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Chemistry, The Central Science, 11th edition
Theodore L. Brown; H. Eugene LeMay, Jr.;
and Bruce E. Bursten
Chapter 5
Thermochemistry
John D. Bookstaver
St. Charles Community College
Cottleville, MO
Thermochemistry
© 2009,
Prentice-Hall, Inc.
Energy
• Energy is the ability to do work or
transfer heat.
– Energy used to cause an object that has
mass to move is called work.
– Energy used to cause the temperature of
an object to rise is called heat.
Thermochemistry
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Potential Energy
Potential energy is energy an object
possesses by virtue of its position or chemical
composition.
Thermochemistry
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Kinetic Energy
Kinetic energy is energy an object possesses
by virtue of its motion.
1
KE =  mv2
2
Thermochemistry
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Units of Energy
• The SI unit of energy is the joule (J).
kg m2
1 J = 1 
s2
• An older, non-SI unit is still in
widespread use: the calorie (cal).
1 cal = 4.184 J
Thermochemistry
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Definitions:
System and Surroundings
• The system includes the
molecules we want to
study (here, the hydrogen
and oxygen molecules).
• The surroundings are
everything else (here, the
cylinder and piston).
Thermochemistry
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Definitions: Work
• Energy used to
move an object over
some distance is
work.
• w=Fd
where w is work, F
is the force, and d is
the distance over
which the force is
exerted.
Thermochemistry
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Heat
• Energy can also be
transferred as heat.
• Heat flows from
warmer objects to
cooler objects.
Thermochemistry
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Conversion of Energy
• Energy can be converted from one type to
another.
• For example, the cyclist above has potential
energy as she sits on top of the hill.
Thermochemistry
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Conversion of Energy
• As she coasts down the hill, her potential
energy is converted to kinetic energy.
• At the bottom, all the potential energy she had
at the top of the hill is now kinetic energy.
Thermochemistry
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First Law of Thermodynamics
• Energy is neither created nor destroyed.
• In other words, the total energy of the universe is
a constant; if the system loses energy, it must be
gained by the surroundings, and vice versa.
Thermochemistry
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Internal Energy
The internal energy of a system is the sum of all
kinetic and potential energies of all components
of the system; we call it E.
Thermochemistry
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Internal Energy
By definition, the change in internal energy, E,
is the final energy of the system minus the initial
energy of the system:
E = Efinal − Einitial
Thermochemistry
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Changes in Internal Energy
• If E > 0, Efinal > Einitial
– Therefore, the system
absorbed energy from
the surroundings.
– This energy change is
called endergonic.
Thermochemistry
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Changes in Internal Energy
• If E < 0, Efinal < Einitial
– Therefore, the system
released energy to the
surroundings.
– This energy change is
called exergonic.
Thermochemistry
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Changes in Internal Energy
• When energy is
exchanged between
the system and the
surroundings, it is
exchanged as either
heat (q) or work (w).
• That is, E = q + w.
Thermochemistry
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E, q, w, and Their Signs
Thermochemistry
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Exchange of Heat between
System and Surroundings
• When heat is absorbed by the system from
the surroundings, the process is endothermic.
Thermochemistry
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Exchange of Heat between
System and Surroundings
• When heat is absorbed by the system from
the surroundings, the process is endothermic.
• When heat is released by the system into the
surroundings, the process is exothermic.
Thermochemistry
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State Functions
Usually we have no way of knowing the
internal energy of a system; finding that value
is simply too complex a problem.
Thermochemistry
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State Functions
• However, we do know that the internal energy
of a system is independent of the path by
which the system achieved that state.
– In the system below, the water could have reached
room temperature from either direction.
Thermochemistry
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State Functions
• Therefore, internal energy is a state function.
• It depends only on the present state of the
system, not on the path by which the system
arrived at that state.
• And so, E depends only on Einitial and Efinal.
Thermochemistry
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State Functions
• However, q and w are
not state functions.
• Whether the battery is
shorted out or is
discharged by running
the fan, its E is the
same.
– But q and w are different
in the two cases.
Thermochemistry
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Work
Usually in an open
container the only work
done is by a gas
pushing on the
surroundings (or by
the surroundings
pushing on the gas).
Thermochemistry
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Work
We can measure the work done by the gas if
the reaction is done in a vessel that has been
fitted with a piston.
w = -PV
Thermochemistry
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Enthalpy
• If a process takes place at constant
pressure (as the majority of processes we
study do) and the only work done is this
pressure-volume work, we can account for
heat flow during the process by measuring
the enthalpy of the system.
• Enthalpy is the internal energy plus the
product of pressure and volume:
H = E + PV
Thermochemistry
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Enthalpy
• When the system changes at constant
pressure, the change in enthalpy, H, is
H = (E + PV)
• This can be written
H = E + PV
Thermochemistry
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Enthalpy
• Since E = q + w and w = -PV, we can
substitute these into the enthalpy
expression:
H = E + PV
H = (q+w) − w
H = q
• So, at constant pressure, the change in
enthalpy is the heat gained or lost.
