Transcript Document

General 2002
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General 2002
Paper 2
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Paper1 Q1
(a)
8
9.2 0
- 3.71
5.4 9
(c)
687
(d)
(b)
11 1
 300
= 687
5.49
+ 6.47
1
11 .9 6
 100  3
7.29
x 2 78
5 8.32
2 . 29
2
3 6.87
3
3 11
33
1
3 2  

 8
4
1 4
4
4
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General 2002
Paper1 Q2
(a)
P( yellow)
number of favourable outcomes

number of possible outcomes
3

15
(b)
1

5
New total =14
P( pink )
number of favourable outcomes

number of possible outcomes
6
3


14
7
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Paper1 Q3
General 2002
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General 2002
Paper1 Q4
30 % of 5 million;
10% =
5 000 000
500 000
30% = 1 500 000
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Paper1 Q5
(a)
A (-4,-3)
B (3,-1)
C (4,4)
y
6
C
4
D
-6
-4
(b)
2
-2
2
-2
A
Gradient of AB =
-4
-6
4
B
6
x
vert
hor
2

7
(c)
D ( -3,2)
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General 2002
Paper1 Q6
0.404
1
4
41%
0.04
4
10
Change into decimals to compare.
0.404
0.25
0.41
0.04
0.4
0.04
0.25
0.4
0.404
0.41
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General 2002
Paper1 Q7
O
26
26
A
C
BCO  90
AB is a tangent ;
Triangle AOB is isosceles ;
So
B
CAO  CBO  26
COB  180  90  26
(Angles in a triangle)
 64
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Paper1 Q8
General 2002
100
90
80
70
Mathematics 60
marks 50
(c)
Maths mark =
54%
40
30
(estimate)
20
10
0
10 20 30 40 50 60 70 80 90 100
Science marks
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General 2002
Paper1 Q9
Week
one
Week
two
Growth
Plant A
29 cm
57 cm
57 – 29 = 28 cm
Plant B
46 cm
71 cm
71 – 46 = 25 cm
Plant A has grown more by 3 cm .
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General 2002
Paper1 Q10
Each tyre spends one fifth of it’s time in the trunk.
So
Each tyre does
1
 4 000miles
5
4
of 20 000miles
5
4
 16 000miles
5
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General 2002
Paper2 Q1
45 mins =
List ;
•
•
•
D
S
T
=
=
=
?
76 km/h
3 hrs 45 mins
45/60 hrs = 0.75 hrs
= 3.75 hrs
D=SxT
D
= 76 x 3.75
S T
= 285 km
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General 2002
Paper2 Q2
(a)
VAT =
17.5% of £779
=
17.5/100 x 779
=
136.325
=
£ 136.33
Total cost = 779 + 136.33
= £ 915.33
(b)
Difference = 915.33 - 900
= £ 15.33
Refund
= 15.33 x 2 = £ 30.66
(Double the difference)
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General 2002
Paper2 Q3
V=
(a) From formula sheet;
r
2
h
= 3.14 x (20)2 x 450
= 565486.68
= 565 000 cm 3
(b)
450 cm
40 cm
5 6 5 0 0 0 = 5.65 x 10 5
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General 2002
Paper2 Q4
1 section
2 sections
3 sections
(a)
Number of sections(s)
Number of iron bars (b)
(b)
1
8
2
3
22
15
+7
+7
4
12
29
85
+7
Number of iron bars = Number of sections x 7
b = 7s +1
+ 1
12 x 7+1
(c)
176 = 7s +1
175 = 7s
s = 25
25 sections
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General 2002
Paper2 Q5
Find 4.5% of £1640
This is for
12 months
4.5
 1640
Yearly interest =
100
Monthly interest =
73.80
12
9 months interest =
6.15  9
 73.80
 6.15
 £ 55.35
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General 2002
Paper2 Q6
PP
In a rhombus, diagonals are bisected at right angles.
10 cm
S
6 cm
Q 20 cm
Q
O
tan xo =
A
SOHCAHTOA
10

6
= 1.667
R
12 cm
xo =
O
T A
tan –1 (1.67)
= 59 o
Therefore
PQR  2  59  118
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General 2002
Paper2 Q7
x
20 cm
120 cm
30cm
According to Pythagoras:
x2 = 1802 + 1202
180
Bathcm
= 32400 + 14400
= 46800
x =
46800 = 216.33 cm
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General 2002
Paper2 Q8
(a)
Scale 1:2
T
HP (15 cm)
7.5 cm
HT (20 cm)
Rod (35 cm)
10 cm
17.5 cm
H
P
(b)
By measuring PT on your drawing you get;
12.5 cm
So
Actual length of PT = 2 x 12.5
= 25 cm
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General 2002
Paper2 Q9
(a)
4 ( 3x + 2) = 68
12x + 8 = 68
12x
= 60
x
=5
(b)
10y +15
= 5 (2y +3 )
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General 2002
Paper2 Q10
A
Length of metal
120 cm
(a)
Length of curve
(b)
B
edge needed
d 2
   120  2
 188.5 cm
Length of metal edge
 308.5 16
 4936 cm
 49.36 m
50m will
be enough!
 188.5  120
 308.5 cm
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General 2002
Paper2 Q11
Hire purchase price =
Deposit + Total instalments
Find these to calculate this
“ The hire
hire purchase
purchase price
price = cash price x 1.22
is 22% more than
= 6300 x 1.22
the cash price”
= £ 7686
Each instalment = 6741  60
“….requires a deposit
deposit, = 15% of £6300
which is 15% of
= £ 112.35
=
0.15
x
6300
the cash price”
= £945
Total instalments = Hire purchase price - Deposit
= 7686 - 945 = £ 6741
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