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3.2 Species overall mass-balance equation 3.2.1 Derivation Consider an arbitrary stationary control volume Ω bounded by surface A through which a moving fluid is flowing, as illustrated in Fig. 3.2-1. The control surface A can be consider to consist of three different regions. A Ain Aout Awall [3.2-1] Consider the transfer rate of species A through dA shown in Fig. 3.2-2a. As shown in Fig. 3.2-2b, the outward transfer and inward transfer rate are ja•ndA and -ja•ndA, respectively. Consider the mass conservation law for species A in the control volume shown in Fig.3.2-1: Rate of Rate of Rate of species A species A in species A out accumulation by mass inflow by mass outflow (1) (2) Rate of other species A transfer to system from surroundings (4) (3) Rate of species A generation in system [3.2-3] (5) 19 Term 1: Mass of species A in the control volume Ad (int egral ) ; M A (overall ) The rate of change in the mass of species A in Ω d (int egral ) ; M A (overall ) term (1) A d dt t Terms 2&3: Mass flow rate of species A through a differential area dA A v ndA (int egral ); A ( A vdA)in -( A vdA)out +( A vdA) wall (overall ) terms (2 & 3) A A A Term 4: Species A goes into the control volume from the surrounding other than terms (2) and (3): jA ndA (int egral ) ; J A (overall ) term (4) A Term 5: The mass production rate of species A in Ω: rAd (int egral ) ; R A (overall ) term (5) 20 Substituting the integral form of terms (1) through (5) into Eq. [3.2.3], we have A d A v ndA jA ndA rA d A A t [3.2-4] Note that the mass convection and diffusion terms can be combined into one through nA =Av+jA A similar equation can be derived on the basis of the molar density cA, the molar flux j A , the local molar average velocity v, and the molar production rate of A per unit volume rA . This equation is cA d cA v ndA jA ndA rA d A A A t [3.2-5] Note that the molar convection and diffusion terms can be combined into one through n A c A v jA 21 Now substituting the overall form of terms (1) through (5) into Eq.[3.2-3] and with A =wA. dM A wAvdA wAvdA A A in dt (mA )in (mA )out J A RA out J A RA Where MAΩ is the mass of species A in the control volume; that is [3.2-6] wAd When the convective mass transfer at the wall has been neglected, substituting Eq. [3.1-23] into Eq.[3.2-6], we obtain dM A wA,av vav Ain wA,av vav Aout J A RA dt (mwA,av )in (mwA,av )out J A RA Where [3.2-7] MAΩ: mass of species A in control volume((=wAΩ=MwA if uniform wA) M: mass flow rate at inlet or outlet (=vAVA) RA:mass generation rate of species A in control volume (= rA ) JA: mass transfer rate of species A into control volume from 22 surroundings by diffusion Equations similar to [3.2-6] and [3.2-7] can be derived on the molar basis, i.e., dM A cxA vdA cxA vdA A A in dt (mA )in (mA )out J A RA out J A RA [3.2-8] and dM A cxA,av vav Ain cxA,av vav Aout J A RA dt (mxA,av )in (mxA,av )out J A RA Where [3.2-9] MAΩ: mass of species A in control volume(=cxAΩ=MxA if uniform cxA) m: mass flow rate at inlet or outlet (=cvavA) RA:mass generation rate of species A in control volume(= rA ) JA: mass transfer rate of species A into control volume from surroundings by diffusion 23 3.3 Species differential mass-balance equation 3.3.1 Derivation The species integral mass-balance equation can be written as follows A t d A A v ndA A jA ndA rAd [3.3-1] The surface integrals in Eq. [3.3-1] can be converted into volume integrals using the Gauss divergence theorem A A v ndA A vd [3.3-2] j v ndA jAd [3.3-3] A A Substituting Eq. [3.3-2] and [3.3-3] into Eq. [3.3-1] A v j r A A A d 0 t [3.3-4] The integrand, which is continuous, must be zero since the equation must hold for any arbitrary region Ω. Therefore, 24 A A v jA rA n A rA (variable properties) t Noting that n A A v +jA from Eq. [3.1-11] [3.3-5] By following a similar approach, an equation can be derived based on the basis of molar density cA (moles A per unit volume), the molar diffusion flux j A , the local molar average velocity v , and the molar production rate of A per unit volume rA . This equation is cA cA v jA rA n A rA (variable properties) t [3.3-6] Noting that n A c A v + jA from Eq. [3.1-14] Fick’s law of diffusion, according to Eqs. [3.1-5] and [3.1-7], is jA DAwA [3.3-7] jA cDAxA [3.3-8] 25 Substituting Eqs. [3.3-7] and [3.3-8] into Eqs. [3.3-5] and [3.3-6], respectively, the following equations can be obtained; A A v DAwA rA t cA cA v cDAx A rA t [3.3-9] [3.3-10] Let us now consider the case of incompressible fluids. From the continuity Equation v = 0 and so ( A v) = v A +A v =v A. Since for constant and DA, Eq. [3.3-9] reduces to A v A DA 2 A rA (constant and D A ) t c A v c A DA 2 c A rA (constant and D A ) t [3.3-11] [3.3-12] Eqs. [3.3-11] or [3.3-12] is the species differential mass-balance equation or the species continuity equation. 