Thermochemistry
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Endothermicity and
Exothermicity
• A process is
endothermic when
H is positive.
Thermochemistry
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Endothermicity and
Exothermicity
• A process is
endothermic when
H is positive.
• A process is
exothermic when
H is negative.
Thermochemistry
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Enthalpy of Reaction
The change in
enthalpy, H, is the
enthalpy of the
products minus the
enthalpy of the
reactants:
H = Hproducts − Hreactants
Thermochemistry
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Enthalpy of Reaction
This quantity, H, is called the enthalpy of
reaction, or the heat of reaction.
Thermochemistry
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The Truth about Enthalpy
1. Enthalpy is an extensive property.
2. H for a reaction in the forward
direction is equal in size, but opposite
in sign, to H for the reverse reaction.
3. H for a reaction depends on the state
of the products and the state of the
reactants.
Thermochemistry
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A moving racquetball has
__________ energy.
100%
0%
0%
0%
1.
2.
3.
4.
kinetic
potential
work
heat
Thermochemistry
A motionless racquetball has
__________ energy.
0%
100%
0%
0%
1.
2.
3.
4.
kinetic
potential
work
heat
Thermochemistry
A racquetball player perspires
during the game, giving off
__________ energy.
6%
0%
13%
81%
1.
2.
3.
4.
kinetic
potential
work
heat
Thermochemistry
The sum of all the kinetic and
potential energies of a system’s
components is known as its:
0%
0%
100%
0%
1.
2.
3.
4.
integral energy.
dynamic energy.
internal energy.
work energy.
Thermochemistry
A system absorbs heat during an
__________ process.
0%
0%
0%
100%
1.
2.
3.
4.
exothermic
isothermic
adiabatic
endothermic
Thermochemistry
Which of the following is NOT a
state function?
10%
50%
0%
40%
1.
2.
3.
4.
internal energy
temperature
enthalpy
work
Thermochemistry
Calculation of Enthalpy
Thermochemistry
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Stoichiometry
• Ex. Upon adding solid potassium
hydroxide pellets to water, the following
reaction takes place
KOH  K+ + OH• For the reaction at constant pressure,
∆H=-43kJ/mol. When 14.0 g of KOH is
added to water,
– Is the reaction endothermic or exothermic?
– Does the beaker get warmer or colder?
Thermochemistry
– What is the enthalpy change for the
dissolution?
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©
For the reaction at constant pressure, ∆H=43kJ/mol. When 14.0 g of KOH is added to
water, what is the enthalpy change for the
dissolution?
Thermochemistry
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Calorimetry
Since we cannot
know the exact
enthalpy of the
reactants and
products, we
measure H through
calorimetry, the
measurement of
heat flow.
Thermochemistry
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Prentice-Hall, Inc.
Heat Capacity and Specific Heat
The amount of energy required to raise the
temperature of a substance by 1 K (1C) is its
heat capacity.
Thermochemistry
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Heat Capacity and Specific Heat
We define specific heat capacity (or simply
specific heat) as the amount of energy
required to raise the temperature of 1 g of a
substance by 1 K.
Thermochemistry
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Heat Capacity and Specific Heat
Specific heat, then, is
Specific heat =
s=
heat transferred
mass  temperature change
q
m  T
Thermochemistry
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Constant Pressure Calorimetry
By carrying out a
reaction in aqueous
solution in a simple
calorimeter such as this
one, one can indirectly
measure the heat
change for the system
by measuring the heat
change for the water in
the calorimeter.
Thermochemistry
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Constant Pressure Calorimetry
Because the specific
heat for water is well
known (4.184 J/g-K), we
can measure H for the
reaction with this
equation:
q = m  s  T
Thermochemistry
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When a hot piece of metal is
placed into cool water, energy:
100%
0%
0%
0%
1.
2.
3.
4.
flows from the metal to the water.
flows from the water to the metal.
does not flow.
is not conserved.
Thermochemistry
Which metal will undergo the
greatest temperature change if
an equal amount of heat is
added to each?
0%
25%
0%
75%
0%
1.
2.
3.
4.
5.
Fe, s = 0.45 J/g K
Al, s = 0.90 J/g K
Cu, s = 0.38 J/g K
Pb, s = 0.13 J/g K
Sn, s = 0.22 J/g K
Thermochemistry
%
%
%
%
%
If a piece of metal at 85°C is added to water at
25°C, the final temperature of the system is 30°C.
Which of the following is true?
1. Heat lost by the metal > heat gained by
water.
2. Heat gained by water > heat lost by the
metal.
3. Heat lost by metal > heat lost by the
water.
4. Heat lost by the metal = heat gained by
water.
Thermochemistry
5. More information is required.
Example problem – physical
exchange
• 2540 J is absorbed by 278 g of water at 21.4
oC. What is the final temperature of the
system?
