Transcript Slide 1

Force changes motion
Hooke’s law
 Hooke’s Law = law of elasticity by Robert Hooke
 Hooke’s law states that the extension produced in the spring is
proportional to the force exerted.
 In symbol: F = k x d
F = Force (Newtons) k = constant spring
d = elongation (meter) or extension
The force exerted by the spring is always in the direction to its
displacement (elongation) from the equilibrium position. A
spring always wants to return to its original position. The spring
force is commonly called as restoring force.
Hooke’s law applies to the idealized case of a
spring. The further you stretch the spring, the
greater the force opposing the stretching. It
assumes that the force increases linearly with
distance.
In the figure below, the first spring is still unstretched. When
a force is applied, this results to an elongation x. As the force
is doubled, the elongation x is also doubled.
In the y-axis, the force in N is indicated. The force measures from 1 N
to 4 N. In the x-axis, the extension or elongation in m is indicated. It
shows that the elongation measures 0.1 to 0.4.
At 1N of force, the extension is 0.1 m.
At 2N force, extension is 0.2m; 3N is 0.3m
at 4N force, the extension is 0.4m
Sample Problems
If a force of 53 N stretches a spring 8 cm with the force,
what is the constant of elasticity or k? How far will the
spring stretch when a force of 133 N is applied?
Force = constant x elongation
F=kxd
Solution: Given: Force = 53 N
elongation = 8 cm or
8 cm --- change to meter
8 / 100 = .08 m (1 m=100 cm)
k = Force / elongation
k = 53N / .08 m = 662.5
1.
k = 662.5
F = 133N
elongation = ?
elongation = F / k
elongation = 133 / 662.5
elongation (d) = 0.20 m
Elastic Body and plastic body
Elastic body – substances which regains or change back
to its original shape and size after moving the force
applied to it.
Plastic body – substances or objects which completely
looses its original shape and size after removing the
force applied to it.
Examples of elastic bodies
Steel ball – perfectly elastic – it absorbs energy and gives
back the energy when a force is removed from it.
IGCSE Sample Problem 1:
Set up the experiment to find the spring constant
of a steel spring. The apparatus is shown in Fig. 1.1.
The student recorded the un-stretched length lo
of the spring. The she added loads W to the spring,
recording new length l each time. The readings are
shown in the table.
The un-stretched length lo = 30 mm.
Sample problems – igcse
Weight or Force
(N)
Length – l (mm)
Elongation (mm)
0
30 mm
e = 30 mm – 30 mm = 0
1
32 mm
e = 32 mm – 30 mm = 2 mm
2
33 mm
e = 33 mm – 30 mm = 3 mm
3
36 mm
e = 36 mm – 30 mm = 6 mm
4
39 mm
e = 39 mm – 30 mm = 9 mm
5
40 mm
e = 40 mm – 30 mm = 10 mm
6
42 mm
e = 42 mm – 30 mm = 12 mm
Calculate the extension e of the spring produced by each load, using the equation
e = (l – lo) or elongation = new length – un-stretched length
At F = 0; the elongation e = 30 mm – 30 mm = 0
At F = 1N; e = 32 mm – 30 mm = 2 mm;
Let us use the data above to construct the graph.
The y-axis denotes the elongation in mm.
The x-axis represents the weight or load in N.
elongation (mm)
12
10
8
6
4
2
0
1
2
3
4
5
Load W in Newtons
6
Draw a straight line of the points you plotted. Calculate
the gradient of the line.
Gradient of the elongation – load graph: = spring constant
elongation
Gradient = --------------- = spring constant k
load
2
Gradient = ------ = 2
1
gradient = 3-2 / 2-1 = 1/1 = 1
gradient = 6-3 / 3-2 = 3/1 = 3
gradient = 9 – 6 / 4-3 = 3/1 = 3
gradient = 10-9 / 5-4 = 1/1 = 1
gradient = 12 – 10 / 6-5 = 2/1 = 2
An IGCSE student is investigating the relationship between the
extension of a spring of un-stretched length lo and the load
hung on the spring.
a) Consider the readings that the student should take and
write appropriate column headings with units in the table
below.
b) The student decides to repeat the experiment using a
spring made of a different metal in order to study how the
extension may be affected by the metal from which the
spring is made. To make a fair comparison, other variables
must be kept constant. What are some of the variables that
the student may be made constant?
1) Length of spring
2) Diameter or thickness of spring
3) Range of loads
4) Length of wire
5) Thickness of wire
6) Number of coils
7) Spacing of coil
Additional Problems
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