26 3.3.2 Dimensionless form Besides the dimensionless parameters listed in Sections 1.5.2 and 2.3.2, we Includes a new parameter for concentration: cA c A c A0 c A1 c A0 (dimensionless concentration) [3.3.14] Where (cA1 –cA0) is characteristic concentration difference. If no chemical reaction occurred, Eq. [3.3.12] reduces to c A v c A DA 2 c A t [3.3.20] Substituting Eq. [3.3-13] through [3.3-19] (please see the book for details) into Eq. [3.3-20] V 1 2 1 c c c V v c c c D A1 A0 A 2 cA cA1 cA0 [3.3.21] A0 A A A1 L t L L 27 Multiplying Eq. [3.3-21] by L/[V (cA1 –cA0)] cA DA 2 v cA cA t LV [3.3.22] By combining Eq.[3.3-22] with Eqs. [2.3-18] through [2.3-24], the following equations can be obtained for mass transfer in forced convection: Continuity: Momentum: v 0 v 1 2 1 v v p v eg t Re Fr Energy: T 1 1 2 2 v T T T t Re Pr P eT Species: cA 1 1 2 2 v c c cA A A t Re Sc P eS [3.3.23] [3.3.24] [3.3.25] [3.3.26] 28 where Re, Fr, and Pr are defined in the previous chapter, the new dimensionless parameters defined in this chapter are listed in the following: viscous diffusivity [3.3.30] Sc (Schmidt number = species diffusivity D ) DA A By combining Eq.[3.3-22] with Eqs. [2.3-18] through [2.3-24], the following equations can be obtained for mass transfer in forced convection: PeT Re Pr LV (thermal Peclet number = LV PeS Re Sc DA (solutal Peclet number = convection heat transport C v V T1 T0 ) conduction heat transport k T1 T0 / L convection species transport V c A1 c A0 diffusion species transport D A c A1 c A0 / L [3.3.31] [3.3.32] ) 3.3.3 Boundary conditions Boundary conditions commonly encountered in mass transfer are summarized and listed: 1. At the plane or axis of symmetry, the concentration gradient in the transverse direction is zero, (case 1) 29 2. A wall in contact with a fluid or the surface of a solid or fluid may be kept at a given solute concentration, (case 2) 3. A wall in contact with a fluid or the surface of a solid or liquid may allow no penetration, evaporation, or reactions, (case 3) 4. The free surface of a fluid may be exposed to a gas of solute concentration wAf. A boundary conditions consistent with Eq. [3.1-21] is as follows: (case 4) wA DA km wA wAf y jAy [3.3-33] 5. For two phase in perfect contact with each other, the concentration and the diffusion flux are both continuous across the interface, that is, they are the same on both sides of the interface, (case 5) 30 31 3.3.4 Solution procedure The purpose of the species equation is to determine the concentration distribution, the step-by step procedure for solving the species continuity equation are listed in Fig. 3.3-3 32 Example 3.3-1 Given: Initial A* (in moles):M (at t=0) Find: CA*(x,t) and diffusion flux jA*x Assume:Overall molar concentration c and the self-diffusion coefficient DA*x are constant Ananlysis: Stationary:vx=vy=vz, one-dimensional problem (varies in x-dir only) Sol: 33 Example 3.3-2 Given: Two interstitial alloys with concentration of CA1 and CA2 at t=0 Find: Concentration profile CA(x,t) Assume: Overall molar density c and intrinsic diffusion coefficient DAare constant Ananlysis: Symmetric concentration with respect to the interface concentration CAS, due to constant c and DA, CAS = (CA1+CA2)/2 =constant Sol: 34 Example 3.3-3 Given: Initial composition of CA1 and CA2 in solids 1 and 2, respectively. The concentration profile after annealing is shown Find: Intrinsic diffusion coefficient DA Analysis: Overall molar concentration c is constant and no bulk motion and chemical reaction Sol: 35 Example 3.3-6 Problem: A chemical species A diffuses from a gas phase into a porous catalyst sphere of radius R in which it is converted into species B. Given: Concentration of A at the surface of the sphere is CAS, A is consumed according to rA = -k1aCA, constant DA Find: Steady-state concentration distribution of A in the sphere Sol: 36