Transcript Jawaban UTS VARKOM
UTS VARKOM SOAL#1
SOAL#1.A
SOAL#1
F
(
s
)
F
(
s
)
s
2
s
e
s s
(
s
2
s
s
s
1 1 )
s
(
s
2
s
1 )
s
(
s
2
s
2
s s
1 )
s
(
s
2
e
s
s
1 )
s
(
s
2
e
s
s
1 )
F
(
s
)
s
2
s
1
s
1
e
s
s
(
s
2 1
s
1 )
Pecahan Parsial
s
(
s
2 1
s
1 )
A
s s
2
Bs
C s
1
s
0
A
1
s B
Bs
2
s
1
s
2
C s
1
C s
2
s
2 1 1
s s
s
1 1 1 0 2 0
s
2
Bs
1 2 0 0
s
1
Cs
1 1
B
1 0
B
1
C
1 0
C
1
Pecahan Parsial
s
(
s
2 1
s
1 )
s
(
s
2 1
s
1 ) 1
s
1
s
s
2
s
1
s
1
s
2
s
1
s
1
Masukkan Hasil Pecahan Parsial
F
(
s
)
F
(
s
)
s
2
s
1
s
1
e
s
s
2
s
1
s
1
e
s
1
s s
(
s
2 1
s
1 )
s
2
s
s
1 1
Manipulasi Penyebut menjadi pergeseran sumbu S
F
(
s
)
s
2
s
1
s
1
e
s
1
s s
2
s
1
s
1
F
(
s
)
s
2
s s
1 1 4 3 4
e
s
1
s
s
2
s s
1 1 4 3 4
F
(
s
)
s
s
1 2 2 1 3 4
e
s
1
s
s
s
1 2 2 1 3 4
Sesuaikan Pembilang menjadi pergeseran sumbu S
F
(
s
)
F
(
s
)
F
(
s
)
s
s
1 2 2 1
s s
1 2 1 2 2 1 2 3 4
s s
1 2 1 2 2 1 2 3 4 3 4
e
s
e
s
e
s s s s
1 1 1
s
s
1 2 2 1
s s
1 2 1 2 2 1 2 3 4
s s
1 2 1 2 2 1 2 3 4 3 4
Inversekan Terpisah biar gak Pusing
F
(
s
)
G
(
s
)
s s
s s
1 2 1 2 2 1 2 1 2 2 1 1 2 2 3 4 3 4
e
s s
1
s s
1 2 1 2 2 1 2 3 4
F
(
s
)
f
(
t
)
G
(
s
)
e
s s g
(
t
) ( 1
g
(
t G
(
s
) 1 )
u
(
t
1 )
Inverse Laplace dari G(s)
G
(
s
)
G
(
s
)
G
(
s
)
s s
1 2 1 2 2 1 2 3 4
s s
s
s
1 2 2 1 2 1 2 2 1 2 3 4 3 4
g
(
t
)
e
1 2
t
cos 2 3
s
s
1 2 2 2 1 (
s
2 1 )( 2 1 2 3 )( 2 2 3 3 4 ) 3 4 1 3
e
1 2
t
3
s
( 3 1 2 2 2 ) sin 2 3
s
1 1 2 2 2 3 4 3 4
Maka inverse Laplace dari F(s) adalah
g
(
t
)
e
1 2
t
cos 2 3
t
e
1 2
t
3 sin 2 3
t g
(
t
1 )
e
1 2 (
t
1 )
f
(
t
) cos 2 3
g
(
t
) ( 1
g
(
t
(
t
1 )
e
1 2 (
t
1 ) 1 )
u
(
t
1 ) 3 sin 2 3 (
t
1 )
f
(
t
)
e
1 2
t
cos 2 3
t
e
1 2
t
3 sin 2 3
t
1
e
1 2 (
t
1 ) cos 2 3 (
t
1 )
e
1 2 (
t
1 ) 3 sin 2 3 (
t
1 )
u
(
t
1 )
SOAL#1.B
Maka inverse Laplace dari F(s) adalah
f
(
t
)
t
2
u
(
t
1 )
f
(
t
) (
t
( 1 1 )) 2
u
(
t
1 )
f
(
t
) ((
t
1 ) 1 ) 2
u
(
t
1 )
f
(
t
) ((
t
1 ) 2 2 (
t
1 ) 1 )
u
(
t
1 )
F
(
s
)
e
s
2
s
3 2
s
2 1
s