Thermochemistry
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Another example – physical exchange
• A piece of an unknown metal with mass 23.8 g
is heated to 100.0 oC and dropped into 50.0 cm3
of water at 24.0 oC. The final temperature of
the system is 32.5 oC. What is the specific heat
of the metal? The specific heat of water is 4.18
J/goC.
Thermochemistry
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Physical heat exchanges
• The color of many ceramic glazes comes
from cadmium compounds. If a piece of
cadmium with mass 65.6 g and a temperature
of 100.0 oC is dropped into 25.0 cm3 of water
at 23.0 oC, what will be the final temperature
of the system? Remember both the metal
and water will end up at the same final temp.
Thermochemistry
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Chemical Reactions and
calorimetry – Sample problem
Suppose you place 0.5 g of magnesium chips in
a coffee-cup calorimeter and then add 100 mL
of 1 M HCl. The temperature of the solution
increases from 22.2C to 44.8C. What is the
enthalpy change for this reaction per mole of
Mg? (assume the heat capacity of the solution
is 4.2 J/gK and the density of the HCl solution is
1 g/mL)
Thermochemistry
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Bomb Calorimetry
• Reactions can be
carried out in a sealed
“bomb” such as this
one.
• The heat absorbed
(or released) by the
water is a very good
approximation of the
enthalpy change for
the reaction.
Thermochemistry
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Bomb Calorimetry
• Because the volume
in the bomb
calorimeter is
constant, what is
measured is really the
change in internal
energy, E, not H.
• For most reactions,
the difference is very
small.
Thermochemistry
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Thermochemistry
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Enthalpies of formation
Thermochemistry
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Enthalpies of Formation
An enthalpy of formation, Hf, is defined
as the enthalpy change for the reaction
in which a compound is made from its
constituent elements in their elemental
forms.
Thermochemistry
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Standard Enthalpies of Formation
Standard enthalpies of formation, Hf°, are
measured under standard conditions (25 °C
and 1.00 atm pressure).
Thermochemistry
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Calculation of H
C3H8 (g) + 5 O2 (g)  3 CO2 (g) + 4 H2O (l)
• Imagine this as occurring
in three steps:
C3H8 (g)  3 C (graphite) + 4 H2 (g)
3 C (graphite) + 3 O2 (g)  3 CO2 (g)
4 H2 (g) + 2 O2 (g)  4 H2O (l)
Thermochemistry
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Calculation of H
C3H8 (g) + 5 O2 (g)  3 CO2 (g) + 4 H2O (l)
• Imagine this as occurring
in three steps:
C3H8 (g)  3 C (graphite) + 4 H2 (g)
3 C (graphite) + 3 O2 (g)  3 CO2 (g)
4 H2 (g) + 2 O2 (g)  4 H2O (l)
Thermochemistry
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Calculation of H
C3H8 (g) + 5 O2 (g)  3 CO2 (g) + 4 H2O (l)
• Imagine this as occurring
in three steps:
C3H8 (g)  3 C (graphite) + 4 H2 (g)
3 C (graphite) + 3 O2 (g)  3 CO2 (g)
4 H2 (g) + 2 O2 (g)  4 H2O (l)
Thermochemistry
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Calculation of H
C3H8 (g) + 5 O2 (g)  3 CO2 (g) + 4 H2O (l)
• The sum of these
equations is:
C3H8 (g)  3 C (graphite) + 4 H2 (g)
3 C (graphite) + 3 O2 (g)  3 CO2 (g)
4 H2 (g) + 2 O2 (g)  4 H2O (l)
C3H8 (g) + 5 O2 (g)  3 CO2 (g) + 4 H2O (l)
Thermochemistry
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Calculation of H
We can use Hess’s law in this way:
H =  nHf°products –  mHf° reactants
where n and m are the stoichiometric
coefficients.
Thermochemistry
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Calculation of H
C3H8 (g) + 5 O2 (g)  3 CO2 (g) + 4 H2O (l)
H = [3(-393.5 kJ) + 4(-285.8 kJ)] – [1(-103.85 kJ) + 5(0 kJ)]
= [(-1180.5 kJ) + (-1143.2 kJ)] – [(-103.85 kJ) + (0 kJ)]
= (-2323.7 kJ) – (-103.85 kJ) = -2219.9 kJ
Thermochemistry
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Hess’s Law
 H is well known for many reactions,
and it is inconvenient to measure H
for every reaction in which we are
interested.
• However, we can estimate H using
published H values and the
properties of enthalpy.
Thermochemistry
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Hess’s Law
Hess’s law states that
“[i]f a reaction is
carried out in a series
of steps, H for the
overall reaction will be
equal to the sum of
the enthalpy changes
for the individual
steps.”
Thermochemistry
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Hess’s Law
Because H is a state
function, the total
enthalpy change
depends only on the
initial state of the
reactants and the final
state of the products.
Thermochemistry
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Energy in Foods
Most of the fuel in the
food we eat comes
from carbohydrates
and fats.
Thermochemistry
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Energy in Fuels
The vast
majority of the
energy
consumed in
this country
comes from
fossil fuels.
Thermochemistry
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