Transcript Slide 1

9.
2 C3H7OH + 9 O2
→ 6 CO2 + 8 H2O
Identify some mole ratios, using the given equation for the
combustion of isopropyl alchol.
a)
6 mol CO2
2 mol C3H7OH
d)
8 mol H2O
2 mol C3H7OH
b)
2 mol C3H7OH
9 mol O2
e)
6 mol CO2
8 mol H2O
c)
9 mol O2
6 mol CO2
f)
8 mol H2O
9 mol O2
10.Mole Ratios
Identify some mole ratios, using the given equation.
3 CaCl2 + 2 H3PO4
→ Ca3(PO4)2 + 6 HCl
a)
3 CaCl2
1 Ca3(PO4)2
b) 6 HCl
2 H3PO4
c)
3 CaCl2
2 H3PO4
d)
1 Ca3(PO4)2
2 H3PO4
e) 6 HCl
1 Ca3(PO4)2
f)
2 H3PO4
6 HCl
11.
C2H5OH + 3 O2 →
2 CO2 + 3 H2O
How many moles of CO2 can be produced from
7.75 mol C2H5OH?
7.75 mol C2H5OH
2 mol CO2 = 15.5 mol CO2
1 mol C2H5OH
or
2 mol CO2 =
X
= 15.5 mol CO2
1 mol C2H5OH 7.75 mol C2H5OH
12. 4 HCl + O2 → 2 Cl2 + 2 H2O
How many moles of Cl2 can be produced from
5.60 mol HCl?
5.60 mol HCl
2 mol Cl2 =
4 mol HCl
2.80 mol Cl2
or
2 mol Cl2 =
X
= 2.80 mol Cl2
4 mol HCl
5.60 mol HCl
13. MnO2 + 4 HCl → Cl2 + MnCl2 + 2 H2O
How many moles of HCl will react with
1.05 mol MnO2?
1.05 mol MnO2 4 mol HCl = 4.20 mol HCl
1 mol MnO2
or
1.05 mol MnO2 = 1 mol MnO2
X mol HCl
4 mol HCl
X = 4.20 mol HCl
14. Al4C3 + 12 H2O
→
4 Al(OH)3 + 3 CH4
a) How many moles of water are needed to react with 100. g Al4C3 ?
100.0 g Al4C3 1 mol Al4C3 12 mol H2O = 8.333 mol H2O
144.0 g Al4C3 1 mol Al4C3
b) How many moles of Al(OH)3 will be produced when 0.600 mol
of CH4 is formed?
0.600 mol CH4
4 mol Al(OH)3 = 0.800 mol Al(OH)3
3 mol CH4
15.
Ca(OH)2 + Na2CO3
→
2 NaOH + CaCO3
How many grams of sodium hydroxide can be produced from
500. g of calcium hydroxide according to this equation?
1 mole Ca(OH) 2 = 74.1 g Ca(OH) 2 = 500. g
2 moles NaOH
80.0 g NaOH
x
74.1 x = 40000
x = 540. g NaOH
16. How many grams of zinc phosphate, Zn3(PO4)2,
are formed when 10.0 g of Zn are reacted with
phosphoric acid?
3 Zn + 2 H3PO4
10.0 g
→ Zn3(PO4)2 + 3 H2
?g
3 mol Zn
=
1 mol Zn3(PO4)2
196.2 g Zn
386.1 g Zn3(PO4)2
196.2 g Zn
=
386.1 g Zn3(PO4)2
10.0 g Zn
X g Zn3(PO4)2
X = 19.7 g Zn3(PO4)2
17.
Fe2O3 + 3C
→
2Fe + CO
How many kilograms of iron would be
formed from 125 kg of Fe2O3?
1 mole Fe2O3 = 0.1598 kg = 125 kg
2 mole Fe 0.1118 kg
x
0.1598 x = 13.975
x = 13.975 = 87.5 kg Fe
0.1598
18.How many grams of steam and iron must react to
produce 375 g of magnetic iron oxide, Fe3O4?
3 Fe + 4 H2O
→ Fe3O4 + 4 H2
3 mol Fe = 167.4 g Fe
= X g Fe
1 mol Fe3O4
231.6 g Fe3O4
375 g Fe3O4
X = 271 g Fe
4 mol H2O = 72.0 g H2O = X g H2O
1 mol Fe3O4
231.6 g Fe3O4
375 g Fe3O4
X = 117 g H2O
19. a.
2C2H6 + 7O2
→
4CO2 + 6H2O
How many moles of O2 are needed for the complete combustion
of 15.0 mol of ethane?
7 mole O2
2 mole C2H6
=
X mole O2
15 mole C2H6
2x = 105
x = 52.5 mole O2
19 b.
2C2H6 + 7O2 →
4CO2 + 6H2O
How many grams of CO2 are produced for each 8.00 g of H2O
produced?
4 mole CO2 = 176 g CO2 = Xg CO2
6 mole H2O
108 g H2O 8.00gH2O
108x = 1408
x = 1408 = 13.0 g CO2
108
19 c.
2C2H6 + 7O2 →
4CO2 + 6H2O
How many grams of CO2 will be produced by the combustion of 75.0 g of C2H6?
4 mole CO2 =
2 mole C2H6
2 = 88.0 g CO2
1 30.0g C2H6
=
x
75.0
30x = 6600
x = 6600 = 220. g CO2
30
20. 4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2
(a)How many moles of Fe2O3 can be made from
1.00 mol of FeS2 ?
