Transcript How do you handle the calculations and data for the gas law lab

How do you handle the calculations
and data for the gas law lab (molar
mass of butane)?
February 27
Finishing up the Gas Unit
Data
Calculations: Trial 1
Trial 1
Atmospheric Pressure (PT)
759.0 mmHg
Water Temperature in K
24.5 C or
297.5 K
Water vapor pressure at
temperature recorded.
23.1 mmHg
Click on number
for water vapor
table.
16.9523 g
Initial Mass of Lighter
Calculate pressure of gas sample:
PT = Pgas + Pwater
759.0 mmHg = Pgas - 23.1 mmHg
Pgas = 735.9 mmHg or 0.9683 atm
Calculate mass of butane in gas sample:
Mass of butane = Initial mass – Final mass
Calculate moles of butane in gas sample:
PV = nRT
16.8501g
Calculate molar mass for this Trial:
Mass of butane / Moles of butane
Final Mass of Lighter.
Volume of gas sample in
Liters
47.80 mL or
0.04780 L
Finishing up the Gas Unit
Calculations: Trial 1
Data
Trial 1
Atmospheric Pressure (PT)
759.0 mmHg
Water Temperature in K
24.5 C or
297.5 K
Water vapor pressure at
temperature recorded.
23.1 mmHg
16.9523 g
Calculate pressure of gas sample:
PT = Pgas + Pwater
Calculate mass of butane in gas sample:
Mass of butane = Initial mass – Final mass
16.9523 g – 16.8501 g = 0.1002 g
Calculate moles of butane in gas sample:
PV = nRT
Initial Mass of Lighter
16.8501g
Final Mass of Lighter.
Volume of gas sample in Liters
47.80 mL or
0.04780 L
Calculate molar mass for this Trial:
Mass of butane / Moles of butane
Finishing up the Gas Unit
Calculations: Trial 1
Data
Trial 1
Atmospheric Pressure (PT)
759.0 mmHg
Water Temperature in K
Water vapor pressure at
temperature recorded.
24.5 C or
297.5 K
23.1 mmHg
16.9523 g
Calculate pressure of gas sample:
PT = Pgas + Pwater
759.0 mmHg = Pgas + 23.1 mmHg
Pgas = 735.9 mmHg or 0.9683 atm
Calculate mass of butane in gas sample:
Calculate moles of butane in gas sample:
PV = nRT
0.9863 atm ( 0.04780 L) = n (.0821 Latm/(molK) 297.5K
Initial Mass of Lighter
0.9863 X 0.04780 / 0.0821/297.5 =
16.8501g
Final Mass of Lighter.
Volume of gas sample in Liters
47.80 mL or
0.04780 L
0.001930 moles
Calculate molar mass for this Trial:
Mass of butane / Moles of butane
Finishing up the Gas Unit
Calculations: Trial 1
Data
Calculate pressure of gas sample:
Trial 1
Atmospheric Pressure (PT)
759.0 mmHg
Water Temperature in K
24.5 C or
297.5 K
Water vapor pressure at
temperature recorded.
23.1 mmHg
16.9523 g
Calculate mass of butane in gas sample:
Mass of butane = Initial mass – Final mass
16.9523 g – 16.8501 g = 0.1022 g
Calculate moles of butane in gas sample:
PV = nRT
0.001930 moles
Initial Mass of Lighter
16.8501g
Final Mass of Lighter.
Volume of gas sample in Liters
47.80 mL or
0.04780 L
Calculate molar mass for this Trial:
Mass of butane / Moles of butane
0.1022 g / 0.001930 = 52.95 g/mol