowski: Strength of Materials 12/14