4 mol FeS2
2 mol Fe2O3
=
1.00 mol FeS2
X mol Fe2O3
X = 0.500 mol Fe2O3
20. 4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2
(b) How many moles of O2 are required to react with
4.50 mol of FeS2 ?
4 mol FeS2
11 mol O2
=
4.50 mol FeS2
X mol O2
X = 12.4 mol O2
20. 4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2
(c) If the reaction produces 1.55 mol of Fe2O3 , how
many moles of SO2 are produced?
2 mol Fe2O3 = 1.55 mol Fe2O3
8 mol SO2
X mol SO2
X = 6.20 mol SO2
20. 4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2
(d) How many grams of SO2 can be formed from
0.512 mol of FeS2 ?
0.512 mol FeS2 8 mol SO2
4 mol FeS2
1.02 mol SO2
64.1 g SO2
1 mol SO2
= 1.02 mol SO2
= 65.4 g SO2
20. 4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2
(e) If the reaction produces 40.6 g of SO2 , how
many moles of O2 were reacted?
40.6 g SO2
1 mol SO2
64.1 g SO2
0.633 mol SO2 11 mol O2
8 mol SO2
=
0.633 mol SO2
= 0.870 mol O2
20. 4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2
(f) How many grams of FeS2 are needed to produce
221 g of Fe2O3 ?
221 g Fe2O3
1 mol Fe2O3 = 1.38 mol Fe2O3
159.7 g Fe2O3
1.38 mol Fe2O3
4 mol FeS2
2 mol Fe2O3
2.76 mol FeS2
120.0 g FeS2
1 mol FeS2
= 2.76 mol FeS2
= 331 g FeS2
20. 4 FeS2 + 11 O2 → 2 Fe2O3 + 8 SO2
(f) How many grams of FeS2 are needed to produce
221 g of Fe2O3 ?
4 mol FeS2 = 480.0 g FeS2 = X g FeS2
2 mol Fe2O3
319.4 g Fe2O3
221 g Fe2O3
X = 332 g FeS2
22.
a) 2 Bi(NO3)3 + 3 H2S → Bi2S3 + 6 HNO3
50.0 g
6.00 g
?g
2 Bi(NO3)3 = 790 g Bi(NO3)3 = 50.0 g Bi(NO3)3
1 Bi2S3
514.3 g Bi2S3
X grams Bi2S3
X = 32.6 grams
3 H2S = 102.3 g H2S = 6.00 g H2S
1 Bi2S3 514.3 g Bi2S3 X g Bi2S3
H2S limits
X = 30.2 grams
22.
b.) 3 Fe + 4 H2O → Fe3O4 + 4 H2
40.0 g 16.0 g
? grams
3Fe = 167.4 g Fe = 40.0 g Fe x= 1.91 g H2
4H2
8.0 g
x g H2
4H2O = 1H2O = 18.0g H2O = 16.0 g H2O
4H2
1H2
2.0 g H2
x g H2
H2O limiting
x= 1.78 g H2
23) a)
C3H8 + 5 O2 → 3 CO2 + 4 H2O
20.0 g 20.0 g ? mol
20.0 g C3H8 1 mol C3H8 3 mol CO2 = 1.36 mol CO2
44.0 g C3H8 1 mol C3H8
20.0 g O2 1 mol O2 3 mol CO2 = 0.375 mol CO2
32.0 g O2 5 mol O2
23 b)
C3H8 + 5 O2 → 3 CO2 + 4 H2O
20.0 g 80.0 g ? mol
20.0 g C3H8 1 mol C3H8 3 mol CO2 = 1.36 mol CO2
44.0 g C3H8 1 mol C3H8
80.0 g O2 1 mol O2 3 mol CO2 = 1.50 mol CO2
32.0 g O2 5 mol O2
24.
C3H8 + 5O2
a)
5.0 mole
5.0 mole
→
3CO2 + 4H2O
? Moles
1C3H8 = 5C3H8
3 CO2
X
X = 15 mole CO2
5O2 = 5
3CO2 X
X = 3.0 mole CO2
O2 limits
24. C3H8 + 5O2
3.0 mole
b)
→
20. mole
3CO2 + 4H2O
? moles
1 mole C3H8 = 3.0 C3H8
3 mole CO2
X
X = 9.00 mole CO2
C3H8 limits
5 mole O2 = 20. O2
3 mole CO2
X
X = 12 mole CO2
24. C3H8 + 5O2
3.0 mole
→
20. mole
3CO2 + 4H2O
? moles
24c)
1 C3H8 = 20 C3H8
3 CO2
X
X = 60 mol CO2
5 O2
3 CO2
= 3 O2
X
X = 1.8 mol CO2
O2 limits
27)
2 Al + 3 Br2 →
25.0 g 100.0 g
2 AlBr3
?g
If 64.2 g of AlBr3 is recovered, what is the percent yield?
2 mol Al = 54.0 g Al
= 25.0 g Al
2 mol AlBr3 533.4 g AlBr3 X g AlBr3
X = 247 g
3 mol Br2 = 479.4 g Br2 = 100.0 g Br2 X = 111.3 g
2 mole AlBr3 533.4 g AlBr3
X g AlBr3
% yield = Actual (lab)
x 100 = 64.2 g = 57.7 %
Calculated (theory)
111.3 g