Transcript Chapter 26

Last time…
Equipotential
lines
Capacitance and
capacitors
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V  Q
C
1
Parallel plate capacitor
V  Q /C
C
o A
d
-Q
Geometrical factor
determined from electric
fields
+Q
Energy stored in parallel-plate capacitor
1
1 o A
1
2
2
U  CV  
Ed  Ado E 2
2
2 d
Energy density
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2
1
U /Ad  o E 2
2
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d
2
Quick Quiz
An isolated parallel plate capacitor has charge Q and potential V.
The plates are pulled apart.
+
Which describes the situation afterwards?
-Q
+Q
-
pull
-
d
+
+
pull
+
A) Charge Q has decreased
Cap. isolated  Q constant
B) Capacitance C has increased
C = 0A/d  C decreases
C) Electric field E has increased
E = (Q/A)/0  E constant
D) Voltage difference V between
plates has increased
V= Ed  V increases
E) None of these
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Quick Quiz
An isolated parallel plate capacitor has
a charge q. The plates are then pulled
further apart. What happens to the
energy stored in the capacitor?
-q
+
+
-
1) Increases
pull
-
2) Decreases
d
+
+q
pull
+
3) Stays the same
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Different geometries of capacitors
+Q
-Q
+Q
-Q
A
L
d
Parallel plate
capacitor
Q o A
C

V
d
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Spherical
capacitor
1 1 1
Q
C
 4o   
a b 
V
Physics 208 Lecture 12
Cylindrical
capacitor
Q
2o L
C

V lnb /a
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Combining Capacitors — Parallel

Connect capacitors together with metal wire
C1
Ceq
C2
“Equivalent” capacitor
Potential difference V
Both have same V
Need different charge
Q1  C1 /V
Q2  C2 /V
Q on each is same
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Oct. 9, 2007
Total charge Qeq  Q1  Q2
Ceq 
Qeq
V

Physics 208 Lecture 12
Q1  Q2
 C1  C2  Ceq
V

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Combining Capacitors — Series
VA
C1
Q
Vm
Q
VA
-Q
C2
-Q
-Q
VB
VB
V  VA  VB
 V1  V2
Q Q
Q
V   
C1 C1 Ceq
V1  VA  Vm  Q /C1
V2  Vm  VB  Q/C2

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Ceq
Q
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1
1
 
Ceq C1 C2
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Current in a wire:
not electrostatic equilibrium

Battery produces
E-field in wire

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Charge moves in
response to E-field
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Electric Current

Electric current = I = amount of charge per unit time flowing
through a plane perpendicular to charge motion

SI unit: ampere 1 A = 1 C / s

Depends on sign of charge:


+ charge particles:
current in direction of particle motion is positive
- charge particles:
current in direction of particle motion is negative
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Quick Quiz

An infinite number of positively charged particles are
uniformly distributed throughout an otherwise empty
infinite space.
A spatially uniform positive electric field is applied.
The current due to the charge motion
A. increases with time
B. decreases with time
C. is constant in time
D. Depends on field
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Constant force qE
Produces constant accel. qE/m
Velocity increases v(t)=qEt/m
Charge / time crossing plane
increases with time
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But experiment says…


Current constant in time
Proportional to voltage
1
I V
R


Also written J 


R = resistance (unit Ohm = )
1

V
J = current density = I / (cross-section area)
 = resistivity = R x (cross-section area) / (length)


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Resistivity is independent of shape
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Charge motion with collisions




Wire not empty space, has various fixed objects.
Charge carriers accelerate, then collide.
After collision, charged particle reaccelerates.
Result: average “drift” velocity vd
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Current and drift velocity

This average velocity
called drift velocity

This drift leads to a current


e  
v d   E
m 
 e 2
I  ene Av d  ne
m

Current density J

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
AE

Conductivity
n e e 2
J  I/A  
E  E
m
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Electric field
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What about Ohm’s law?

Current density proportional to electric field
J  E


Current proportional to current density through
geometrical factor
Electric field proportional to electric potential through
geometrical factor
I  JA  AE 
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A
L
EL  V /R
Physics 208 Lecture 12
L
L
R

A
A
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Resistivity

Resistivity


A
R
L
Independent of
sample geometry
SI units Ω-m
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Resistors
Circuits
Physical layout
Schematic layout
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Quick Quiz
Which bulb is brighter?
A. A
B. B
C. Both the same
Current through each must be same
Conservation of current (Kirchoff’s current law)
Charge that goes in must come out
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I2
Current conservation
Iin
I1
I3
I1=I2+I3
I1
I3
Iout
Iout = Iin
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I2
I1+I2=I
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Quick Quiz
How does brightness of bulb B compare to that of A?
A. B brighter than A
B. B dimmer than A
C. Both the same
Battery maintain constant potential difference
Extra bulb makes extra resistance -> less current
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